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Vadim26 [7]
2 years ago
9

1.What is the name of the compound CuCO3?. a. Copper (I) Carbonate. b. Copper (II) Carbonate. c. Copper Carbon Oxide . d. Copper

Carbon Oxide. . 2. Did Ca2+ react with Na2S?. a. Yes . b. No . . 3.What is the product of NaCl and Ag?. a. NaCl and Ag+ do not form a product. b. AgNa. c. AgCl . . 4.Describe what happened when you combine Ag+ and Na2S. What does this indicate?
Chemistry
2 answers:
likoan [24]2 years ago
4 0

1- The answer is:

the compound CuCO3 is named (b)Copper(II) carbonate.

The explanation:

-when Cu is the chemical symbol for the copper and CO3 is the chemical symbol for the carbonate group and each one of them has (2) Valence number , 2:2 = 1:1 so it will be CuCO3.

2)The answer is:

yes, Ca2+ will react with Na2S

The explanation:

and this is the reaction equation: Ca2+ + Na2S → 2Na+ + CaS

Ca2+ ions will replace Na+ ions in Na2S and gives CaS and Na+ ions.

3) The answer is:

NaCl and Ag+ do not form a product

The Explanation:

The reaction between NaCl and Ag+ metal will not take place. That is because silver (Ag) is less reactive than sodium metal so, It can't displace sodium from its salt. that means silver metal is lower in the reactivity series as compared to sodium metal which indicates sodium metal is more reactive than silver. So that there is no product will be formed .

4)The answer is:

when we combine Ag+ and Na2S this will Form a white precipitate of Ag2S, this indicates that Ag2S is insoluble in water the and the reaction equation will be:

2 Ag+ (aq) + Na2S(aq) ----- Ag2S (s) + 2 Na+ (aq)

The explanation:

so, we have here Ag2S as a precipitate and Na+ ions dissolved in water, this means a combination in the aqueous solution and Ag+ replace Na+ ions in Na2S.

Studentka2010 [4]2 years ago
3 0

1. Answer;

Copper (ii) carbonate.

The name of the compound CuCO3 is copper (ii) carbonate.

Explanation;

Cu is the chemical symbol for the copper and CO3 is the chemical symbol for the carbonate group and each one of them has valency of two. Therefore, a compound CuCO3 is formed.

2. Answer;

Yes

Ca2+ reacted with Na2S to form CaS and Na+

Explanation:

Calcium ions reacts with sodium sulfide to form calcium sulfide and sodium ions.

For example; a salt of calcium, calcium carbonate reacts with sodium sulfide to form sodium carbonate and calcium sulfide.

3. Answer;

NaCl and Ag+ do not form a product

Explanation;

The reaction between sodium chloride and silver metal will not take place. This is because silver (Ag) is less reactive than sodium metal and therefore cannot displace sodium from its salt. In other words, silver metal is lower in the reactivity series as compared to sodium metal which indicates sodium metal is more reactive than silver.

4. Answer;

Formation of a white precipitate ; this indicates that silver sulfide is insoluble in water.

Explanation;

When an aqueous solution containing Ag+ ions is added to aqueous solution of sodium sulfide (Na2S), there will be formation of white precipitate. Formation of white precipitate indicates that a reaction has taken place to form a water insoluble compound. The water insoluble compound occurs as a precipitate. The white precipitate is silver sulfide (Ag2S)

2 Ag+ (aq) + Na2S(aq) ----- Ag2S (s) + 2 Na+ (aq)

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rodikova [14]

Answer:

\boxed {\boxed {\sf D. \ 64 \ grams }}

Explanation:

Given the moles, we are asked to find the mass of a sample.

We know that the molar mass of methanol is 32.0 grams per mole. We can use this number as a fraction or ratio.

\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}

Multiply by the given number of moles, which is 2.0

2.0 \ mol \ CH_3OH *\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}

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2.0 \ *\frac{32 \ g \ CH_3OH}{1 }

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2.0 * 32 \ g\ CH_3OH

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64 \ g \ CH_3OH

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1 year ago
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Answer:

A titration

Explanation:

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5 0
1 year ago
A sample of bismuth weighing 0.687 g was converted to bismuth chloride by reacting it first with HNO3, and then with HCI, follow
alisha [4.7K]

Answer:

The empirical formula is BiCl3

% Bi = 66.27 %

Explanation:

Step 1: Data given

Mass of bismuth = 0.687 grams

Mass of bismuth chloride produced = 1.032 grams

Molar mass of bismuth = 208.98 g/mol

Molar mass of bismuth chloride = 315.33 g/mol

Step 2: The balanced equation

Step 3: Calculate moles of Bi

Moles Bi = mass Bi / molar mass Bi

Moles Bi = 0.687 grams / 208.98 g/mol

Moles Bi =  0.00329 moles

Step 4: Calculate moles of Cl

Mass of Cl = 1.032 - 0.687  = 0.345 moles

Moles Cl = 0.345 moles / 35.45 g/mol

Moles Cl = 0.00973 moles Cl

Step 5: Calculate mol ratio

We divide by the smaller number of moles:

Bi: 0.00329 / 0.00329 = 1

Cl: 0.0097The empirical formula is BiCl33/0.00329 = 3

Step 6: Calculate molar mass of BiCl3

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Step 7: Calculate percent of Bi

% Bi = (208.98 / 315.33) * 100%

% Bi = 66.27 %

3 0
1 year ago
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