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2 years ago

5

1.50 × 104 J of energy is transferred thermally into a huge tank filled with liquid water. The water temperature remains constan

t at 10.0 ∘C during the process.Part ABy how much does the entropy of the water change?

1 answer:

posledela2 years ago

3 0

Answer:

53j/k

Explanation:

ΔH = TΔS => ΔS = ΔH/T = 1.5 x 10⁴ joules/283 Kelvin = 53 joules/K

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Witch of the following isotopes would most likely be unstable and therefore radioactive?

STALIN [3.7K]

The answer is D; Mercury-194
All of the others are not when I looked them up

5 0

2 years ago

In a fixed cylinder are 3moles of oxygen gas at 300Kelvin and 1.25atm. What is the volume of the container?

vladimir2022 [97]

Answer:

The volume of the container is 59.112 L

Explanation:

Given that,

Number of moles of Oxygen, n = 3

Temperature of the gas, T = 300 K

Pressure of the gas, P = 1.25 atm

We need to find the volume of the container. For a gas, we know that,

PV = nRT

V is volume

R is gas constant, R = 0.0821 atm-L/mol-K

So,

$V=\dfrac{nRT}{P}\\\\V=\dfrac{3\ mol\times 0.0821\ L-atm/mol-K \times 300\ K}{1.25\ atm}\\\\V=59.112\ L$

So, the volume of the container is 59.112 L

6 0

2 years ago

A. The measured pH of a 0.100 M HCl solution at 25 degrees Celsius is 1.092. From this information, calculate the activity coeff

ra1l [238]

Answer:

activity coefficient $\mathbf{\gamma =0.809}$

activity coefficient $\mathbf{\gamma = 0.791}$

The change in pH in part A = 0.092

The change in pH in part B = 0.102

Explanation:

From the given information:

pH of HCl solution = 1.092

Activity of the pH solution [a] = $10^{-1.092}$

[a] = 0.0809 M

Recall that [a] = $\gamma$ × C

where;

$\gamma$ = activity coefficient

C = concentration

Making the activity coefficient the subject of the formula, we have:

$\gamma = \dfrac{[a]}{C}$

$\gamma = \dfrac{0.0809 \ M}{0.100 \ M}$

$\mathbf{\gamma =0.809}$

B.

The pH of a solution of HCl and KCl = 2.102

[a] = $10^{-2.102}$

[a] = 0.00791 M

activity coefficient $\gamma = \dfrac{0.00791 \ M}{0.01 \ M}$

$\mathbf{\gamma = 0.791}$

C. The change in pH in part A = 1.091 - 1.0 = 0.092

The change in pH in part B = 2.102 -2.00 = 0.102

3 0

2 years ago

The average distance between nitrogen and oxygen atoms is 115 pm in a compound called nitric oxide. what is this distance in cen

e-lub [12.9K]

<span>pm stands for picometer and picometers are units which can be used to measure really tiny distances. One picometer is equal to 10^{-12} meters. We know that one centimeter is equal to 10^{-2} m so there are 10^2 cm per meter. We can change the distance d = 115 pm to units of centimeters. d = (115 pm) x (10^{-12}m / pm) x (10^2 cm / m) d = 115 x 10^{-10} cm = 1.15 x 10^{-8} cm The distance in centimeters is 1.15 x 10^{-8} cm</span>

7 0

2 years ago

Electroplating is a way to coat a complex metal object with a very thin (and hence inexpensive) layer of a precious metal, such

8_murik_8 [283]

Answer:

0.0164 g

Explanation:

Let's consider the reduction of silver (I) to silver that occurs in the cathode during the electroplating.

Ag⁺(aq) + 1 e⁻ → Ag(s)

We can establish the following relations.

1 A = 1 C/s
The charge of 1 mole of electrons is 96,468 C (Faraday's constant)
1 mole of Ag(s) is deposited when 1 mole of electrons circulate.
The molar mass of silver is 107.87 g/mol

The mass of silver deposited when a current of 0.770 A circulates during 19.0 seconds is:

$19.0s \times \frac{0.770c}{s} \times \frac{1mole^{-} }{96,468C} \times \frac{1molAg}{1mole^{-}} \times \frac{107.87g}{1molAg} = 0.0164 g$

5 0

2 years ago