Answer:
It can bond through either the N or O atoms
Explanation:
An ambident ("both teeth") group is a group that can attach to another by either of two atoms.
A nitro group can bond through either N or O.
Organic chemistry
In organic chemistry, this property gives rise to functional group isomers.
For example, we can have either nitromethane (CH₃NO₂, Fig. 1) or methyl nitrite (CH₃ONO, Fig. 2)
Inorganic chemistry
The ambidentate property of the nitro group gives rise to linkage isomers in inorganic coordination complexes.
For example, we can have either a pentachloronitroiron(III) cation (Fig. 3) or a pentachloronitritoiron(III) cation (Fig. 4)
Answer : The cell emf for this cell is 0.118 V
Solution :
The half-cell reaction is:
In this case, the cathode and anode both are same. So, is equal to zero.
Now we have to calculate the cell emf.
Using Nernest equation :
where,
n = number of electrons in oxidation-reduction reaction = 1
= ?
= 0.0222 M
= 2.22 M
Now put all the given values in the above equation, we get:
Therefore, the cell emf for this cell is 0.118 V
<u>Answer:</u> The element represented by M is Strontium.
<u>Explanation:</u>
Let us consider the molar mass of metal be 'x'.
The molar mass of MO will be = Molar mass of oxygen + Molar mass of metal = (16 + x)g/mol
It is given in the question that 15.44% of oxygen is present in metal oxide. So, the equation becomes:
The metal atom having molar mass as 87.62/mol is Strontium.
Hence, the element represented by M is Strontium.
