Answer:
194 g/mol.
Explanation:
Hello,
In this case, one first must compute the mass of each element as shown below:
Next, the corresponding moles:
Then, each element's subscripts is found to be:
Therefore, the empirical formula is:
Nonetheless, it has a molar mass of 97bg/mol, thereby, by multiplying such formula by 2 one gets:
Which has a molar mass of 194 g/mol being correctly contained in the given interval.
Best regards.
Answer:
0.192 mol.
Explanation:
- To calculate the no. of moles of a substance (n), we use the relation:
<em>n = mass / molar mass.</em>
mass of AsH₃ = 15.0 g.
molar mass of AsH₃ = 77.95 g/mol.
∴ The number of moles in 15.0 g AsH₃ = mass / molar mass = (15.0 g) / (77.95 g/mol) = 0.192 mol.
Answer: the empirical formula is C3H4O3
Explanation:Please see attachment for explanation
Answer:
R = 6, P = 6
Explanation:
Answer
Number of R molecules = 6
Number of P molecules = 6
Explanation
R(aq) <-------> P(aq)
K = [P]/[R]
at equillibrium
[ P ] = 10+x
[R] = 2-x
10 + x /(2-x) = 1
10 + x = 2- x
2x = -8
x = -4
Therefore,
[ R] = 2 - ( -4) = 6
[ P ] = 10 + ( -4) = 6
Answer:
Passivation of Oxide layers of the metals.
Explanation:
Passivation is a non-electrolytic finishing process that makes most metals rust-resistant. The prosses removes free iron from the surface by using either nitric or citric acid. When this happens, it results to an inert, protective oxide layer that is very slow or less likely to chemically react with air and cause corrosion.
Passivity caused many of the metals several minutes to begin to react. Once the finishing process that makes metals less likely to react was eroded, reaction was initiated vigorously.
