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Blababa [14]
2 years ago
12

During the time 0.325 mol of an ideal gas undergoes an isothermal compression at 22.0∘c, 352 j of work is done on it by the surr

oundings. part a if the final pressure is 1.76 atm, what was the initial pressure?
Chemistry
1 answer:
Yuri [45]2 years ago
5 0
According to the equation of the work done W:
When W = nRT㏑(Pi/Pf) and we have:

W = 352 joule & n = 0.325 & T by kelvin = 22+273 = 295 K & Pf= 1.76

by the substitute: 

352 = (0.325 x 8.314 x 295)㏑(Pi/Pf)
∴㏑(Pi/Pf) = -352 / (0.325 x 8.314 x 295) 
㏑(Pi/Pf) = - 0.44
Pi/Pf = 0.644 
∴ Pi =1.76 x 0.644 = 1.13 atm

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4 0
2 years ago
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A flask of fixed volume contains 1.0 mole of gaseous carbon dioxide and 88 g of solid carbon dioxide. The original pressure and
lianna [129]

Answer:

The correct option is: C. 250 K

Explanation:

Given: <em><u>Before Sublimation-</u></em>

Initial Temperature: T₁ = 300 K, Initial Pressure: P₁ = 1 atm, Initial number of moles of gas: n₁ = 1 mol, given mass of solid Carbon dioxide: w = 88 g    

<u><em>After Sublimation- </em></u>      

Final Pressure: P₂ = 2.5 atm, Final number of moles of gas: n₂ = ? mol

Final Temperature: T₂ = ? K,            

Also, Volume is constant, Molar mass of Carbon dioxide: m = 44 g/mol

As we know,

<em>The number of moles:</em>

n = \frac {given\: mass\: (w)} {Molar\: mass\: (m)}

<em>So the number of moles of carbon dioxide sublimed:</em>

n = \frac {w}{m} = \frac {88\: g} {44\: g/mol} = 2 mol

<em><u>Therefore, the final number of moles of gas after sublimation:</u></em>

n_{2} = n_{1} + n = 1\: mol + 2\: mol = 3\: mol

<u><em>According to the </em></u><u><em>Ideal gas equation</em></u><u><em>:</em></u>

P.V = n.R.T

or, \frac {P_{1}.V_{1}}{n_{1}.T_{1}} = \frac {P_{2}.V_{2}}{n_{2}.T_{2}} \: \: \: \: \: \: ....equation\: (1)

<em>Since the volume is constant, so the equation (1) can be written as:</em>

\frac {P_{1}}{n_{1}.T_{1}} = \frac {P_{2}}{n_{2}.T_{2}}

\Rightarrow \frac {1\:atm}{1\:mol \times 300\:K} = \frac {2.5\:atm}{3\:mol \times T_{2}}

\therefore T_{2} = \frac {2.5\:atm \times 300\:K \times 1\:mol}{3\:mol \times 1\:atm}

\Rightarrow T_{2} = 250\:K

<u>Therefore, the final temperature: T₂ = 250 K</u>

6 0
1 year ago
Enter the chemical equation 2H+(aq)+S2−(aq)→H2S(g). Express your answer as a chemical equation.
amm1812

Answer : The complete chemical equation is,

2H^+(aq)+S^{2-}(aq)\rightarrow H_2S(aq)

Explanation :

As we know that, in a chemical equation the reacting species present on left side and the product formed present on right side and a right arrow inserted between the reactants and product that show a chemical reaction taking place.

In the chemical reaction, the phases of the substances are also included and subscripts and superscripts are also used for the numbers.

For the given chemical reaction, the balanced chemical equation including the phases, is given by:

2H^+(aq)+S^{2-}(aq)\rightarrow H_2S(aq)

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1 year ago
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Thus the millimoles of sodium carbonate the chemist has added to the flask are 256.

6 0
2 years ago
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