Answer: pH=12.69
Explanation:
Initial 0.12 0 0
Eqm 0.12-x x x
(neglecting small value of x in comparison to 0.12)
Moles of
0.06 moles of NaOH will give 0.06 moles of
Now moles of
will be neutralized by
moles of
and
moles of
will be left.
Molarity of
pH = 14 - pOH= 14 - 1.31 = 12.69
Answer : The equilibrium pressure is,
Explanation :
The given balanced chemical reaction is,
First we have to calculate the standard free energy of reaction .
where,
= standard free energy of reaction = ?
n = number of moles
Now put all the given values in this expression, we get:
Now we have to calculate the value of
where,
= standard Gibbs free energy = -90.72 kJ/mol
R = gas constant = 8.314 J/mole.K
T = temperature = 298 K
= equilibrium constant = ?
Now put all the given values in this expression, we get:
Now we have to calculate the value of .
The given balanced chemical reaction is,
The expression for equilibrium constant will be :
In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.
Let the equilibrium pressure be, x
Pressure of = Pressure of
= x
Now put all the given values in this expression, we get
Thus, the equilibrium pressure is,
Answer:
Explanation:
<u>1) Data:</u>
a) Hypochlorous acid = HClO
b) [HClO} = 0.015
c) pH = 4.64
d) pKa = ?
<u>2) Strategy:</u>
With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.
<u>3) Solution:</u>
a) pH
b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)
c) Equilibrium constant: Ka = [ClO⁻] [H₃O⁺] / [HClO]
d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M
e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M
f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46