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const2013 [10]
2 years ago
11

How many atoms of oxygen are in 75.6g of silver nitrate (AgNO3)?​

Chemistry
1 answer:
vodomira [7]2 years ago
8 0

Answer:

1.50x10^21 molecules O2

Explanation:

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If charges flow very slowly through a metal, why does it not require several hours for a light to come on when you throw a switc
Harlamova29_29 [7]
T<span>he charges themselves may not move fast, but the force upon them does. The electric field set up by the battery or generator propagates through the wires at the speed of light.

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6 0
2 years ago
How many atoms of S are in 98.0 grams of hydrosulfuric acid?
noname [10]
<h2>Answer:6.022\times 10^{23}</h2>

Explanation:

The formula for sulphuric acid is H_{2}SO_{4}.

Molecular mass of sulphuric acid is 2(2)+32+16(4)=98g

given weight=98g

Number of moles of sulphuric acid given is \frac{\text{given weight}}{molar mass}=\frac{98}{98}=1

The formula indicates that one mole of H_{2}SO_{4} contains 2 moles of H atoms,1 mole of S atoms,4 moles of O atoms.

So,the compound contains 1 mole of sulphur atoms.

1 mole of sulphur has 6.022\times 10^{23} atoms

7 0
2 years ago
Most Bic lighters hold 5.0ml of liquified butane (density = 0.60 g/ml). Calculate the minimum size container you would need to "
Hatshy [7]

Answer:

Volume of container = 0.0012 m³ or 1.2 L or 1200 ml

Explanation:

Volume of butane = 5.0 ml

density = 0.60 g/ml

Room temperature (T) = 293.15 K

Normal pressure (P) = 1 atm = 101,325 pa

Ideal gas constant (R) = 8.3145 J/mole.K)

volume of container V = ?

Solution

To find out the volume of container we use ideal gas equation

PV = nRT

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

First we find out number of moles

<em>As Mass = density × volume</em>

mass of butane = 0.60 g/ml ×5.0 ml

mass of butane = 3 g

now find out number of moles (n)

n = mass / molar mass

n = 3 g / 58.12 g/mol

n = 0.05 mol

Now put all values in ideal gas equation

<em>PV = nRt</em>

<em>V = nRT/P</em>

V = (0.05 mol × 8.3145 J/mol.K × 293.15 K) ÷ 101,325 pa

V = 121.87 ÷ 101,325 pa

V = 0.0012 m³ OR 1.2 L OR 1200 ml

8 0
2 years ago
How much heat is required to convert 422 g of liquid h2o at 23.5 °c into steam at 150 °c?
Misha Larkins [42]
Heat is given by multiplying the specific heat capacity of a substance by mass and the change in temperature. The heat capacity of water is Approximately 4184 J/K/C.
Therefore, heat = mc0 mass in kg
                         = (422/1000) × 4184 × (100-23.5)
                         = 135072.072 J
Latent heat of vaporization is 2260 kJ/kg
Thus the heat will be 0.422 × 2260000 = 953720 J
Heat to raise steam from 100 to 150 
    2000 × 0.422 ×50 = 42200 J
Thus the heat required is (135072.072 + 953720 + 42200) = 1330992.07 Joules or 1330 kilo joules

4 0
2 years ago
Read 2 more answers
Saccharin, a sugar substitute, is a weak acid with pka=2.32 at 25 ∘c. it ionizes in aqueous solution as follows: hnc7h4so3(aq)←−
MrMuchimi
Saccharin is considered as weak acid:
pH of weak acid = \frac{1}{2} pKa +  \frac{1}{2} pCa
pKa = 2.32 (given) and
pCa = -log (acid concentration) = - log (0.11) = 0.96
so pH = (\frac{1}{2}* 2.32 ) + ( \frac{1}{2} * 0.96) = 1.64
3 0
2 years ago
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