Answer:
Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.
Explanation:
Volume of NaOH = 1.7 ml = 0.0017 L
Molarity of NaOH = 0.0811 M
Moles of NaOH = n
n = 0.0001378 mol
According to reaction, 2 mol of NaOH neutralize 1 mol of sulfuric acid.
Then 0.0001378 mol of NaOH will neutralize:
of sulfuric acid.
Concentration of sulfuric acid in the acid rain sample: x
Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.
Answer:
The correct options are "b" and "c". A further explanation is given below.
Explanation:
- Saturation temperature can be determined where this enough of some other solution that is incorporated like that can be absorbed by a solvent.
- The formulation is saturated at this same stage, so Ksp could be computed. As well as the solid throughout solution should continue to appear upon freezing below a certain temperature.
The other options offered aren't relevant to the situation described. So the equivalents above are the right ones.
Answer:
The pressure will increase due ot expnasion of gasses in a closed sealed tube tube .
Explanation:
Answer:
The empirical formula of the solid metal oxide is : 
Explanation:
M atom is present in the every corner and in the center of every face.
Number of m atoms :
Number of tetrahedral voids in F.C.C = 2n = 2 × 4 = 8
Oxide ion is present in the half of the tetrahedral void
Number oxide ions = 
The molecular formula of the solid metal oxide is : 
The empirical formula represent the lowest number of atoms present in a compound.
The empirical formula of the solid metal oxide is :
Answer:
58.61 grams
Explanation:
Taking The molecular weight of NaCl = 58.44 grams/mole
<u>Determine how many grams of NaCl to prepare the bath solution </u>
first we will calculate the moles of NaCl that is contained in 6L of 170 mM of NaCI solution
= ( 6 * 170 ) / 1000
= 1020 / 1000 = 1.020 moles
next
determine how many grams of NaCl
= moles of NaCl * molar mass of NaCl
= 1.020 * 58.44
= 58.61 grams
