Answer:
Mass= 2.77g
Explanation:
Applying
P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28
PV=nRT
NB
Moles(n) = m/M
PV=m/M×RT
m= PVM/RT
Substitute and Simplify
m= (2.09×1.13×28)/(0.082×291)
m= 2.77g
The elements in this list are mercury, gold, iron, carbon and hydrogen. The compounds in this list, on the other hand, are sucrose, table salt, water and air. Elements are composed only of one substance while compounds are composed of two or more substances.
Answer:
Explanation:
Given the moles, we are asked to find the mass of a sample.
We know that the molar mass of methanol is 32.0 grams per mole. We can use this number as a fraction or ratio.
Multiply by the given number of moles, which is 2.0
The moles of methanol will cancel each other out.
The denominator of 1 can be ignored.
Multiply.
There are 64 grams of methanol in the sample.
Answer:
The concentration after 20 mins is 0.832 M
Explanation:
Zero order rate law is given by;
R = K [A₀]⁰
A zero order reaction, rate is independent of the initial concentration
R = K
Where;
R is the rate of reaction
K is the rate constant = 0.0416 M/min
Since R = K,
Then, R = 0.0416 M/min
After 20 min, the concentration will be;
A = Rt
A = (0.0416 M/min)(20 min)
A = 0.832 M
Therefore, the concentration after 20 mins is 0.832 M
Knowing the number of valence electrons in one of the alien elements helps in identifying it because the number of valence electrons can help categorize the alien element. Similar elements have the same valence electrons and knowing the category of the element can help further analyze the element.
