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Sever21 [200]
2 years ago
6

) A concentration cell is based on the aqueous reaction

Chemistry
1 answer:
Brrunno [24]2 years ago
8 0

Answer:

Kindly check the attachment for the diagram representing the cell and showing all necessary components including: anode, cathode, electron flow, cation flow and anion flow.

Explanation:

So, the reaction in the concentration cell is given below as;

Cu2+(1.00 M) → Cu2+(0.0100 M).--(1).

The anode = Cu2+(0.0100 M) because it has lesser Concentration, thus, lesser potential value.

Cathode = Cu2+(1.00 M) because it has higher Concentration, hence higher potential value.

It must be noted that in the digaram depicting the Reaction, the electrons moves from the anode part of the cell to the cathode part of the cell and this is done through an external circuit. The following are the things that happens at each electrode;

At the Anode: in here is where oxidation occurs and Cu^2+ is released into the solution.

At the cathode: in here is where the reduction occur and the Cu^2+ moves in the direction to where the Cu electrode is, thus, causing the deposition of Cu.

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For each reaction, identify the element that gets reduced and the element that gets oxidized. 2AgCl+Zn⟶2Ag+ZnCl2 Identify the el
PolarNik [594]

Answer:

Explanation:

Oxidation no is equal to charge on each atomic ion. If it is increased , element is oxidised and if it is decreased , element is reduced .

2AgCl+Zn⟶2Ag+ZnCl2

Zinc is oxidised , Ag is reduced .

Ag⁺ converts to Ag . ( oxidation number is reduced ) so Ag is reduced.

Zn converts to Zn⁺² ( oxidation number is increased ) so Zn is oxidised .

4NH₃+3O₂⟶2N₂+6H₂O

oxidation number of nitrogen in ammonia is - 3

oxidation no of nitrogen in nitrogen is zero.

Oxidation no of nitrogen is increased so it is oxidised.

oxidation no of oxygen is zero in oxygen and its oxidation no in water is -2 . So oxidation no is reduced so oxidation  is reduced.

Fe₂O₃+2Al⟶Al₂O₃+2Fe

oxidation no of Fe in Fe₂O₃ is + 3 and it is zero in Fe so iron is reduced.

oxidation no of Al in Al is zero and it is +3 in Al₂O₃ so it is oxidised .

7 0
2 years ago
An atom of beryllium (m = 8.00 u) splits into two atoms of helium (m = 4.00 u) with the release of 92.2 kev of energy. if the or
galben [10]
The kinetic energy of the products is equal to the energy liberated which is 92.2 keV. But let's convert the unit keV to Joules. keV is kiloelectro volt. The conversion that we need is: 1.602×10⁻¹⁹ <span>joule = 1 eV

Kinetic energy = 92.2 keV*(1,000 eV/1 keV)*(</span>1.602×10⁻¹⁹ joule/1 eV) = 5.76×10²³ Joules

From kinetic energy, we can calculate the velocity of each He atom:
KE = 1/2*mv²
5.76×10²³ Joules = 1/2*(4)(v²)
v = 5.367×10¹¹ m/s
4 0
2 years ago
Read 2 more answers
HELP! Ethanol has a density of 0.8 g/cm3. a. What is the mass of 225 cm3 of ethanol? b. What is the volume of 75.0 g of ethanol?
IRINA_888 [86]

Answer:

The correct answers are:

a) 180 g

b) 93.7 cm³

Explanation:

The density of a substance is the mass of the substance per unit of volume. So, it is calculated as follows:

density= mass/volume

From the data provided in the problem:

density = 0.8 g/cm³

a) Given: volume= 225 cm³

mass= density x volume = 0.8 g/cm³ x 225 cm³ = 180 g

b) Given: mass= 75.0 g

volume = mass/density = 75.0 g/(0.8 g/cm³)= 93.75 cm³≅ 93.7 cm³

5 0
1 year ago
The specific heat capacity of a pure substance can be found by dividing the heat needed to change the temperature of a sample of
mrs_skeptik [129]

Answer:

The answers to your questions are given below.

Explanation:

Data obtained from the question include:

Mass (M) = 420.0 g

Temperature change (ΔT) = 43.8 °C

Specific heat capacity (C) = 3.52 J/g °C

Heat needed (Q) =...?

The heat needed for the temperature change can be obtained by using the following formula:

Q = MCΔT

Where:

Q is the heat needed measured in joule (J).

M is the mass of substance measured in grams (g)

C is the specific heat capacity of the substance with unit J/g °C.

ΔT is the temperature change measured in degree celsius (°C).

Thus, we can calculate the heat needed to change the temperature as follow:

Q = MCΔT

Q = 420 x 3.52 x 43.8

Q = 64753.92 J

Therefore, the heat needed to cause the temperature change is 64753.92 J

4 0
1 year ago
In an experiment, the density of an unknown liquid was calculated to be 0.78 g/ml. if the accepted value is 0.75 g/ml, calculate
Vikki [24]
Percentage error is the relative error your measured value is from the true or accepted value. The formula for percentage error is written below:

Percentage error = |True Value - Measured Value|/True Value   * 100
Percentage error = |0.75 g/mL - 0.78 g/mL|/0.75 g/mL  * 100
Percentage error = 4%
6 0
1 year ago
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