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Sever21 [200]
2 years ago
6

) A concentration cell is based on the aqueous reaction

Chemistry
1 answer:
Brrunno [24]2 years ago
8 0

Answer:

Kindly check the attachment for the diagram representing the cell and showing all necessary components including: anode, cathode, electron flow, cation flow and anion flow.

Explanation:

So, the reaction in the concentration cell is given below as;

Cu2+(1.00 M) → Cu2+(0.0100 M).--(1).

The anode = Cu2+(0.0100 M) because it has lesser Concentration, thus, lesser potential value.

Cathode = Cu2+(1.00 M) because it has higher Concentration, hence higher potential value.

It must be noted that in the digaram depicting the Reaction, the electrons moves from the anode part of the cell to the cathode part of the cell and this is done through an external circuit. The following are the things that happens at each electrode;

At the Anode: in here is where oxidation occurs and Cu^2+ is released into the solution.

At the cathode: in here is where the reduction occur and the Cu^2+ moves in the direction to where the Cu electrode is, thus, causing the deposition of Cu.

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Answer:

3.7 mol Al2O3 x 4 mol Al = 7.4 mol Al 2 mol Al2O3

Explanation:

8 0
2 years ago
A lead cylinder has a mass of 540 grams and a density of 2.70 g/ml. What is its volume
ch4aika [34]
Volume = Mass / Density

Volume = 540g / 2.70 g/ml

Volume = 200 ml 
3 0
2 years ago
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How many atoms are in a molecule of RSq?
Wewaii [24]
2 atoms in a molecule of RSq, TSq contains 3 different types of atoms (Sq, R, and T.)
6 0
2 years ago
A molecule contains 23.24 g iodine (I),
gavmur [86]
Convert each amount of grams into moles:

I: 23.24g x 1 mol / 126.90g = 0.1831 mol I

C: 2.198 x 1 mol / 12.01g = 0.1830 mol C

N: 2.562 x 1 mol / 14.01g = 0.1829 mol N

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7 0
1 year ago
What is the density of 2.5 g of gaseous sulfur held at 130. kPa and 10.0 degrees Celsius?
worty [1.4K]
Use ideal gas equation: pV = nRT

Now pass n to mass: n = mass / MM .... [MM is the  molar mass]

pV = [mass/MM]*RT =>mass/V = [p*MM] / RT  and mass / V = density

p= 130 kPa = 130,000 Pa = 130,00 joule / m^3
T = 10.0 ° + 273.15 = 283.15 k
MM of sulfur (S) = 32 g/mol  = 32000 kg/mol

density = 130,000 Pa * 32000kg/mol / [8.31 joule / mol*k * 283.15 k] = 1.77*10^6 kg/m^3 = 1.77 g/L  ≈ 1.8 g/L

Then, I do not get any of the option choices.

Is it possbile that the pressure is 13.0 kPa instead 130. kPa? If so the answer would be 18 g/L

Note that the mass is not used. You do not need it unless you are asked for the volume, which is not the case.



 
4 0
2 years ago
Read 2 more answers
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