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Katena32 [7]
2 years ago
14

Identify the equations that show ionization. Check all that apply.

Chemistry
1 answer:
tigry1 [53]2 years ago
8 0

Answer: B. HCl(g)+H2O(I)—>H3O+(aq)+Cl-(aq)

D. CO2(g)+2H2O(I)—>HCO3-(aq)+H3O+(aq)

Explanation: on edge

You might be interested in
True or false, The atomic number of an element is a whole number that decreases as you read across each row of
torisob [31]

Answer:

I believe it's false because the atomic number is the number of protons in the nucleus of an atom.

5 0
1 year ago
7.744 Liters of nitrogen are contained in a container. Convert this amount to grams.
Xelga [282]

Answer:

9.69g

Explanation:

To obtain the desired result, first let us calculate the number of mole of N2 in 7.744L of the gas.

1mole of a gas occupies 22.4L at stp.

Therefore, Xmol of nitrogen gas(N2) will occupy 7.744L i.e

Xmol of N2 = 7.744/22.4 = 0.346 mole

Now let us convert 0.346 mole of N2 to gram in order to obtain the desired result. This is illustrated below:

Molar Mass of N2 = 2x14 = 28g/mol

Number of mole N2 = 0.346 mole

Mass of N2 =?

Mass = number of mole x molar Mass

Mass of N2 = 0.346 x 28

Mass of N2 = 9.69g

Therefore, 7.744L of N2 contains 9.69g of N2

7 0
2 years ago
how many moles of cesium carbonate will be produced when 5.34 moles of cesium reacts with iron iii carbonate
irga5000 [103]

Answer: 2.7moles

Explanation:

6Cs + Fe2(CO3)3 —> 3Cs2CO3 + 2Fe

From the equation,

6moles of Cs produced 3 moles of Cs2CO3.

Therefore, 5.34 moles of Cs will produce = (5.4x3)/6 = 2.7moles of Cs2CO3

6 0
2 years ago
Type in the maximum number of electrons that can be present in each shell or subshell below.
diamong [38]

<span>n = 5 shell=50</span>

<span>n = 2 shell=8</span>

<span>n = 2, l = 0 subshell=2</span>

<span>n = 2, l = 1 subshell=6</span>

<span><span>3d subshell=</span>10</span>

<span>2s subshell=2</span>

<span><span>5f subshell=14</span></span><span><span> sorry if I'm late I just did this! hope it helps..</span></span>
7 0
1 year ago
Read 2 more answers
What is the [h3o + ] in a 0.050 m solution of ba(oh)2?
elena-14-01-66 [18.8K]
The H3O+ in a 0.050M  solution of Ba(OH)2  is calculated as below

write  the equation for the dissociation of Ba(OH)2

Ba(OH)2  =  Ba^2+  +2OH^-

calculate the OH-  concentration

by use of mole ratio between Ba(OH)2  to OH^- which is 1:2 the concentration of OH  =  0.050 x2  = 0.1 M

by  use of  the  formula ( H3O+)(OH-) =  1 x10 ^-14

by  making H3O+ the subject of the formula
H3O+ = 1 x10^-14/ OH-

substitute  for OH-

H3O+ =  (1 x10^-14 )/0.1

=  1  x10^-3  M
7 0
2 years ago
Read 2 more answers
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