<u>Answer:</u> The mass of 97 % of NaOH solution required is 114.33 g
<u>Explanation:</u>
To calculate mass of a substance, we use the equation:
We are given:
Density of 10 % solution = 1.109 g/mL
Volume of 10% solution = 1 L = 1000 mL (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:
The mass of 10 % solution is 1109 g.
To calculate the mass of concentrated solution, we use the equation:
where,
are the concentration and mass of concentrated solution.
are the concentration and mass of diluted solution.
We are given:
Putting values in above equation, we get:
Hence, the mass of 97 % of NaOH solution required is 114.33 g
Answer:
+5
Explanation:
it hs 5 more protons thant electrons, so it has a positive charge of 5
Q1)
the number of moles can be calculated as follows
number of moles = mass present / molar mass
number of moles is the amount of substance.
4.8 g of Ca was added therefore mass present of Ca is 4.8 g
molar mass of Ca is 40 g/mol
molar mass is the mass of 1 mol of Ca
therefore if we substitute these values in the equation
number of moles of Ca = 4.8 g / 40 g/mol = 0.12 mol
0.12 mol of Ca is present
q2)
next we are asked to calculate the number of moles of water present
again we can use the same equation to find the number of moles of water
number of moles = mass present / molar mass
3.6 g of water is present
sum of the products of the molar masses of the individual elements by the number of atoms
H - 1 g/mol and O - 16 g/mol
molar mass of water = (1 g/mol x 2 ) + 16 g/mol = 18 g/mol
molar mass of H₂O is 18 g/mol
therefore number of moles of water = 3.6 g / 18 g/mol = 0.2 mol
0.2 mol of water is present
Answer: Molarity of 
in the original sample was 1.96M
Explanation:
Molarity is defined as the number of moles of solute dissolved per liter of the solution.
Now put all the given values in the formula of molarity, we get
Thus molarity of in the original sample was 1.96M
