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sp2606 [1]
2 years ago
8

¿Cuántos moles de aluminio (AI) se necesitan para formar 3,7 mol de Al2O3? 4Al(s) + 302 (g) -> 2A1203 (s) ​

Chemistry
1 answer:
tatuchka [14]2 years ago
8 0

Answer:

3.7 mol Al2O3 x 4 mol Al = 7.4 mol Al 2 mol Al2O3

Explanation:

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0.01 M HCl solution has a pH of 2. Suppose that during the experiment, both the universal pH indicator and the cabbage indicator
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Steam initially at 0.3 MPa, 2500 C is cooled at constant volume. (a) At what temperature will steam become saturated vapour? [12
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Answer:

a. 123.9°C

b.

c.

Explanation:

Hello, I'm attaching a picture with the numerical development of this exercise.

a. Since the steam is overheated vapour, the specific volume is gotten from the corresponding table. Then, as it became a saturated vapour, we look for the interval in which the same volume of state 1 is, then we interpolate and get the temperature.

b. Now, at 80°C, since it is about a rigid tank (constant volume for every thermodynamic process), the specific volume of the mixture is 0.79645 m^3/kg as well, so the specific volume for the liquid and the vapour are taken into account to get the quality of 0.234.

c. Now,since this is an isocoric process, the heat transfer per kg of steam is computed as the difference in the internal energy, considering the initial condition (showed in a. part) and the final one computed here.

** The thermodynamic data were obtained from Cengel's thermodynamics book 7th edition.

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7 0
2 years ago
How many grams are in 8.2 x 1022 molecules of N216?
hoa [83]

Answer:

N2I6 = 789 g

N2I6 = 8.2x1022 molecules N2I6 x 1 mole/6.02x1023 molecules = 1.36x10-1 moles = 0.136 moles

N2I6=0.136molesx789g/mole=107g=110g

----------------------

Hope this helps, have a BLESSED AND WONDERFUL DAY!

- Cutiepatutie ☺❀❤

7 0
2 years ago
Write a hypothesis for Section 2 of the lab, which is about the effect of the angle of insolation on the amount of heat a materi
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Answer:

If the angle of insolation is higher, then the temperature of the soil will be higher because it will receive more direct light.

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5 0
2 years ago
A compound of barium and oxygen was dissolved in hydrochloric acid to give a solution of barium ion, which was then precipitated
n200080 [17]

Answer:

The empiricial formula of the compound is BaO2

Explanation:

<u>Step 1:</u> Data given

Barium and oxygen dissolved in hydrochloric acid gives a solution of barium ion. This was precipitated with an excess of potassium chromate and gives barium chromate.

The original compound weighs 1.345g and gives 2.012g of BaCrO4

<u>Step 2: </u>Calculate moles of BaCrO4

moles of BaCrO4 = mass of BaCrO4 / molar mass of BaCrO4

moles of BaCrO4 = 2.012g / 253.37 g/mol = 0.0079 moles

<u>Step 3</u>: Calculate moles of Ba

Mole ratio for Ba and BaCrO4 is 1:1 so this means for 0.0079 moles of BaCrO4, there are 0.0079 moles of Ba-ion

<u>Step 4:</u> Calculate mass of Ba-ion

Mass of Ba = Moles of Ba / Molar mass of Ba

Mass of Ba = 0.0079 moles * 137.327g/mole = 1.085 g Ba

<u>Step 5:</u> Mass of oxygen

Since the original compound has barium and oxygen, the mass of oxygen is the difference between the original mass and the mass of the Ba-ion

1.345 g - (1.085 g Ba) = 0.260 g O

<u>Step 6:</u> Calculate moles of Oxygen

moles oxygen = mass of oxygen / Molar mass of oxygen

moles oxygen = 0.260g / 16g/mole = 0.01625 moles O

We divide the number of moles by the smallest number of moles which is 0.0079

Ba → 0.0079/0.0079 = 1

O → 0.01625 / 0.0079 ≈ 2

(1.091 g Ba) / (137.3277 g Ba/mol) = 0.00794450 mol Ba

(0.254 g O) / (15.99943 g O/mol) = 0.0158756 mol O

This gives us the empirical formula of BaO2 for this compound

7 0
2 years ago
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