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1 year ago

3. A student was given an unknown metal. The student determined that the mass of the metal was 30.2 g. The student placed the

Chemistry

1 answer:

expeople1 [14]1 year ago

6 0

Answer:

15.1 g/mL

Explanation:

The density of a substance is defined as the ratio of the mass of the substance and the volume of the substance. Mathematically, it is expressed as:

Density = mass in grams/volume in mL

In this case, the mass of the metal = 30.2 g

Volume of the metal = volume of water displaced by the metal.

The volume of water displaced by the metal can be calculated as the final volume of water after placing the metal - initial volume of water before placing the metal.

Hence, volume of metal = 22.0 - 20.0 mL = 2.0 mL

Density of metal = 30.2/2.0 = 15.1 g/mL

The density of the metal is 15.1 g/mL

The identity of the metal is not in the table.

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) The only noble gas without eight valence electrons is __________. A) Ar B) Ne C) Kr D) He E) All noble gases have eight valenc

nadya68 [22]

Answer:

D) He

Explanation:

Helium is in the first period. It only has 1 valence electron so it's very reactive. (This could be completely wrong and I'm sorry if it is.)

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2 years ago

A compound that contains only carbon, hydrogen, and oxygen is 48.64% C and 8.16% H by mass. What is the empirical formula of thi

TiliK225 [7]

Answer:

The empirical formula of this substance is:

$C_3H_6O_2$

Explanation:

To find the empirical formula of this substance we need the molecular weight of the elements Carbon, Hydrogen and Oxygen, we can find this information in the periodic table:

- C: 12.01 g/mol

- H: 1.00 g/mol

- O: 15.99 g/mol

With the information in this exercise we can suppose in 100 g of the substance we have:

C: 48.64 g

H: 8.16 g

O: 43.2 g (100 g - 48.64g - 8.16g= 43.2 g)

Now, we need to divide these grams by the molecular weight:

$C=\frac{48.64g}{12.01 g/mol} =4.05 mol\\H=\frac{8.16g}{1.00g/mol}= 8.16 mol\\O=\frac{43.2g}{15.99 g/mol} = 2.70 mol$

We need to divide these results by the minor result, in this case O=2.70 mol

$C=\frac{4.05mol}{2.70mol}= 1.5\\H= \frac{8.16mol}{2.70 mol} = 3.02 \\O=\frac{2.70mol}{2.70mol} = 1$

We need to find integer numbers to find the empirical formula, for this reason we multiply by 2:

$C= 1.5*2=3\\H= 3.02*2= 6.04 \\O= 1*2=2$

This numbers are very close to integer numbers, so we can find the empirical formula as subscripts in the chemical formula:

$C_3H_6O_2$

6 0

1 year ago

Why would it be better to be an r-selected species if the water resources in an area were to become more limited over a short pe

Gnoma [55]

An r-selected species reproduces much faster than K-selected species.

r-selected species focuses on maturing and reproducing quickly. r-selected species will probably reproduce when the water supply is there for the short period of time; thus, increasing the chance of the r-selected species of surviving.

K-selected species, on the other hand, focus on raising their young and reproduce later. Since the K-selected species take long to mature before reproducing, water supply may run out before they have a chance of fully maturing; thus, K-selected species have a lower chance of survival.

Hope this helps.
If you need anything more, feel free to comment! Have an awesome day! :)

~Collinjun0827, Junior Moderator

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1 year ago

Read 2 more answers

in which sample of water do the molecules have the highest average kinetic energy 1)20. mL at 100.°C 2)40. mL at 80. °C 3)60. mL

miv72 [106K]

100°C because all the molecules are moving the fastest past each other

6 0

2 years ago

In attempts to lift ron's spirits, dumbledore asks him a fairly easy question: calculate the mass percent composition of carbon

Salsk061 [2.6K]

Mass percentage composition of carbon in the compound is the composition of carbon in the compound. This can be calculated by finding out the mass of carbon in the compound and the mass of the whole compound .
The compound formula is C2H5Cl
Mass of 1 mol of compound -64.5 g
Mass of carbon - 24 g
Mass percentage = 24/64.5 x100
Therefore mass composition percentage of carbon = 37.2%

4 0

1 year ago