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kolbaska11 [484]
2 years ago
14

3. A student was given an unknown metal. The student determined that the mass of the metal was 30.2 g. The student placed the

Chemistry
1 answer:
expeople1 [14]2 years ago
6 0

Answer:

15.1 g/mL

Explanation:

<em>The density of a substance is defined as the ratio of the mass of the substance and the volume of the substance. Mathematically, it is expressed as:</em>

Density = mass in grams/volume in mL

In this case, the mass of the metal = 30.2 g

Volume of the metal = volume of water displaced by the metal.

<em>The volume of water displaced by the metal can be calculated as the final volume of water after placing the metal - initial volume of water before placing the metal.</em>

Hence, volume of metal = 22.0 - 20.0 mL = 2.0 mL

Density of metal = 30.2/2.0 = 15.1 g/mL

The density of the metal is 15.1 g/mL

<u>The identity of the metal is not in the table.</u>

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What occurs when an optically active alcohol reacts with HBr to give an alkyl halide? Multiple Choice the chirality center retai
denpristay [2]

Answer:

The incomplete and varying inversion of configuration takes place at the chirality center.

Explanation:

When optically active alcohols react with HBr an SN1 reaction occurs.

In SN1 reactions an intermediate carbocation is formed in which the nucleophile can attack it on either side of the molecule. Therefore, there is a partial inversion of the center of chilarity of the molecule.

8 0
2 years ago
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If an equal number of moles of reactants are used, do the following equilibrium mixtures contain primarily reactants or products
puteri [66]

<u>Answer:</u>

<u>For a:</u> The equilibrium mixture contains primarily reactants.

<u>For b:</u> The equilibrium mixture contains primarily products.

<u>Explanation:</u>

There are 3 conditions:

  • When K_{eq}>1; the reaction is product favored.
  • When K_{eq}; the reaction is reactant favored.
  • When K_{e}=1; the reaction is in equilibrium.

For the given chemical reactions:

  • <u>For a:</u>

The chemical equation follows:

HCN(aq.)+H_2O(l)\rightleftharpoons CN^-(aq.)+H_3O^+(aq.);K_{eq}=6.2\times 10^{-10}

The expression of K_{eq} for above reaction follows:

K_{eq}=\frac{[CN^-][H_3O^+]}{[HCN][H_2O]}=6.2\times 10^{-10}

As, K_{eq}, the reaction will be favored on the reactant side.

Hence, the equilibrium mixture contains primarily reactants.

  • <u>For b:</u>

The chemical equation follows:

H_2(g)+Cl_2(g)\rightleftharpoons 2HCl(g);K_{eq}=2.51\times 10^{4}

The expression of K_{eq} for above reaction follows:

K_{eq}=\frac{[HCl]^2}{[H_2][Cl_2]}=2.51\times 10^{4}

As, K_{eq}>1, the reaction will be favored on the product side.

Hence, the equilibrium mixture contains primarily products.

4 0
2 years ago
Determine if the following salt is neutral, acidic or basic. If acidic or basic, write the appropriate equilibrium equation for
Nat2105 [25]

Answer:

It is neutral (NR)

Explanation:

Salts are formed when the ionizable hydrogens in an acid is replaced by metallic or ammonium ions from bases. The reaction is known as a neutralization reaction.

The nature of a salt formed from this reaction depends on the nature of the reacting acid and base.

If the reaction is between a strong acid and strong base, the salt produced is a neutral salt.

If the reaction occurs between a strong acid and a weak base, the salt produced is acidic.

If the reaction occurs between a strong base and a weak acid, the salt produced is a basic salt.

Considering the salt above, LiNO3.

On hydrolysis, addition of water, the following products are obtained:

LiNO3 + H2O ----> LiOH + HNO3

The products obtained, LiOH and HNO3 are a strong base and a strong acid respectively. Therefore, the salt, LiNO3, is a neutral salt.

7 0
2 years ago
In the adjoining figure, the circles with the + sign represent protons and the empty circles represent neutrons. Determine which
Natali [406]

Answer: option C. 2 and 3.

Explanation:

1) Isotopes are atoms of a same element with different number of neutrons. That means that the isotopes of a same element have the same number of protons, since the number of protons is what identify an element.

2) For example, all the atoms of oxygen have 8 protons. But isotope oxygen-16 has 8 neutrons, while oxygen-18 has 10 neutrons.

3) In the figure there are 3 different atoms:

i) atom # 1 has 5 protons and 7 neutrons

ii) atom # 2 has 6 protons and 7 neutrons

iii) atom # 3 has 6 protons and 8 neutrons.

4) Hence the atoms with the same number of protons and different number of neutrons are the #2 and the # 3. So, they are the isotopes of the same element.

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A mixture of carbon dioxide and an unknown gas was allowed to effuse from a container. The carbon dioxide took 1.25 times as lon
Aleks04 [339]

Answer:

CO

Explanation:

From Graham's law, time taken to diffuse is directly proportional to the molecular mass of the gases. For two different gases.

t1/t2=√m1/m2

Since gas 1 diffuse 1.25 times as slowly as gas 2 and gas 1 is CO2 with m as 44g

1.25/1=√44/m2

Therefore m2=28g CO

7 0
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