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kolbaska11 [484]
2 years ago
14

3. A student was given an unknown metal. The student determined that the mass of the metal was 30.2 g. The student placed the

Chemistry
1 answer:
expeople1 [14]2 years ago
6 0

Answer:

15.1 g/mL

Explanation:

<em>The density of a substance is defined as the ratio of the mass of the substance and the volume of the substance. Mathematically, it is expressed as:</em>

Density = mass in grams/volume in mL

In this case, the mass of the metal = 30.2 g

Volume of the metal = volume of water displaced by the metal.

<em>The volume of water displaced by the metal can be calculated as the final volume of water after placing the metal - initial volume of water before placing the metal.</em>

Hence, volume of metal = 22.0 - 20.0 mL = 2.0 mL

Density of metal = 30.2/2.0 = 15.1 g/mL

The density of the metal is 15.1 g/mL

<u>The identity of the metal is not in the table.</u>

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WARRIOR [948]

Answer:

20.2 g silver placed in 21.6 mL of water and 20.2 g copper placed in 21.6 mL of water

Explanation:

Since the density formula is mass divided volume, you can calculate the density of each of the components of the group and see which of all the groups are equal

In the group

density Ag=20.2 g silver/21.6ml H2O=0.9352g/ml

density Cu=20.2 g copper/21.6ml H2O=0.9352 g/ml

6 0
2 years ago
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In the first paragraph, the words "disrobed," "unveiling" and<br> "deconstructed" primarily serve to
Solnce55 [7]

Complete Question:

In the first paragraph, the words “disrobed,” “unveiling” and “deconstructed” primarily serve to (a) highlight the negative connotations that laser technology currently has, (b) emphasize the extensive reach of laser technology; (c) demonstrate the inherently unknowable characteristics of objects, even with laser technology; (d) implicitly compare lasers to other forms of technology

Answer:

(b) emphasize the extensive reach of laser technology;

Explanation:

The use of the word disrobed and deconstructed from the passage emphasizes the extensive reach of laser technology. Even without looking up the dictionary meaning of the two words, one can easily deduce that the passage is a pro-laser technology one.

  • The passage presents the use of the laser technology in solar exploration.
  • It also show its use by ecologists.

#learnwithBrainly

8 0
2 years ago
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What volume is occupied by 0.34 moles of Helium gas?
guapka [62]

Answer:

0.65882352941

Explanation:

5 0
2 years ago
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When 1.00 g of boron is burned in o2(g) to form b2o3(s), enough heat is generated to raise the temperature of 733 g of water fro
Bas_tet [7]
<span>Answer: For this problem, you would need to know the specific heat of water, that is, the amount of energy required to raise the temperature of 1 g of water by 1 degree C. The formula is q = c X m X delta T, where q is the specific heat of water, m is the mass and delta T is the change in temperature. If we look up the specific heat of water, we find it is 4.184 J/(g X degree C). The temperature of the water went up 20 degrees. 4.184 x 713 x 20.0 = 59700 J to 3 significant digits, or 59.7 kJ. Now, that is the energy to form B2O3 from 1 gram of boron. If we want kJ/mole, we need to do a little more work. To find the number of moles of Boron contained in 1 gram, we need to know the gram atomic mass of Boron, which is 10.811. Dividing 1 gram of boron by 10.811 gives us .0925 moles of boron. Since it takes 2 moles of boron to make 1 mole B2O3, we would divide the number of moles of boron by two to get the number of moles of B2O3. .0925/2 = .0462 moles...so you would divide the energy in KJ by the number of moles to get KJ/mole. 59.7/.0462 = 1290 KJ/mole.</span>
7 0
2 years ago
HBrO (aq) + H2O (l) ⇋ H3O+ (aq) + BrO- (aq)
joja [24]

Answer:

6.24 x 10-3 M

Explanation:

Hello,

In this case, for the given dissociation, we have the following equilibrium expression in terms of the law of mass action:

Ka=\frac{[H_3O^+][BrO^-]}{[HBrO]}

Of course, water is excluded as it is liquid and the concentration of aqueous species should be considered only. In such a way, in terms of the change x, we rewrite the expression considering an ICE table and the initial concentration of HBrO that is 0.749 M:

5.2x10^{-5}=\frac{x*x}{0.749-x}

Thus, we obtain a quadratic equation whose solution is:

x_1=-0.00627M\\x_2=0.00624M

Clearly, the solution is 0.00624 M as no negative concentrations are allowed, so the concentration of BrO⁻ is 6.24 x 10-3 M.

Best regards.

4 0
2 years ago
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