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Sphinxa [80]
2 years ago
8

In attempts to lift ron's spirits, dumbledore asks him a fairly easy question: calculate the mass percent composition of carbon

in c2h5cl. prof. vitarelli thinks you should try this also.
Chemistry
1 answer:
Salsk061 [2.6K]2 years ago
4 0
Mass percentage composition of carbon in the compound is the composition of carbon in the compound. This can be calculated by finding out the mass of carbon in the compound and the mass of the whole compound .
The compound formula is C2H5Cl
Mass of 1 mol of compound -64.5 g
Mass of carbon - 24 g
Mass percentage = 24/64.5 x100
Therefore mass composition percentage of carbon = 37.2%
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Air pressure is lower at high altitudes. An airplane cabin can adjust, but as the plane rises, passengers can experience tempora
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Answer:

The air pressure in the ears increases

The volume of air in the ears increases

The change in volume causes discomfort

It takes time for the ears to dispell excess air past the ear drum.

Explanation:

As the plane engages in a steep incline into the atmosphere, the outside atmospheric pressure decreases with altitude. The air pressure in the ear, therefore, become greater than atmospheric pressure. The air volume in the ear therefore grows and pushes on the ear causing discomfort. As the air in the cabin pressurizes the discomfort eases away as pressure equalization is restored relative to the ear.

4 0
2 years ago
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A group of students working in a high school chemistry lab believe they have discovered a new element! How exciting! Upon furthe
mart [117]

Answer:

1) The atomic number of this element is 74, because number of protons = atomic number

2) Mass number of this element is 184

Ar=Z+N=74+110=184

3) It isn't a new element. An element with such atomic and mass numbers exists

4) It is Wolfram. Symbol: W

5) Solid

Sorry if I made mistakes. I started learning English recently.

4 0
2 years ago
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When a stable diatomic molecule spontaneously forms from its atoms, what are the signs of Delta H, Delta S, and Delta G? A. + +
Neko [114]
H will definitely be positive because a bond is always more stable than no bond surely if it is a sigma bond.
For G you can't really know because you don't know how much energy is provided by the bond and if it outways the loss in disorder.


The reaction will become more spontaneous with a lower temperature because H tells you the reaction is exotherm
3 0
2 years ago
Identify the oxidizing agent and the reducing agent in the following reactions: (i) 8NH3( g) + 6NO2( g) => 7N2( g) + 12H2O( l
shusha [124]

Answer:

(i)  Oxidizing Agent: NO2 / Reducing Agent NH3-

(ii) Oxidizing Agent AgNO3 / Reducing Agent Zn

Explanation:

(i) 8NH3( g) + 6NO2( g) => 7N2( g) + 12H2O( l)

In this reaction, both two reactants contain nitrogen with a different oxidation number and produce only one product which contains nitrogen with a unique oxidation state. So, nitrogen is oxidized and reduced in the same reaction.

Nitrogen Undergoes a change in oxidation state from 4+ in NO2 to 0 in N2. It is reduced because it gains electrons (decrease its oxidation state). NO2 is the oxidizing agent (electron acceptor).

Nitrogen Changes from an oxidation state of 3- in NH3 to 0 in N2. It is oxidized because it loses electrons (increase its oxidation state). NH3 is the reducing agent (electron donor)

(ii) Zn(s) +AgNO3(aq) => Zn(NO3)2(aq) + Ag(s)

Ag changes oxidation state from 1+ to 0 in Ag(s).

Ag is reduced because it gains electrons and for this reason and AgNO3 is the oxidizing agent (electron acceptor)

Zn Changes from an oxidation state of 0 in Zn(s) to 2+ in Zn(NO3)2. It is oxidized and for this reason Zn is the reducing agent (electron donor).

Balanced equation:

Zn(s) +2AgNO3(aq) => Zn(NO3)2(aq) + 2Ag(s)

 

4 0
2 years ago
A 0.56 M solution of AlCl₃ is determined to have a concentration of particles of 1.79 M. What is the van't Hoff factor for AlCl₃
Crank

Answer:

Van't Hoff factor for AlCl₃ = 3 (Approx)

Explanation:

Given:

Number of observed particular = 1.79 M

Number of theoretical particular = 0.56 M

Find:

Van't Hoff factor for AlCl₃

Computation:

Van't Hoff factor for AlCl₃ = Number of observed particular / Number of theoretical particular

Van't Hoff factor for AlCl₃ = 1.79 M / 0.56 M

Van't Hoff factor for AlCl₃ = 3.19

Van't Hoff factor for AlCl₃ = 3 (Approx)

3 0
1 year ago
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