Answer:
2080 kJ/mol is the first ionization of 1st atom and 496 kJ/mol is the first ionization of 2nd atom
Explanation:
Given electronic configurations are :
1st: 
2nd : 
given 1st ionization energy are: 2080 kJ/mol and 496 kJ/mol
generally ionization energy of fulfilled orbital is more than half filled orbital and these two state are more stable.
therefore ionization energy of fulfilled is more than half filled orbital
hence
ionization energy of 1st atom will be very high because its orbital is fulfilled and less energy for 2nd atom so 2080 kJ/mol is the first ionization of 1st atom and 496 kJ/mol is the first ionization of 2nd atom.
Density is calculated using the following rule:
density = mass / volume
therefore:
mass = density * volume
mass of Hg = 13.6 * 60.2 = 818.72 grams
From the periodic table:
molar mass of Hg = 200.59 grams
number of moles = mass / molar mass
number of moles of Hg = 818.72 / 200.59 = 4.08 moles
each mole contains Avogadro's number of atoms.
Therefore,
number of atoms in the given sample = 4.08 * 6.022 * 10^23
= 2.456976 * 10^24 atoms
I believe the correct answer is the first option. To increase the molar concentration of the product N2O4, you should increase the pressure of the system. You cannot determine the effect of changing the temperature since we cannot tell whether it is an endothermic or an exothermic reaction. Also, decreasing the number of NO2 would not increase the product rather it would shift the equilibrium to the left forming more reactants. The only parameter we can change would be the pressure. And, since NO2 takes up more space than the product increasing the pressure would allow the reactant to collide more forming the product.
Answer:
Explanation:
Mol of NaI = 0.405 mol
Molarity of solution = 0.724 M
Molarity is given by
The required volume is .
