All categories

2 years ago

To burn 1 molecule of C5H12 to form CO2 and H2O (complete combustion), how many molecules of O2 are required?

Chemistry

2 answers:

viva [34]2 years ago

5 0

C5H12 + 8 O2 → 5 CO2 + 6 H2O

8 molecules of O2 are required.

matrenka [14]2 years ago

5 0

Answer:

8 molecules of oxygen gas are required.

Explanation:

Combustion reaction is the type of chemical reaction in which a hydrocarbon reacts with oxygen gas to give to carbon dioxide and water.

$C_5H_{12}+8O_2\rightarrow 5CO_2+6H_2O$

According to reaction ,1 mole of pentane reacts with 8 molecules of oxygen gas to give 5 moles of carbon dioxide and 6 moles of water.

So, to burn 1 mole of pentane we will need 8 molecules of oxygen gas.

You might be interested in

Which of the following NOT a principle of deep ecology, according to Arne Naess? All life has intrinsic value Environment must b

motikmotik

Answer:

On the picture are all principles cited on wikipedia.

Explanation:

So the answer is

1. Environment must be exploited to improve living standards

2. Flourishing human and nonhuman life depends on diversity of life forms

5 0

2 years ago

A chemist adds 180.0 mL of a 1.42M sodium carbonate (Na CO,) solution to a reaction flask. Calculate the millimoles of sodium ca

svet-max [94.6K]

Answer: The millimoles of sodium carbonate the chemist has added to the flask are 256

Explanation:

Molarity is defined as the number of moles dissolved per liter of the solution.

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{milli moles of solute}}{\text{Volume of solution in ml}}$ .....(1)

Molarity of $BaCl_2$ solution = 1.42 M

Volume of solution = 180.0 mL

Putting values in equation 1, we get:

$1.42M=\frac{\text{milli moles of }BaCl_2}{180.0ml}\\\\\text{milli moles of }BaCl_2}={1.42M\times 180.0ml}=256milli mol$

Thus the millimoles of sodium carbonate the chemist has added to the flask are 256.

6 0

2 years ago

For some jobs, “good enough” is good enough. That’s sometimes true in chemistry. More often, though, careful planning, calculati

Lilit [14]

For the first task, lighting a campfire can be used. Quantities of firestarter and kindling do not need to be precise. For the second task, the process of titration can be used. In a titration, the precise amount of a substance may be determined by adding a precise amount of a reactive species

4 0

2 years ago

Read 2 more answers

Which of the following statements is true concerning the reaction given below?2H2S(g) + O2(g) → 2S(s) + 2H2O(g)a. The reaction i

pantera1 [17]

Answer:

The rate law may be determined only by experiment.

Explanation:

For a reaction, A + B ---> C, the rate law can only be determined from experimental data. Chemists determine the rate of reaction by carefully observing the changes in the concentration of species as the reaction progresses.

Hence, the rate law is not determined by inspection of the chemical reaction equation, it must be obtained from the experimental data, hence the answer given.

8 0

2 years ago

Consider the reaction H2(g) + Cl2(g) → 2HCl(g)ΔH = −184.6 kJ / mol If 2.00 moles of H2 react with 2.00 moles of Cl2 to form HCl,

zalisa [80]

Answer:

ΔU=-369.2 kJ/mol.

Explanation:

We start from the equation:

Δ(H)=ΔU+Δ(PV), which is an extension of the well known relation: H=U+PV.

If Δ(PV) were calculated by ideal gas law,

PV=nRT

Δ(PV)=RTΔn.

Where Δn is the change of moles due to the reaction; but, this reaction does not give a moles change (Four moles of HCl produced from 4 moles of reactants), so Δ(PV)=0.

So, for this case, ΔH=ΔU.

The enthalpy of reaction given is for one mole of reactant, so the enthalpy of reaction for the reaction of interest must be multiplied by two:

$2 reactant moles*\frac{-184.6kJ}{mol}$

ΔU=-369.2 kJ/mol.

4 0

2 years ago