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OlgaM077 [116]
2 years ago
13

You wish to extract an organic compound from an aqueous phase into an organic layer (three to six extractions on a marco scale).

With regard to minimizing the number of transfer steps, would it be better to use an organic solvent that is heavier or lighter than water
Chemistry
1 answer:
AVprozaik [17]2 years ago
7 0

Answer:

Explanation:

It will be better to use solvents that are lighter than water, because their density has an influence on the miscibility . This will give you a better separation during extraction.

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Wich if the following statements best describes why the mass of a bowling ball would not change if it were transported from eart
Murljashka [212]

Answer:

the amount of matter in the bowling ball remains the same

Explanation:

The reason why the mass of the bowling ball on earth and moon remains the same is that matter in the bowling ball remains the same.

Mass of any substance is the amount of matter it contains.

  • Since there is no loss in matter, the mass of the bowling ball anywhere in the universe will be the same.
  • Only the weight changes due to differences in gravity.
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1 year ago
The density of lead is 11.4 g/cm3 at 20°C. A chemist has a metallic sample that is either pure lead or mostly lead. If the densi
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The sample is most likely lead with lighter substances in it. Pure lead would be closer to the pure lead density, and heavier substances would make the density more, not less.
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1 year ago
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A chunk of dry ice, solid CO2, "disappears" after sitting at room temperature for a while. There is no puddle of liquid. What ha
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I believe the answer is A.
8 0
2 years ago
If 4.35 g of phosphoric acid are added to 5.25g of KOH, what is the percent yield of the reaction if only 3.15g of potassium pho
irina1246 [14]
We are given with
4.35 g Phosphoric acid
5.25 g KOH
3.15 g K3PO4 produced

The reaction is
H3PO4 + 3KOH => K3PO4 + 3H2O

First, convert masses into moles.
Then, determine the limiting reactant.
Next, determine the maximum amount of K3PO4 that can be produced from the limiting reactant.
Lastly, calculate the percent yield by dividing the actual amount produced by the theoretical amount produced.
5 0
2 years ago
Starting with 1.5052g of BaCl2•2H2O and excessH2SO4, how many grams of BaSO4 can be formed?
muminat
1.5052g BaCl2.2H2O => 1.5052g / 274.25 g/mol = 0.0054884 mol
=> 0.0054884 mol Ba 
<span>This means that at most 0.0054884 mol BaSO4 can form since Ba is the limiting reagent. </span>
<span>0.0054884 mol BaSO4 => 0.0054884 mol * 233.39 g/mol = 1.2809 g BaSO4</span>
6 0
2 years ago
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