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pishuonlain [190]
2 years ago
9

dentify salts that will dissolve to give an acidic solution. (Select all that apply.) LiCl C6H5NH3Cl NaNO2 CH3NH3Br CH3COONa KCl

O4 Identify salts that will dissolve to give a basic solution. (Select all that apply.) LiCl C6H5NH3Cl NaNO2 CH3NH3Br CH3COONa KClO4 Identify salts that will dissolve to give a neutral solution. (Select all that apply.) LiCl C6H5NH3Cl NaNO2 CH3NH3Br CH3COONa KClO4
Chemistry
1 answer:
Lubov Fominskaja [6]2 years ago
6 0

Answer:  C_6H_5NH_3Cl and CH_3NH_3Br are acidic solutions

Explanation:

When a weak acid and strong base reacts, it leads to the formation of a basic solution.

When a strong acid and weak base reacts, it leads to the formation of acidic solution.

When a strong acid and strong base or weak acid and weak base reacts, it leads to the formation of a neutral solution.

LiCl is neutral, as it is formed from the combination of strong acid and strong base.

C_6H_5NH_3Cl:  acidic, as it is formed from the combination of weak base and strong acidic

NaNO_2: basic, as it is formed from the combination of weak acid and strong base.

CH_3NH_3Br:  acidic, as it is formed from the combination of weak  base and strong acid.

CH_3COONa:   basic, as it is formed from the combination of strong  base and weak acid.

KClO_4:  neutral, as it is formed from the combination of strong acid and strong base.

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3.98 x 10⁻¹⁹ Joule

<h3>Further explanation</h3>

<u>Given:</u>

The green light has a frequency of about 6.00 x 10¹⁴ s⁻¹.

<u>Question:</u>

The energy of a photon of green light (in joules).

<u>The Process:</u>

The energy of a photon is given by \boxed{\boxed{ \ E = hf \ }}

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Let us find out the energy of the green light emitted per photon.

\boxed{ \ E = (6.63 \times 10^{-34})(6.00 \times 10^{14}) \ }

Thus, we get a result of \boxed{\boxed{ \ E = 3.98 \times 10^{-19} \ J \ }}

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Notes

  • When an electron moves between energy levels it must emit or absorb energy.  
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Answer and Explanation:

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