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pishuonlain [190]
2 years ago
9

dentify salts that will dissolve to give an acidic solution. (Select all that apply.) LiCl C6H5NH3Cl NaNO2 CH3NH3Br CH3COONa KCl

O4 Identify salts that will dissolve to give a basic solution. (Select all that apply.) LiCl C6H5NH3Cl NaNO2 CH3NH3Br CH3COONa KClO4 Identify salts that will dissolve to give a neutral solution. (Select all that apply.) LiCl C6H5NH3Cl NaNO2 CH3NH3Br CH3COONa KClO4
Chemistry
1 answer:
Lubov Fominskaja [6]2 years ago
6 0

Answer:  C_6H_5NH_3Cl and CH_3NH_3Br are acidic solutions

Explanation:

When a weak acid and strong base reacts, it leads to the formation of a basic solution.

When a strong acid and weak base reacts, it leads to the formation of acidic solution.

When a strong acid and strong base or weak acid and weak base reacts, it leads to the formation of a neutral solution.

LiCl is neutral, as it is formed from the combination of strong acid and strong base.

C_6H_5NH_3Cl:  acidic, as it is formed from the combination of weak base and strong acidic

NaNO_2: basic, as it is formed from the combination of weak acid and strong base.

CH_3NH_3Br:  acidic, as it is formed from the combination of weak  base and strong acid.

CH_3COONa:   basic, as it is formed from the combination of strong  base and weak acid.

KClO_4:  neutral, as it is formed from the combination of strong acid and strong base.

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An increase in temperature will effect vapor pressure by:
-BARSIC- [3]

Answer: Increases.

Explanation:  As the temperature of a liquid or solid increases its vapor pressure also increases. Conversely, vapor pressure decreases as the temperature decreases.

5 0
2 years ago
A chemist mixes 75.0 g of an unknown substance at 96.5C w/ 1,150 g of water at 25.0C . if the final temperature of the system is
vichka [17]
Remember: heat lost = heat gained 

When calculating heat loss or gain, remember 

mass*(spec heat cap)*(change in T) 

The unknown loses heat- we don't know the spec heat cap, so we'll call it x.

The water gains. I've omitted the units, but always use when solving problems on your own. 

75*x*(96.5-37.1) = 1150*4.184*(37.1-25) 
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Now it's all set up- use algebra to get x, the spec heat cap of the unk in J/g*degC

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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3 0
2 years ago
A curium-245 nucleus is hit with a neutron and changes as shown by the equation. Complete the equation by filling in the missing
Lera25 [3.4K]

Try this option:

^{245}_{96}Cm+^1_0n=^{103}_{42}Mo+^{245+1-103-3*1}_{96+0-42-3*0}(X)+3^1_0n;

^{245}_{96}Cm+^1_0n=> ^{103}_{42}Mo+^{140}_{54}(X)+3^1_0n;

^{245}_{96}Cm+^1_0n=> ^{103}_{42}Mo+^{140}_{54}Xe+3^1_0n;

Answer:

^{140}_{54}Xe

8 0
2 years ago
Read 2 more answers
The percent composition by mass of a compound is 76.0% c, 12.8% h, and 11.2% o. the molar mass of this compound is 284.5 g/mol.
Leokris [45]
You have a few steps to solve this one. First, we'll find the molar mass by percentage of each element in the molecule. Then, we'll divide each of those relative masses by the atomic mass of each element. The number of times the mass divides into the relative mass is the number of atoms of that element in the molecule:

C: 284.5 x .76 = 216.22
H: 284.5 x .128= 36.416
O: 284.5 x .112 = 31.864.

Now we divide out each element's atomic mass (from the periodic table). it's okay if they're approximated from the decimal answer.
C: 216.22 ÷ 12.011 ≈ 18
H: 36.416 ÷ 1.008 ≈36
O: 31.864 ÷ 15.999 ≈ 2

Therefore, the molecular formula is C18H36O2. 

The empirical formula would be found by dividing out all factors of those subscript numbers. In our case, all of them can be divided by 2. The empirical formula would be C9H18O




7 0
2 years ago
The specific heat of aluminum is 0.214 cal/g.oC. Determine the energy, in calories, necessary to raise the temperature of a 55.5
Natasha2012 [34]
For this problem, we use the formula for sensible heat which is written below:

Q= mCpΔT
where Q is the energy
Cp is the specific heat capacity
ΔT is the temperature difference

Q = (55.5 g)(<span>0.214 cal/g</span>·°C)(48.6°C- 23°C)
<em>Q = 304.05 cal</em>
4 0
2 years ago
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