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2 years ago

10

as a result of chemical weathering, even a hard rock such as granite can be turned into __________. a) sediment b) limestone c)

kaolin d) minerals

1 answer:

kotykmax [81]2 years ago

3 0

The best ansewer would be a)sediment

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Which of the following contains maximum number of atoms? a) 2.0g hydrogen b) 2.0g oxygen c) 2.0g nitrogen d) 2.0g methane

Fynjy0 [20]

A) 2.0g hydrogen is your answer

7 0

2 years ago

Write the balanced chemical equation for the reaction shown.

son4ous [18]

Explanation:

Carbon black sphere

Nitrogen blue sphere

Chlorine green sphere

Hydrogen white sphere

Reactants:

three molecules that contain one black sphere and four white spheres

3CH₄

three molecules that contain two blue spheres and four green spheres:

3N₂Cl₄

Products:

three molecules that contain one black sphere and four green spheres:

3CCl₄

three molecules that contain two blue spheres:

3N₂

six molecules that contain two white spheres

6H₂

The reaction proper:

3CH₄ + 3N₂Cl₄ → 3CCl₄ + 3N₂ + 6H₂

Learn more:

Chemical reactions brainly.com/question/4216541

#learnwithBrainly

7 0

2 years ago

Neon is a gas made up of only one type of atom. Which term best describes neon?

Juli2301 [7.4K]

Neon<span> is a rare inert </span>noble gas<span> and is</span><span> colorless and odorless </span><span>with about two-thirds the density of air. It </span><span>is chemically </span>inert <span>and does not form uncharged chemical compounds.</span>

8 0

2 years ago

Read 2 more answers

What mass of 2-bromopropane could be prepared from 25.5 g of propene? Assume a 100% yield of product.

Mamont248 [21]

Answer:

78.46 grams of 2-bromopropane could be prepared from 25.5 g of propene

Explanation:

$C_3H_6+HBr\rightarrow C_3H_7Br$

Moles of propene = $\frac{25.5 g}{39 g/mol}=0.6538 mol$

According to reaction, 1 mole of propene gives 1 mole of propane.

Then 0.6538 moles of bromo-propane will give:

$0.6538 mol\times 120 g/mol=78.46 g$

78.46 grams of 2-bromopropane could be prepared from 25.5 g of propene.

5 0

2 years ago

Calculate the volume of H2(g) at 273 K and 2.00 atm that will be formed when 275 mL of 0.725 M HCl solution reacts with 50.0 g Z

Anarel [89]

Answer:

The volume of H₂ (g) obtained is 22.4L

Explanation:

First of all, think the reaction:

2HCl (aq) + Zn (s) → ZnCl₂ (aq) + H₂ (g)

You have to add a 2, in the HCl to get ballanced.

Now we should know how many moles of each reactant, do we have.

Volume . Molarity = moles

Notice that volume is in mL, so I must convert to L.

275 mL = 0.275L

0.275L . 0.725mol/L = 0.2 moles of HCl

Molar mass of Zn: 65.41 g/m

50 g / 65.41 g/m = 0.764 moles

Ratio between reactants is 2:1, so I need the double of moles of HCl to react, and a half moles of Zn to react.

<em>My limiting reactant is the HCl</em>, for 0.764 moles of Zinc, I need 1.528 (0.764 .2) of HCl, and I only have 0.2 moles.

Ratio between HCl and H₂ is 1:1, so 0.2 HCl make 0.2 moles of gas

Now apply the Ideal Gas Law, to find out the volume

P. V = n . R . T

2 atm . V = 0.2 mol . 0.08206L atm/K mol . 273K

V = (0.2 mol . 0.08206L atm/K mol . 273K ) / 2 atm

V = 2.24 L

6 0

2 years ago