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marin [14]
2 years ago
11

The diagram shows the movement of particles from one end of the container to the opposite end of the container. A cylindrical co

ntainer is shown sealed at the top and bottom, with a solid layer with one small hole in it in the middle. The top part of the container has many small balls in it; the bottom part has only 4 balls. Arrows point down through the hole in the center layer. Which event is most likely occurring? diffusion because particles move from regions of high concentration to regions of low concentration diffusion because particles move from regions of low concentration to regions of high concentration effusion because there is a movement of a gas through a small opening into a larger volume effusion because there is a movement of a gas through a large opening into a smaller volume
Chemistry
2 answers:
Rzqust [24]2 years ago
8 0

Answer:

C. effusion because there is a movement of a gas through a small opening into a larger volume

Explanation:

got it right on edg

trapecia [35]2 years ago
3 0

Answer:

C. effusion because there is a movement of a gas through a small opening into a larger volume

Explanation:

Effusion makes fluid/gas molecules move to the container with less pressure or larger volume. In diffusion, the movement should work two ways even though one side might receive more. But in effusion, the movement is rather one way.

This case shows how effusion work because its not the concentration that makes the balls moving to the bottom part of the container. No ball moving from bottom container to top either.

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15. Using the information below, calculate ΔHf° for PbO(s)
Svet_ta [14]
ΔH(reaction) = ΔH(formation of products) - ΔH(formation of reactants) 
ΔH(reaction) = ( 1*ΔH(Pb(s)) + 1*ΔH(CO2(g)) ) - ( 1*ΔH(PbO(s)) + 1*ΔH(CO(g)) ) 
ΔH(reaction) = ( 0 + -393.5 ) - ( ΔH(PbO(s)) + -110.5 ) 
ΔH(reaction) = -283 - ΔH(PbO(s)) 
-131.4 = -283 -ΔH(PbO(s)) 
ΔH(PbO(s)) = -151.6 kJ

So, the best answer is A.
5 0
2 years ago
Read 2 more answers
Calculate the concentration of H3O in a solution that contains 5.5 × 10-5 M OH at 25°C. Identify the solution as acidic, basic o
Masteriza [31]

Answer:

The correct option is option (D).

Therefore the concentration of H_3O is 1.8×10⁻¹⁰ M and it is basic in nature.

Explanation:

List of pH:

  1. If pH of a solution is 7, then solution is neutral.
  2. If pH of a solution is grater than 7, then solution is basic.
  3. If pH of a solution is less than 7, then solution is acidic.

pH of a solution is = - log₁₀[H₃O⁺]

We know that,

[H₃O⁺][OH⁻] = K_w = 10^{-14}  (at 25°C)

Taking log both sides

log ([H₃O⁺][OH⁻]) =log K_w =log 10^{-14}

⇒log[H₃O⁺]+log[OH⁻] = logK_w = -14 log 10

[since log(mn)= log m + log n, log( a^b)=b\ log (a) ]

⇒ - log[H₃O⁺] - log[OH⁻] = - (-14)  [ log 10 =1]

⇒pH+pOH =14.

Given that,

The concentration of OH⁻ is 5.5 × 10⁻⁵ M

[H₃O⁺][OH⁻] = K_w = 10^{-14}

⇒[H₃O⁺] 5.5 × 10⁻⁵ M=10⁻¹⁴

\Rightarrow [H_3O^+]=\frac{10^{-14}}{5.5\times 10^{-5}}

⇒[H₃O⁺] = 1.8×10⁻¹⁰ M

Now check the pH of the solution.

[H₃O⁺] = 1.8×10⁻¹⁰

Taking log both sides

log [H₃O⁺] =log( 1.8×10⁻¹⁰)

⇒ -log [H₃O⁺] = - log( 1.8×10⁻¹⁰)

⇒ pH = - log( 1.8×10⁻¹⁰)

⇒ pH =9.7.

So the nature of solution is basic.

Therefore the concentration of H_3O is 1.8×10⁻¹⁰ M and it is basic in nature.

4 0
2 years ago
In which orbital does an electron in a bromine atom experience the greatest effective nuclear charge?
asambeis [7]

First let us determine the electronic configuration of Bromine (Br). This is written as:

Br = [Ar] 3d10 4s2 4p5

 

Then we must recall that the greatest effective nuclear charge (also referred to as shielding) greatly increases as distance of the orbital to the nucleus also increases. So therefore the electron in the farthest shell will experience the greatest nuclear charge hence the answer is:

<span>4p orbital</span>

4 0
2 years ago
Read 2 more answers
Match each set of quantum numbers to the correct subshell description by typing in the correct number. 1: n = 2, l = 0 2p: 2: n
Reil [10]

Answer:

4

2

1

5

3

Explanation:

4 0
2 years ago
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Which conjugate pair is suited best to make this buffer? Which conjugate pair is suited best to make this buffer? Phosphoric aci
Juliette [100K]

Answer:

bkfhjjfrsxtr

Explanation:

4 0
2 years ago
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