All categories

1 year ago

Give all possible, accurate, correct IUPAC names for the following compounds:

Chemistry

1 answer:

Viefleur [7K]1 year ago

6 0

Answer:

A. 4-ethyl-hex-3,5-dien-2-ol.

B. 2-chloro-3-methyl-5-<em>tert</em>-butylphenol.

Explanation:

Hello there!

In this case, according to the given problems, it is possible to apply the IUPAC rules to obtain the following names:

A. 4-ethyl-hex-3,5-dien-2-ol because we have an ethyl radical at the fourth carbon and the beginning of the parent chain is on the Me (CH3) because it is closest to first OH.

B. 2-chloro-3-methyl-5-<em>tert</em>-butylphenol: because we start at the alcohol and have a chlorine atom on the second carbon, a methyl radical on the third carbon, a <em>tert</em>-butyl on the fifth carbon and the parent chain is benzene which is phenol as an alcohol.

Regards!

You might be interested in

A readily corroded silvery solid that fizzes with water

fiasKO [112]

Answer:

c) a readily corroded silvery solid that fizzes with water ... (e) an orange high melting solid and good electrical conductor. (f) soft low melting ...

Explanation:

5 0

1 year ago

Calculate the hydroxide ion concentration [oh-] for human urine (ph = 6.2). notice this is about hydroxide.

igomit [66]

[OH⁻] = 1.6 × 10⁻⁸ mol / dm³

<h3>Explanation</h3>

By definition, $[\text{H}^{+}] = 10^{-\text{pH}}$ , where $[\text{H}^{+}]$ is the concentration of proton in the solution.

pH = 6.2 for this solution. As a result, $[\text{H}^{+} = 10^{-6.2} = 6.31 \times 10^{-7} \; \text{mol} \cdot \text{dm}^{-3}$ .

$[\text{H}^{+}] \cdot [\text{OH}^{-}] = \text{K}_w$ , where $[\text{OH}^{-}]$ the concentration of hydroxide ions and $\text{K}_w$ is the dissociation constant of water.

$\text{K}_w = 10^{-14} \; \text{mol}\cdot \text{dm}^{-3}$ at 0.10 MPa and 25 °C. As a result, $[\text{OH}^{-}] = \text{K}_w / [\text{H}^{+}] = 10^{14} / (6.31 \times 10^{-7}) = 1.6 \times 10^{-8} \; \text{mol}\cdot \text{dm}^{-3}$ .

5 0

1 year ago

The yeast Brettanomyces causes spoilage in wine. Brettanomyces produces 4-ethylphenol, which at high levels gives wine a bad fla

Tanya [424]

Hhbbbuddjcsdhnkvdb h jbbj jn

5 0

2 years ago

A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCl. What volume of 3.00 M HCl did the stu

Pani-rosa [81]

83.3 mL

Explanation:

M $_{i}$ = 3M

V $_{i}$ = 50mL

M $_{f}$ = 1.80M

Unknown:

V $_{f}$ = ?

Solution:

To solve this problem we must understand that the initial and final number of moles remains the same.

Number of moles = molarity x volume

Molarity x volume of initial solution = Molarity x volume of final solution

Therefore:

M $_{i}$ x V $_{i}$ = M $_{f}$ x V $_{f}$

M is the molarity

V is the volume

i = initial state

f = final state

input the parameters;

3 x 50 = 1.8 x V $_{f}$

V $_{f}$ = 83.3 mL

learn more:

Molarity brainly.com/question/9324116

#learnwithBrainly

8 0

1 year ago

Read 2 more answers

Draw the structure of the major organic product isolated from the reaction of 3-hexyne with hydrogen (1 mol), Lindlar palladium.

ohaa [14]

Answer:

See explanation and image attached

Explanation:

When 1 mole of hydrogen is added to 3-hexyne, the addition occurs on the same face or side of the triple bond to yield cis-2-hexene in the presence of lindlar catalyst which prevents further hydrogenation. This is known as syn addition.

The syn addition is achieved because the hydrogen molecule is first adsorbed on the surface of the palladium metal and is subsequently attached to the same face of the triple bond in 3-hexyne as shown in the image attached to this answer.

6 0

1 year ago