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1 year ago

A readily corroded silvery solid that fizzes with water

Chemistry

1 answer:

fiasKO [112]1 year ago

5 0

Answer:

c) a readily corroded silvery solid that fizzes with water ... (e) an orange high melting solid and good electrical conductor. (f) soft low melting ...

Explanation:

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6. Explain why the boiling point of water is a characteristic physical property, but the temperature and volume of a glass of wa

NNADVOKAT [17]

A physical property is a property that does not change the original substance, meaning that it does not break any bonds, nor for any new ones. Though, a physical property can be changing the substances state of matter.

When you are boiling water, you are changing its state to go from a liquid to a gas. The temperature is not a characteristic physical property because it doesn't help us know a lot about that substance, in other words, it isn't significant to the substance. Same goes for volume.

4 0

2 years ago

Read 2 more answers

How many moles of hydrogen gas are produced when 0.066 mole of sodium is completely reacted?

SVEN [57.7K]

Base on my research the complete reaction of hydrogen and sodium are form by this equation 2Na + 2H2O = 2NaOH +H2 If we base from this equation it shows you already the ratio of the moles of the product and reactants taking part in the reaction

1 mole of Na r/w 1 mole of water to produce .5 mole of Hydrogen

Therefore, .066 mole of Na produces .033 moles of H2

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1 year ago

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How many moles of CO2 could fit in a 475 mL bag a -22° C and 855 mmHg?

Sergeeva-Olga [200]

Answer:

The amount of moles of CO₂ is 0.026 moles

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of point particles that move randomly and do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The equation known as the ideal gas equation explains the relationship between the four variables P (Pressure), V (Volume), T (Temperature) and n (Amount of substance). The ideal gas law is expressed mathematically as:

P*V = n*R*T

where P represents the pressure of the gas, V its volume, n the number of moles of gas (which must remain constant), R the constant of the gases and T the temperature of the gas.

In this case:

P= 855 mmHg
V= 475 mL= 0.475 L
n= ?

R= 62.36367 $\frac{mmHg*L}{mol*K}$

T= -22°C= 251 °K

Replacing:

855 mmHg*0.475 L=n*62.36367 $\frac{mmHg*L}{mol*K}$ *251 °K

Solving:

$n=\frac{855 mmHg*0.475 L}{62.36367 \frac{mmHg*L}{mol*K} *251 K}$

n= 0.026 moles

<u><em>The amount of moles of CO₂ is 0.026 moles</em></u>

4 0

2 years ago

Identify the oxidizing and reducing agents in the following: 2H+(aq) + H2O2(aq) + 2Fe2+(aq) → 2Fe3+(aq) + 2H2O(l)

schepotkina [342]

Answer : The oxidizing and reducing agents are, $H_2O_2$ and $Fe^{2+}$ .

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given redox reaction is:

$2H^+(aq)+H_2O_2(aq)+2Fe^{2+}(aq)\rightarrow 2Fe^{3+}(aq)+2H_2O(l)$

The half oxidation-reduction reactions are:

Oxidation reaction : $Fe^{2+}\rightarrow Fe^{3+}+1e^-$

Reduction reaction : $O^-+1e^-\rightarrow O^{2-}$

The oxidation state of oxygen in $H_2O_2$ and $H_2O$ is, (-1) and (-2) respectively.

In this reaction, 'Fe' is oxidized from oxidation (+2) to (+3) and 'O' is reduced from oxidation state (-1) to (-2). Hence, ' $Fe^{2+}$ ' act as a reducing agent and ' $H_2O_2$ ' act as a oxidizing agent.

Thus, the oxidizing and reducing agents are, $H_2O_2$ and $Fe^{2+}$ .

7 0

1 year ago

Consider the following hypothetical reaction: 2 P + Q â†’ 2 R + S The following mechanism is proposed for this reaction: P + P Q

aleksandr82 [10.1K]

Answer: the answer is option (D). k[P]²[Q]

Explanation:

first of all, let us consider the reaction from the question;

2P + Q → 2R + S

and the reaction mechanism for the above reaction given thus,

P + P ⇄ T (fast)

Q + T → R + U (slow)

U → R + S (fast)

we would be applying the Rate law to determine the mechanism.

The mechanism above is a three step process where the slowest step seen is the rate determining step. From this, we can see that this slow step involves an intermediate T as reactant and is expressed in terms of a starting substance P.

It is important to understand that laws based on experiment do not allow for intermediate concentration.

The mechanism steps for the reactions in the question are given below when we add them by cancelling the intermediates on the opposite side of the equations then we get the overall reaction equation.

adding this steps gives a final overall reaction reaction.

2P + Q ------------˃ 2R + S

Thus the rate equation is given as

Rate (R) = K[P]²[Q]

cheers, i hope this helps

3 0

1 year ago