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dlinn [17]
2 years ago
7

Write a condensed structural formula for the repeat unit of the Kevlar molecule

Chemistry
2 answers:
shusha [124]2 years ago
4 0

Explanation:

Kevlar is a fiber which is used in making of bullet proof vests and armors. It is a co-polymer which is formed by condensing two organic molecules 1,4-phenylene-diamine and terephthaloyl chloride.

NH_2C_6H_4NH_2+Cl-(CO)-C_6H_4-(CO)-Cl\xrightarrow[-2HCl]{ }

                      NH_2-C_6H_4-NH-CO-C_6H_4-COOH

For Structure refer to image attached.


dolphi86 [110]2 years ago
3 0

The condensed formula for Kevlar is attached in the image.

Further explanation:

Polymerization is a process through which monomer molecules undergo addition or condensation reaction to form a three-dimensional network structure called polymers. They are also called as macromolecules.

Monomers are defined as low molecular weight compounds that undergo reaction to form high molecular weight compounds called polymers.

Types of polymerization:  

Addition polymerization is also known as chain-growth polymerization. It mainly occurs by the reaction in which a carbon-carbon double bond adds to a carbon-carbon double bond. There is no loss of small molecules in it.

Condensation reaction is a reaction where a larger molecule is formed by a reaction between two reactants by loss of small neutral molecules like {{\text{H}}_{\text{2}}}{\text{O}},{\text{N}}{{\text{H}}_3},{\text{HCl}}.

Kevlar is copolymer formed by condensation reaction between 1,4-phenylene-diamine and terephthaloyl chloride by loss of HCl molecule. It is heat resistant and strong synthetic fiber which is used in the making of bulletproof vests and armors.

The copolymerization of Kevlar occurs as follows:  

 {{\text{H}}_{\text{2}}}{\text{N}}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{4}}}{\text{N}}{{\text{H}}_{\text{2}}} + {\text{Cl}} - \left( {{\text{CO}}} \right) - {{\text{C}}_{\text{6}}}{{\text{H}}_{\text{4}}} - \left( {{\text{CO}}} \right) - {\text{Cl}}\; \to \;{\text{N}}{{\text{H}}_{\text{2}}}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{4}}} - {\text{NH}} - {\text{CO}} - {{\text{C}}_{\text{6}}}{{\text{H}}_{\text{4}}}{\text{COOH}}\;{\text{ +  2HCl}}

Learn more:

1. To draw a Lewis structure when the condensed formula is given: brainly.com/question/6215269

2. Write the condensed electronic configuration for monoatomic ion: brainly.com/question/8568483

Answer details:

Grade: Senior Secondary School

Subject: Chemistry

Chapter: Polymerization

Keywords: Kevlar, condensation, fiber, polymerization, addition, terephthaloyl chloride and phenylenediamine.

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4.8g of calcium is added to 3.6g of water. The following reaction occurs
notka56 [123]
Q1)
the number of moles can be calculated as follows
number of moles = mass present / molar mass
number of moles is the amount of substance.
4.8 g of Ca was added therefore mass present of Ca is 4.8 g
molar mass of Ca is 40 g/mol 
molar mass is the mass of 1 mol of Ca
therefore if we substitute these values in the equation 
number of moles of Ca = 4.8 g / 40 g/mol = 0.12 mol
0.12 mol of Ca is present 

q2)
next we are asked to calculate the number of moles of water present 
again we can use the same equation to find the number of moles of water
number of moles = mass present / molar mass
3.6 g of water is present 

sum of the products of the molar masses of the individual elements by the number of atoms 
H - 1 g/mol and O - 16 g/mol 
molar mass of water = (1 g/mol x 2 ) + 16 g/mol = 18 g/mol 
molar mass of H₂O is 18 g/mol 
therefore number of moles of water  = 3.6 g / 18 g/mol = 0.2 mol 
0.2 mol of water is present 
8 0
2 years ago
7. You are about to perform some intricate electrical studies on single skeletal muscle fibers from a gastronemius muscle. But f
Vilka [71]

Answer:

58.61 grams

Explanation:

Taking The molecular weight of NaCl = 58.44 grams/mole

<u>Determine how many grams of NaCl to prepare the bath solution </u>

first we will calculate the moles of NaCl that is contained in 6L of 170 mM of NaCI solution

= ( 6 * 170 ) / 1000

= 1020 / 1000 = 1.020 moles

next

determine how many grams of NaCl

= moles of NaCl * molar mass of NaCl

= 1.020 * 58.44

= 58.61 grams

4 0
2 years ago
Upon combustion, a 0.8009 g sample of a compound containing only carbon, hydrogen, and oxygen produces 1.6004 g co2 and 0.6551 g
dlinn [17]
The compound contains Carbon, Hydroxide and Oxide
1 mole of carbon iv oxide contains 44 g, out of which 12 g are carbon.
Therefore, 1.6004 g of CO2 will contain;
    1.6004 ×12/44 = 0.4365 g of carbon
1 mole of water contains 18 g of which 2 g is hydrogen,
Therefore, 0.6551 g of H2O will hace ;
         0.6551 × 2/18 = 0.0728 g of hydrogen.
The total mass of the compound is 0.8009 g,
Thus the mass of oxygen = 0.8009 -(0.4365 +0.0728)
                                         = 0.2916 g
To get the empirical formula we first get the number of moles of each element;\
 Carbon = 0.4365/12= 0.036375 moles
Hydrogen = 0.0728/1 = 0.0728 moles
Oxygen = 0.2916/16 = 0.018225 moles
Then, to get the smallest ratio we divide each with the smallest value;
Carbon :                        Hydrogen :                    Oxygen
= (0.036375/0.018225) : (0.0728/0.018225) : ( 0.018225/0.018225)
= 1.996                         :   3.995                    : 1
≈ 2 : 4 : 1
Therefore, the empirical formula is C2H4O


3 0
2 years ago
Products or solutions found at home or in store and their characteristics
AleksAgata [21]

Answer:

bruh, just go in your bathroom and look for cleaning products

Explanation:

4 0
2 years ago
A gas is know to have a volume of 7.81 liters when the pressure is 754 torr what would be the volume when the pressure is change
Elis [28]

Answer:

The volume when the pressure is changed to 1.23 atm and temperature is constant will be <u><em>6.3075 L</em></u>.

Explanation:

Pressure and volume are related by Boyle's law that says:

"The volume occupied by a certain gas mass at a constant temperature is inversely proportional to the pressure"

Boyle's law is expressed mathematically as:

P * V = k

where:

  • P: Pressure
  • V: Volume
  • k: Constant

Assuming a certain volume of gas V1 is at a pressure P1 at the beginning of the experiment. By varying the volume of gas to a new V2 value, then the pressure will change to P2, and the following will be true:

P1 * V1 = P2 * V2

In this case you have:

  • P1= 754 torr= 0.9921 atm (1 atm=760 torr)
  • V1= 7.82 L
  • P2=1.23 atm
  • V2=?

Replacing:

0.9921 atm*7.82 L=1.23 atm*V2

Resolving:

V2=\frac{0.9921 atm*7.82 L}{1.23 atm}

V2≅6.3075 L

<u><em>The volume when the pressure is changed to 1.23 atm and temperature is constant will be 6.3075 L.</em></u>

6 0
2 years ago
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