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dlinn [17]
2 years ago
7

Write a condensed structural formula for the repeat unit of the Kevlar molecule

Chemistry
2 answers:
shusha [124]2 years ago
4 0

Explanation:

Kevlar is a fiber which is used in making of bullet proof vests and armors. It is a co-polymer which is formed by condensing two organic molecules 1,4-phenylene-diamine and terephthaloyl chloride.

NH_2C_6H_4NH_2+Cl-(CO)-C_6H_4-(CO)-Cl\xrightarrow[-2HCl]{ }

                      NH_2-C_6H_4-NH-CO-C_6H_4-COOH

For Structure refer to image attached.


dolphi86 [110]2 years ago
3 0

The condensed formula for Kevlar is attached in the image.

Further explanation:

Polymerization is a process through which monomer molecules undergo addition or condensation reaction to form a three-dimensional network structure called polymers. They are also called as macromolecules.

Monomers are defined as low molecular weight compounds that undergo reaction to form high molecular weight compounds called polymers.

Types of polymerization:  

Addition polymerization is also known as chain-growth polymerization. It mainly occurs by the reaction in which a carbon-carbon double bond adds to a carbon-carbon double bond. There is no loss of small molecules in it.

Condensation reaction is a reaction where a larger molecule is formed by a reaction between two reactants by loss of small neutral molecules like {{\text{H}}_{\text{2}}}{\text{O}},{\text{N}}{{\text{H}}_3},{\text{HCl}}.

Kevlar is copolymer formed by condensation reaction between 1,4-phenylene-diamine and terephthaloyl chloride by loss of HCl molecule. It is heat resistant and strong synthetic fiber which is used in the making of bulletproof vests and armors.

The copolymerization of Kevlar occurs as follows:  

 {{\text{H}}_{\text{2}}}{\text{N}}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{4}}}{\text{N}}{{\text{H}}_{\text{2}}} + {\text{Cl}} - \left( {{\text{CO}}} \right) - {{\text{C}}_{\text{6}}}{{\text{H}}_{\text{4}}} - \left( {{\text{CO}}} \right) - {\text{Cl}}\; \to \;{\text{N}}{{\text{H}}_{\text{2}}}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{4}}} - {\text{NH}} - {\text{CO}} - {{\text{C}}_{\text{6}}}{{\text{H}}_{\text{4}}}{\text{COOH}}\;{\text{ +  2HCl}}

Learn more:

1. To draw a Lewis structure when the condensed formula is given: brainly.com/question/6215269

2. Write the condensed electronic configuration for monoatomic ion: brainly.com/question/8568483

Answer details:

Grade: Senior Secondary School

Subject: Chemistry

Chapter: Polymerization

Keywords: Kevlar, condensation, fiber, polymerization, addition, terephthaloyl chloride and phenylenediamine.

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vlabodo [156]

The number of particles  that  are in 12.7  moles of  compound that Jessica had is     7.65 x10^24 particles  of compound ( answer E)


    <u><em>Calculation</em></u>

<u><em> </em></u>The number  of particles are calculated  using the Avogadro's Principle  constant.


  • that is according  to  Avogadro's    1 moles =  6.02 x10^23 particles

             what about 12.7 moles  of  compound=   ?  particles\

   by use of  cross multiplication

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6 0
2 years ago
The stock concentration of dye is 3.4E-5M. The stock concentration of bleach is 0.36M. Assuming that the reaction goes to comple
Aleks04 [339]

Answer:

0.036 M

Explanation:

To do this, let's mark the dye as D and bleach as B.

We have the concentrations of both, and we already know that they react in a 1:1 mole ratio. The total volume of reaction is 9 + 1 = 10 mL or 0.010 L, and we hava both concentrations.

The problem already states that the dye reacts completely, so this is the limiting reagent, while bleach is the excess.

To know the remaining amount of bleach, we need to do this with the moles. First, let's calculate the initial moles of D and B:

moles D = 3.4x10⁻⁵ * 0.009 = 3.06x10⁻⁷ moles

moles B = 0.36 * 0.001 = 3.6x10⁻⁴ moles

Now that we have the moles, and that we know that all the dye reacts completely, let's see how many moles of bleach are left:

moles of B remaining = 3.6x10⁻⁴ - 3.06x10⁻⁷ = 3.597x10⁻⁴ moles

These are the moles presents of B after the reaction has been made. The concentration of the same will be:

[B] = 3.597x10⁻⁴ / 0.010

[B] = 0.0357

With 2 SF it would be:

[B] = 3.6x10⁻² M

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2 years ago
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In a fixed cylinder are 3moles of oxygen gas at 300Kelvin and 1.25atm. What is the volume of the container?
vladimir2022 [97]

Answer:

The volume of the container is 59.112 L

Explanation:

Given that,

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Temperature of the gas, T = 300 K

Pressure of the gas, P = 1.25 atm

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PV = nRT

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R is gas constant, R =  0.0821 atm-L/mol-K

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V=\dfrac{nRT}{P}\\\\V=\dfrac{3\ mol\times 0.0821\ L-atm/mol-K \times 300\ K}{1.25\ atm}\\\\V=59.112\ L

So, the volume of the container is 59.112 L

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2 years ago
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