answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anit [1.1K]
2 years ago
6

Study Example 8.1 on page 321. Then, calculate the molarity of a solution made by adding 5.51 g of CaCl2 to enough water to crea

te a solution with a total volume of 2.50 L. Enter only a numerical value in the correct number of significant figures. Use the Periodic Table that is part of your exam to calculate molar mass. Do not enter units in the answer box, but know that the symbol for the unit of this calculation is M
Chemistry
1 answer:
DiKsa [7]2 years ago
7 0

Answer:

0.0198 M

Explanation:

Given data

  • Mass of CaCl₂ (solute): 5.51 g
  • Volume of solution: 2.50 L

Step 1: Calculate the moles of solute

The <em>molar mass of CaCl₂</em> is 110.98 g/mol. The moles corresponding to 5.51 g are:

5.51 g × (1 mol/110.98 g) = 0.0496 mol

Step 2: Calculate the molarity of the solution

<em>M = moles of solute / liters of solution</em>

M = 0.0496 mol / 2.50 L

M = 0.0198 M

You might be interested in
One molecule of a compound weighs 2.03x10-22 g. what is the molar mass of that compound?
stealth61 [152]
<span>The molar mass of the compound is 122 g. </span>
6 0
2 years ago
Read 2 more answers
In May 2016, William Trubridge broke the world record in free diving (diving underwater without the use of supplemental oxygen)
Maru [420]

Answer:

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

Explanation:

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 3.6 L  

V₂ = ?

P₁ = 1.0 atm

P₂ = 13.3 atm (From correct source)

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{1.0\ atm}\times {3.6\ L}={13.3\ atm}\times {V_2}

{V_2}=\frac{{1.0}\times {3.6}}{13.3}\ L

{V_2}=0.27\ L

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

7 0
2 years ago
The unit cell for cr2o3 has hexagonal symmetry with lattice parameters a = 0.4961 nm and c = 1.360 nm. If the density of this ma
IRINA_888 [86]

To calculate the packing factor, first calculate the area and volume of unit cell.

Area is calculated as:

A=6R^{2}\sqrt{3}

Here, R is radius and is related to a as follows:

R=\frac{a}{2}

Putting the value in expression for area,

A=6(\frac{a}{2})^{2}\sqrt{3}=1.5a^{2}\sqrt{3}

The value of a is 0.4961 nm

Since, 1 nm=10^{-7}cm

Thus, 0.4961 nm=4.961\times 10^{-8} cm

Putting the value,

Area=1.5(4.961\times 10^{-8}cm)^{2}\sqrt{3}=6.39\times 10^{-15}cm^{2}

Now, volume can be calculated as follows:

V=Area\times c

The value of c is 1.360 nm or 1.360\times 10^{-7} cm

Putting the value,

V=(6.39\times 10^{-15}cm^{2})\times (1.360\times 10^{-7} cm)=8.7\times 10^{-22}cm^{3}

now, number of atom in unit cell can be calculated by using the following formula:

n=\frac{\rho N_{A}V_{c}}{A}

Here, A is atomic mass of Cr_{2}O_{3} is 151.99 g/mol.

Putting all the values,

n=\frac{(5.22 g/cm^{3})(6.023\times 10^{23} mol^{-1})(8.7\times 10^{-22}cm^{3})}{(151.99 g/mol)}\approx 18

Thus, there will be 18 Cr_{2}O_{3} units in 1 unit cell.

Since, there are 2 Cr atoms and 3 oxygen atoms thus, units of chromium and oxygen will be 2×18=36 and 3×18=54 respectively.

The atomic radii of Cr^{3+} and O^{2-} is 62 pm and 140 pm respectively.

Converting them into cm:

1 pm=10^{-10}cm

Thus,

r_{Cr^{3+}}=6.2\times 10^{-9}cm

and,

r_{O^{2-}}=1.4\times 10^{-8}cm

Volume of sphere will be sum of volume of total number of cations and anions thus,

V_{S}=V_{Cr^{3+}}+V_{O^{2-}}

Since, volume of sphere is V=\frac{4}{3}\pi r^{3},

V_{S}=36\left ( \frac{4}{3}\pi (r_{Cr^{3+})^{3}} \right )+54\left ( \frac{4}{3}\pi (r_{O^{2-})^{3}} \right )

Putting the values,

V_{S}=36\left ( \frac{4}{3}(3.14) (6.2\times 10^{-9} cm)^{3}} \right )+54\left ( \frac{4}{3}(3.14) (1.4\times 10^{-8} cm)^{3}} \right )=6.6\times 10^{-22}\times 10^{-8}cm^{3}

The atomic packing factor is ratio of volume of sphere and volume of crystal, thus,

packing factor=\frac{V_{S}}{V_{C}}=\frac{6.6\times 10^{-22}cm^{3}}{8.7\times 10^{-22}cm^{3}}=0.758

Thus, atomic packing factor is 0.758.

6 0
2 years ago
Read 2 more answers
Two cars started at the same position and were driven through a city using different streets. The red car traveled north 2 miles
Bad White [126]

Answer:

C

green traveled les distance but still ended up in the same location as red

5 0
2 years ago
Read 2 more answers
How many grams of KBr are required to make 550. mL of a 0.115 M KBr solution?
In-s [12.5K]

Molarity is expressed as the number of moles of solute per volume of the solution. For example, we are given a solution of 2M NaOH this describes a solution that has 2 moles of NaOH per 1 L volume of the solution. We calculate as follows:

0.115 M = n mol KBr / .55 L solution

n = 0.06325 mol KBr

mass = 0.06325 mol KBr (119 g / mol) = 7.53 g KBr

4 0
2 years ago
Other questions:
  • In Males which of the following organ performs a dual function of ejaculation of sperm and voiding of urine
    13·2 answers
  • When the alcohol thermometer is placed in 20∘c water, what temperature will the thermometer record?
    7·2 answers
  • Calculate the ph of a 0.20 m solution of iodic acid (hio3, ka = 0.17).
    6·1 answer
  • Consider two solutions, the first being 50.0 mL of 1.00 M CuSO4 and the second 50.0 mL of 2.00 M KOH. When the two solutions are
    12·1 answer
  • Ammonia gas is compressed from 21°C and 200 kPa to 1000 kPa in an adiabatic compressor with an efficiency of 0.82. Estimate the
    15·1 answer
  • A 60.0 mL sample of 0.250 M NaOH is added to a beaker containing 125 mL of 0.120 M HOCl. Ka for HOCl is 3.5 x 10-8 at 25o C. Fin
    6·1 answer
  • what would the total pressure of a mixture of fluorine, chlorine, and bromine gases be if the partial pressure are 2.20 atm, 6.7
    11·1 answer
  • The decantate from Question 1 that possibly contains K, Zn, or Cr, is neutralized with acetic acid and divided into the appropri
    9·1 answer
  • A compound A (C22H27NO) is insoluble in acid and base but reacts with concentrated aqueous HCl and heat to give a clear aqueous
    9·1 answer
  • A compound containing Na, C, and O is found to have 1.06 mol Na, 0.528 mol C, and 1.59 mol O. What is the empirical formula of t
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!