The oxidation numbers of nitrogen in NH3, HNO3, and NO2 are, respectively: -3, -5, +4 +3, +5, +4 -3, +5, -4 -3, +5, +4

1 answer:

5 0

In NH3 , let oxidation number of N be x

x + (+1)3 = 0

x = -3

In HNO3 , let oxidation number of N be x

1 + x + (-2)3 = 0

x = +5

In NO2 , let oxidation number of N be x

x + (-2)2 = 0

x = +4

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parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
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Answer:

The structures are attached in file.

Hydrogen bonding and intermolecular forces is the reason for ranks allotted.

Explanation:

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Read 2 more answers

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yaroslaw [1]

Sorenson

Explanation:

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The pH and pOH scale is logarithmic scale that ranks the acidity and bascity of compounds.
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