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2 years ago

The oxidation numbers of nitrogen in NH3, HNO3, and NO2 are, respectively: -3, -5, +4 +3, +5, +4 -3, +5, -4 -3, +5, +4

1 answer:

5 0

In NH3 , let oxidation number of N be x

x + (+1)3 = 0

x = -3

In HNO3 , let oxidation number of N be x

1 + x + (-2)3 = 0

x = +5

In NO2 , let oxidation number of N be x

x + (-2)2 = 0

x = +4

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0.6 = 600 / F
F = 1000 N

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Efficiency = (500 / 2000) x 100
Efficiency = 25%

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2 years ago

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Which element in period 4 would have chemical properties similar to magnesium? 7. which metalloids would have chemical propertie

azamat

The only solution you'll need to have for this problem is a periodic table. The columns in the table are called groups, and they are number from the left to the right starting with 1. The rows in the table are called periods which are numbered from the top to bottom starting with 1.

6. Elements that belong to the same group portray similar chemical properties. Therefore, the element in period 4 which is also in group 2 is Calcium (Ca).

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8. Tin has the chemical symbol of Sn. The nonmetal that is located in the same group is Carbon (C).

9. All the elements in period 6 would have similar properties. The answers could be: Phosphorus (P), Arsenic (As), Antimony (Sb) and Bismuth (Bi).

10. Period is row 1 and group 18 is the last column. The answer is Helium (He).

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2 years ago

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If 10.0 liters of h2(g) at STP is heated to a temperature of 546 K, pressure remaining constant, the new volume of the gas will

Effectus [21]

Answer:

20L

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 10L

Initial Temperature (T1) = stp = 273K

Final temperature (T2) = 546K

Final volume (V2) =..?

The new volume of the gas can be obtained by using the Charles' law equation as shown below:

V1/T1 = V2/T2

10/273 = V2/546

Cross multiply to express in linear form

273 x V2 = 10 x 546

Divide both side by 273

V2 = (10 x 546) / 273

V2 = 20L

Therefore, the new volume of the gas is 20L.

3 0

2 years ago

Barium oxalate is used as a colorant to produce the green color in fireworks. Imagine that you have been assigned to prepare bar

JulsSmile [24]

Answer:

2.1

Explanation:

Calculation of moles of $Ba(OH)_2.8H_2O$

Mass of copper = 5.3 g

Molar mass of copper = 315.46 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{5.3\ g}{315.46\ g/mol}$

Moles of $Ba(OH)_2.8H_2O$ = 0.0168 moles

According to the reaction,

$Ba(OH)_2.8H_2O + H_2C_2O_4.2H_2O\rightarrow BaC_2O_4 + 12 H_2O$

1 mole of $Ba(OH)_2.8H_2O$ react with 1 mole of $H_2C_2O_4.2H_2O$

0.0168 moles of $Ba(OH)_2.8H_2O$ react with 0.0168 moles of $H_2C_2O_4.2H_2O$

Moles of $H_2C_2O_4.2H_2O$ = 0.0168 moles

Molar mass of $H_2C_2O_4.2H_2O$ = 126.07 g/mol

Thus,

Mass = Moles * Molar mass = 0.0168 moles * 126.07 g/mol = 2.1 g

Answer - 2.1

5 0

2 years ago

A sample of vinegar was found to have an acetic acid concentration of 0.8846 m. What is the acetic acid % by mass? Assume the de

jenyasd209 [6]

Answer:

5.3%

Explanation:

Let the volume be 1 L

volume , V = 1 L

use:

number of mol,

n = Molarity * Volume

= 0.8846*1

= 0.8846 mol

Molar mass of CH3COOH,

MM = 2*MM(C) + 4*MM(H) + 2*MM(O)

= 2*12.01 + 4*1.008 + 2*16.0

= 60.052 g/mol

use:

mass of CH3COOH,

m = number of mol * molar mass

= 0.8846 mol * 60.05 g/mol

= 53.12 g

volume of solution = 1 L = 1000 mL

density of solution = 1.00 g/mL

Use:

mass of solution = density * volume

= 1.00 g/mL * 1000 mL

= 1000 g

Now use:

mass % of acetic acid = mass of acetic acid * 100 / mass of solution

= 53.12 * 100 / 1000

= 5.312 %

≅ 5.3%

3 0

2 years ago