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Studentka2010 [4]
1 year ago
15

Which response includes all of the following processes that are accompanied by an increase in entropy?

Chemistry
1 answer:
dlinn [17]1 year ago
7 0

Answer:

1 and 3.

Explanation:

The entropy measures the randomness of the system, as higher is it, as higher is the entropy. The randomness is associated with the movement and the arrangement of the molecules. Thus, if the molecules are moving faster and are more disorganized, the randomness is greater.

So, the entropy (S) of the phases increases by:

S solid < S liquid < S gases.

1. The substance is going from solid to gas, thus the entropy is increasing.

2. The substance is going from a disorganized way (the molecules of I are disorganized) to an organized way (the molecules join together to form I2), thus the entropy is decreasing.

3. The molecules go from an organized way (the atom are joined together) to a disorganized way, thus the entropy increases.

4. The ions are disorganized and react to form a more organized molecule, thus the entropy decreases.

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You were given the liters (.120L) 
Std pressure is 1 atmosphere 
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<span>Temp is 293.15 kelvin, thats standard </span>
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T<span>he charges themselves may not move fast, but the force upon them does. The electric field set up by the battery or generator propagates through the wires at the speed of light.

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Determine the compound type for the following formulas: C12H22011 Mg(OH)2 H20 Cu3Zn2 Au <br>​
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Answer:

C12H22O11  

✔ covalent

Mg(OH)2    

✔ Ionic

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Explanation:

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57.5 % is the percent yield if 10.9 g of H₃PO₄ is formed.

Explanation:

Balanced equation for the reaction:

Ca₃(PO₄)₂ (s) + 2H₂SO₄ (aq) → H₃PO₄ (aq) + 2CaSO₄ (aq)

data given:

mass of Ca₃(PO₄)₂ = 19.9 grams

mass of  H₂SO₄, = 54.3 grams

mass of H₃PO₄ produced = 10.9 grams (actual yield)

percent yield=?

atomic mass of Ca₃(PO₄)₂  = 310.17 grams/mole

atomic mass of H₂SO₄ = 98.07 grams/mole

number of moles is calculated as:

number of moles  = \frac{mass}{atomic mass of one mole}

putting the values in the above equation:

for Ca₃(PO₄)₂  = \frac{19.9}{310.17}

                        = 0.064 moles

moles of H₂SO₄ = \frac{54.3}{98.07}

                            = 0.55 moles

from the reaction, it can be found that the limiting reagent is Ca₃(PO₄)₂

1 mole of Ca₃(PO₄)₂ reacts to form 1 mole of phosphoric acid

0.064 moles of  Ca₃(PO₄)₂ will produce x moles of phosphoric acid

0.064 moles of phosphoric acid produced

mass = number of moles x atomic mass of  H3PO4

             =0.064 x 97.994

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FORMULA FOR PERCENT YIELD:

percent yield = \frac{actual yield}{theoretical yield} x 100

                      = \frac{6.27}{10.9} x 100

                       = 57.5 %

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