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2 years ago

Which response includes all of the following processes that are accompanied by an increase in entropy?

Chemistry

1 answer:

dlinn [17]2 years ago

7 0

Answer:

1 and 3.

Explanation:

The entropy measures the randomness of the system, as higher is it, as higher is the entropy. The randomness is associated with the movement and the arrangement of the molecules. Thus, if the molecules are moving faster and are more disorganized, the randomness is greater.

So, the entropy (S) of the phases increases by:

S solid < S liquid < S gases.

1. The substance is going from solid to gas, thus the entropy is increasing.

2. The substance is going from a disorganized way (the molecules of I are disorganized) to an organized way (the molecules join together to form I2), thus the entropy is decreasing.

3. The molecules go from an organized way (the atom are joined together) to a disorganized way, thus the entropy increases.

4. The ions are disorganized and react to form a more organized molecule, thus the entropy decreases.

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PLS HELP ASAP, WILL GIVE 100 POINTS.

Ivan

Answer: values of the quantum numbers: -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6

location of the electron: In the 7th energy level away from the nucleus.

Explanation:

From the description of the problem, the magnetic number is given is as -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6 and the electron is located in the 7th energy level away from the nucleus. Basically, the problem is testing for the understanding of the principal quantum numbers which gives the location of electrons and the magnetic quantum number that shows the spatial orientation of the orbitals.

The orbital designation of the describe electron is 7d

Magnetic quantum number is limited by the azimuthal quantum number which is the quantum number describing the possible shapes. The azimuthal is given as L= n-1. "n" is the principal quantum number which is 7. Therefore L is 6 and the magnetic quantum numbers are -6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6

The position of the electron is given by the principal quantum number which represents the main energy level in which the orbital is located or the average distance from the nucleus.

Got it from quasarJose

Hope it helps

5 0

2 years ago

Electrons in __________ bonds remain localized between two atoms. electrons in __________ bonds can become delocalized between m

dsp73

Electrons in sigma bonds remain localized between two atoms. Sigma bond results from the formation of a molecular orbital by the end to end overlap of atomic orbitals. Electrons in pi bonds can become delocalized between more than two atoms. Pi bonds result from the formation of molecular orbital by side to side overlap of atomic orbitals.

7 0

2 years ago

Which sentences describe alpha particles? Check all that apply 1. Alpha particles consist of two protons and two neutrons 2. Alp

Masja [62]

thanks for the answers ッ. (btw they’re on the bottom of the question if anyone doesn’t see it.

4 0

2 years ago

Read 2 more answers

What is the concentration of Iodine I2 molecules in a solution containing 2.54 g of iodine 250 cm3 of solution? A 0.01mol/dm3 B

gulaghasi [49]

Answer:

C. 0.04 moles per cubic decimeter.

Explanation:

The molar mass of the Iodine is 253.809 grams per mole and a cubic decimeter equals 1000 cubic centimeters. The concentration of Iodine ( $c$ ), measured in moles per cubic decimeter, can be determined by the following formula:

$c = \frac{m}{M\cdot V}$ (1)

Where:

$m$ - Mass of iodine, measured in grams.

$M$ - Molar mass of iodine, measured in grams per mol.

$V$ - Volume of solution, measured in cubic decimeters.

If we know that $m = 2.54\,g$ , $M = 253.809\,\frac{g}{mol}$ and $V = 0.25\,dm^{3}$ , then the concentration of iodine in a solution is:

$c = \frac{2.54\,g}{\left(253.809\,\frac{g}{mol} \right)\cdot (0.25\,dm^{3})}$

$c = 0.04\,\frac{mol}{dm^{3}}$

Hence, the correct answer is C.

3 0

2 years ago

When 200g of AgNO3 solution mixes with 150 g of NaI solution, 2.93 g of AgI precipitates, and the temperature of the solution ri

gizmo_the_mogwai [7]

Answer:

$\Delta H=1962.3J$

Explanation:

Hello,

In this case, we can compute the change in the solution enthalpy by using the following formula:

$\Delta H=mC\Delta T$

Whereas the mass of the solution is 350 g, the specific heat capacity is 4.184 J/g °C and the change in the temperature is 1.34 °C, therefore, we obtain:

$\Delta H=350g*4.184\frac{J}{g\°C} *1.34\°C\\\\\Delta H=1962.3J$

It is important to notice that the mass is just 350 g that is the reacting amount and by means of the law of the conservation of mass, the total mass will remain constant, for that reason we compute the change in the enthalpy as shown above, which is positive due to the temperature raise.

Best regards.

8 0

2 years ago