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vekshin1
2 years ago
14

For each reaction, identify the precipitate, or lack thereof. 2nacl(aq)+ba(oh)2(aq)⟶bacl2+2naoh naoh bacl2 no precipitate agclo3

(aq)+mgi2(aq)⟶agi+mg(clo3)2
Chemistry
2 answers:
Marat540 [252]2 years ago
8 0

\boxed{{\text{No precipitate will be formed}}} in 2{\text{NaCl}} + {\text{Ba}}{\left( {{\text{OH}}} \right)_2} \to {\text{BaC}}{{\text{l}}_2} + 2{\text{NaOH}}

\boxed{{\text{AgI}}} is the precipitate formed in {\text{AgCl}}{{\text{O}}_3} + {\text{Mg}}{{\text{I}}_2} \to {\text{AgI}} + {\text{Mg}}{\left( {{\text{Cl}}{{\text{O}}_3}} \right)_2}

Further Explanation:

<u>Precipitation reaction: </u>

It is the type of reaction in which an<em> insoluble salt</em> is formed by the combination of two solutions containing soluble salts. That insoluble salt is known as <em>precipitate </em>and therefore such reactions are named precipitation reactions. An example of precipitation reaction is,

{\text{AgN}}{{\text{O}}_3}\left( {aq} \right) + {\text{KBr}}\left( {aq} \right) \to {\text{AgBr}}\left( s \right) + {\text{KN}}{{\text{O}}_3}\left( {aq} \right)

Here, AgBr is a precipitate.

The solubility rules to determine the solubility of the compound are as follows:  

1. The common compounds of group 1A are soluble.

2. All the common compounds of ammonium ion and all acetates, chlorides, nitrates, bromides, iodides, and perchlorates are soluble in nature. Only the chlorides, bromides, and iodides of {\text{A}}{{\text{g}}^ + }, {\text{P}}{{\text{b}}^{2 + }}, {\text{C}}{{\text{u}}^ + } and {\text{Hg}}_2^{2 + } are not soluble.

3. All common fluorides, except for {\text{Pb}}{{\text{F}}_{\text{2}}} and group 2A fluorides, are soluble. Moreover, sulfates except {\text{CaS}}{{\text{O}}_{\text{4}}}, {\text{SrS}}{{\text{O}}_{\text{4}}},  {\text{BaS}}{{\text{O}}_{\text{4}}}, {\text{A}}{{\text{g}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}} and {\text{PbS}}{{\text{O}}_{\text{4}}} are soluble.

4. All common metal hydroxides except {\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}, {\text{Sr}}{\left( {{\text{OH}}} \right)_{\text{2}}}, {\text{Ba}}{\left( {{\text{OH}}} \right)_{\text{2}}} and hydroxides of group 1A, are insoluble.

5. All carbonates and phosphates, except those formed by group 1A and ammonium ion, are insoluble.

6. All sulfides, except those formed by group 1A, 2A, and ammonium ion are insoluble.

7. Salts that contain {\text{C}}{{\text{l}}^ - }, {\text{B}}{{\text{r}}^ - } or {{\text{I}}^ - } are usually soluble except for the halide salts of {\text{A}}{{\text{g}}^ + }, {\text{P}}{{\text{b}}^{2 + }} and {\left( {{\text{H}}{{\text{g}}_2}} \right)^{{\text{2 + }}}}.

8. The chlorides, bromides, and iodides of all the metals are soluble in water, except for silver, lead, and mercury (II). Mercury (II) iodide is water insoluble. Lead halides are soluble in hot water.

9. The perchlorates of group 1A and group 2A are soluble in nature.

(1) The given reaction is as follows:

 2{\text{NaCl}} + {\text{Ba}}{\left( {{\text{OH}}} \right)_2} \to {\text{BaC}}{{\text{l}}_2} + 2{\text{NaOH}}

This is an example of a double displacement reaction in which two ionic compounds are exchanged with each other and two new compounds are formed. {\text{BaC}}{{\text{l}}_2} and NaOH are soluble salts according to the solubility rules. So no precipitate will be formed in this reaction.

(2) The given reaction is as follows:

 {\text{AgCl}}{{\text{O}}_3} + {\text{Mg}}{{\text{I}}_2} \to {\text{AgI}} + {\text{Mg}}{\left( {{\text{Cl}}{{\text{O}}_3}} \right)_2}

According to the solubility rules, AgI is an insoluble salt. The perchlorates of group 2 are soluble in nature and therefore {\text{Mg}}{\left( {{\text{Cl}}{{\text{O}}_3}} \right)_2} is soluble in water. So AgI forms the precipitate in the above reaction.

Learn more:

1. Balanced chemical equation brainly.com/question/1405182

2. The mass of ethylene glycol: brainly.com/question/4053884

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: precipitation reaction, precipitate, insoluble, soluble, AgI, AgClO3, Mg(ClO3)2, MgI2, NaCl, Ba(OH)2, BaCl2, NaOH, solubility rules, halides, sulfides.

Paha777 [63]2 years ago
7 0
1) Answer is: <span>no precipitate.
</span>Chemical reaction: 2NaCl + Ba(OH)₂ → BaCl₂ + 2NaOH.
Barium chloride is salt that dissolves in water, sodium hydroxide is strong base that dissolves in water. This is example of double replacement reactions(double displacement or metathesis reactions)<span>, two ionic compounds are exchanged, making two new compounds.</span>

2) Answer is: AgI.
Chemical reaction: 2AgClO₃ + MgI₂ → 2AgI + Mg(ClO₃)₂.
Silver chloride form yellow precipipate, magnesium chlorate is salt that dissolves in water. This is also example of double replacement, Mafnesium has oxidation number +2 and siilver has oxidation number +1, iodine has -1 and chlorate also -1.

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a scientists finds an organism that cannot move. it has many cells, produces spores, and gets food from its environment. in whic
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The correct answer is : The Organism belongs in Kingdom Fungi


The explanation:


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3 0
2 years ago
Which response includes all of the following processes that are accompanied by an increase in entropy?
dlinn [17]

Answer:

1 and 3.

Explanation:

The entropy measures the randomness of the system, as higher is it, as higher is the entropy. The randomness is associated with the movement and the arrangement of the molecules. Thus, if the molecules are moving faster and are more disorganized, the randomness is greater.

So, the entropy (S) of the phases increases by:

S solid < S liquid < S gases.

1. The substance is going from solid to gas, thus the entropy is increasing.

2. The substance is going from a disorganized way (the molecules of I are disorganized) to an organized way (the molecules join together to form I2), thus the entropy is decreasing.

3. The molecules go from an organized way (the atom are joined together) to a disorganized way, thus the entropy increases.

4. The ions are disorganized and react to form a more organized molecule, thus the entropy decreases.

7 0
2 years ago
A NiCd battery uses nickel and cadmium to produce a potential difference. Using these equations, answer the following questions.
Dahasolnce [82]

Answer : The correct chemical reaction within the galvanic cell is,

(3) Cd(s)+2NiO(OH)(s)+2H_2O(l)\rightarrow 2Ni(OH)_2(s)+Cd(OH)_2(s)

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Galvanic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the electrochemical cell.

The redox reaction occurs between the nickel and cadmium.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

The balanced two-half reactions will be,

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Thus the overall reaction will be,

Cd(s)+2NiO(OH)(s)+2H_2O(l)\rightarrow 2Ni(OH)_2(s)+Cd(OH)_2(s)

6 0
2 years ago
Scientists tracking a flock of ducks found that, on average, the ducks flew 740 km south in 12 hours. What were the speed and ve
Verizon [17]

1) 17.1 m/s

2) 17.1 m/s south

Explanation:

1)

The speed of an object is a scalar quantity indicating "how fast" is the object moving, regardless of its direction of motion.

Being a scalar quantity, it has only a magnitude, while it doesn't have a direction.

The speed of an object is given by the formula:

v=\frac{d}{t}

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d is the distance covered by the object, which is the total length of the path covered by the object

t is the time taken to cover the distance d

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d=740 km =740,000 m is the distance covered by the ducks

t=12 h  \cdot 60 \cdot 60 =43,200 s is the time taken

Substituting, we find:

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2)

The velocity of an object is a vector quantity indicating how fast the object is moving in a certain direction.

Being a vector, velocity has both a magnitude and a direction.

The magnitude of the velocity is given by:

v=\frac{d}{t}

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t is the time taken for the displacement d to occur

And the direction is equal to the direction of the displacement.

In this problem:

d=740 km = 740,000 m south is the displacement

t=12 h  \cdot 60 \cdot 60 =43,200 s is the time taken

Substituting, we find:

v=\frac{740,000}{43,200}=17.1 m/s south

5 0
2 years ago
What is the mass, in grams, of 6.33 mol of nahco3?
zhuklara [117]
1 mole of NaHCO3 contains 84.007g,
Therefore,to get the number of mass of 6.33 mol we multiply the number of moles and the relative formula mass.
That is; 6.33 moles × 84.007 g =  531.764 g
Hence the mass of 6.33 moles of NaHCO3 is 531.764 grams
6 0
2 years ago
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