How many degrees of unsaturation are lost or gained in the base-induced transformation from mito-ph to its photoactive ring-open
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Answer:
The anode half reaction is :
Explanation:
In electrochemical cell, oxidation occurs in anode and reduction occurs in cathode.
In oxidation, electrons are being released by a species. In reduction, electrons are being consumed by a species.
We can split the given cell reaction into two half-cell reaction such as-
Oxidation (anode):
Reduction (cathode):
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overall:
So the anode half reaction is :
Explanation:
The given reaction equation will be as follows.
Now, number of atoms on reactant side are as follows.
- H = 2
- S = 1
- O = 3
Number of atoms on product side are as follows.
- H = 2
- S = 1
- O = 3
Therefore, this equation is balanced since atoms on both reactant and product sides are equal.
Thus, we can conclude that there is one sulfur atom in the products.