In 200 g of a concentrated solution of 70.4 wt% nitric acid (r = 1.41 g/mL, FW(HNO3) = 63.01 g/mol), how many grams of water are
1 answer:
Answer:
59.2 grams
Explanation:
We are given that 70.4% of the weight of the total 200 g of the concentration is made up of nitric acid, the remaining information is not required to solve the problem. Since water and nitric acid are the only components of the solution, the total weight of water is given by:
There are 59.2 grams of water in this solution.
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Answer:
Yes
Explanation:
1. Mass of 0.60 mol of AuCl₃
2. Mass of AuCl₃ in 750 mL
The solubility of AuCl₃ is 68 g/100 mL.
In 750 mL of water, you can dissolve
∴ Yes, 750 mL of water can dissolve 0.60 mol of AuCl₃.
Explanation:
The given reaction equation will be as follows.
Now, number of atoms on reactant side are as follows.
- H = 2
- S = 1
- O = 3
Number of atoms on product side are as follows.
- H = 2
- S = 1
- O = 3
Therefore, this equation is balanced since atoms on both reactant and product sides are equal.
Thus, we can conclude that there is one sulfur atom in the products.