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wlad13 [49]
1 year ago
13

What would the % p, on the npk ratio, be reported as for a 100g sample containing 7.5g of phosphorous?

Chemistry
2 answers:
kati45 [8]1 year ago
6 0
When the concentration is expressed in percentage, you simply have to divide the amount of substance to the total amount of the mixture, then multiply it by 100. In this case, when you want to find the percentage of P in the sample, the solution is as follows:

%P = 7.5 g/100 g * 100 =<em> 7.5%</em>
pshichka [43]1 year ago
6 0

<u>Ans: 7.50% of P</u>

<u></u>

<u>Given:</u>

Mass of NPK sample = 100 g

Mass of P in sample = 7.5 g

<u>To determine:</u>

The % P in the given sample

<u>Explanation:</u>

The percent of a particular substance (say,X) in a given total amount (M) is generally expressed as:

<u>% X = [Mass of X/Total mass]*100</u>

In this case:

%P = [mass of P/mass of NPK sample]*100

    = [7.5/100]*100 = 7.5%

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Answer:

a. 123.9°C

b.

c.

Explanation:

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a. Since the steam is overheated vapour, the specific volume is gotten from the corresponding table. Then, as it became a saturated vapour, we look for the interval in which the same volume of state 1 is, then we interpolate and get the temperature.

b. Now, at 80°C, since it is about a rigid tank (constant volume for every thermodynamic process), the specific volume of the mixture is 0.79645 m^3/kg as well, so the specific volume for the liquid and the vapour are taken into account to get the quality of 0.234.

c. Now,since this is an isocoric process, the heat transfer per kg of steam is computed as the difference in the internal energy, considering the initial condition (showed in a. part) and the final one computed here.

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2 years ago
Magnesium burns in air with a dazzling brilliance to produce magnesium oxide: 2Mg (s) + O2 (g) →→ 2MgO (s) When 4.50 g of magnes
Klio2033 [76]

Answer:

7.46 g

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6 0
2 years ago
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2 years ago
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2 years ago
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