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2 years ago

For the n = 3 electron shell, which of the following quantum numbers are valid? Check all that apply.

Chemistry

2 answers:

stealth61 [152]2 years ago

7 0

Answer:

The valid quantum numbers are l=0, l=-2 and l= 2.

Explanation:

Given that,

n = 3 electron shell

Suppose, the valid quantum numbers are

l = 3

m = 3

l = 0

m = –2

l = –1

m = 2

We know that,

The value of n = 3

Principle quantum number :

Then the principal quantum number is 3. Which is shows the M shell.

So, n = 3

Azimuthal quantum number :

The azimuthal quantum number is l.

$l=0,1,2$

Magnetic quantum number :

The magnetic quantum number is

$m=-2,-1,0,1,2$

Hence, The valid quantum numbers are l=0, l=-2 and l= 2.

Ymorist [56]2 years ago

3 0

Answer: I = 0 m = -2 m = 2

Explanation: Edge.

the correct answers to the second part of this are:

n = 1, I = 0, m = 0

n = 3, I = 0, m = 0

n = 5, I = 4, m = -3

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Identify the most and the least acidic compound in each of the following sets.

il63 [147K]

Answer:

See explanation

Explanation:

Our answer options for this question are:

a. 2-chlorobutanoic acid:_______ 2-chlorobutanoic acid:_______ 3-chlorobutanoic acid:______.

b. 2,4-dinitrobenzoic acid:______ p-nitrobenzoic acid:______ p-bromobenzoic acid:_______.

c. p-cyanobenzoic acid:________ benzoic acid:_______ p-aminobenzoic acid:______

We have to check each set of molecules

a. 2-chlorobutanoic acid, 3-chlorobutanoic acid

In this case, the difference between these molecules is the position of "Cl". If the chlorine atom is closer to the acid group, we will have a higher inductive effect. So, the bond O-H would be weaker and we will have more acidity. So, the molecule with more acidity is 2-chlorobutanoic acid and the less acidic would be 3-chlorobutanoic acid.

b. 2,4-dinitrobenzoic acid, p-nitrobenzoic acid, p-bromobenzoic acid

In this case, we have several structural differences. In all the structure, we have deactivating groups ( $Br$ and $NO_2$ ). If we have a deactivating group the acidity will increase. In the case of "Br", we have a weak deactivating, so, this will be the less acidic one (p-bromobenzoic acid)

in 2,4-dinitrobenzoic acid we have two deactivating groups, therefore, this would be the most acid compound.

c. p-cyanobenzoic acid, benzoic acid, p-aminobenzoic acid

On these molecules, we have several structural differences. In p-cyanobenzoic acid we have a deactivating group, therefore in this molecule we will have more acidity. In the p-aminobenzoic acid, we have an activating group, so, this would be the less acidic compound.

See figure 1

I hope it helps!

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