answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Grace [21]
2 years ago
14

For the n = 3 electron shell, which of the following quantum numbers are valid? Check all that apply.

Chemistry
2 answers:
stealth61 [152]2 years ago
7 0

Answer:

The valid quantum numbers are l=0, l=-2 and l= 2.

Explanation:

Given that,

n = 3 electron shell

Suppose, the valid quantum numbers are

l = 3

m = 3

l = 0

m = –2

l = –1

m = 2

We know that,

The value of n = 3

Principle quantum number :

Then the principal quantum number is 3. Which is shows the M shell.

So, n = 3

Azimuthal quantum number :

The azimuthal quantum number is l.

l=0,1,2

Magnetic quantum number :

The magnetic quantum number is

m=-2,-1,0,1,2

Hence, The valid quantum numbers are l=0, l=-2 and l= 2.

Ymorist [56]2 years ago
3 0

Answer: I = 0  m = -2 m = 2

Explanation: Edge.

the correct answers to the second part of this are:

n = 1, I = 0, m = 0

n = 3, I = 0, m = 0

n = 5, I = 4, m = -3

You might be interested in
The reading on a speedometer represents the average velocity of the car. True False
Sedbober [7]
Answer: False. Hope this helps!!
7 0
2 years ago
Consider a process in which the entropy of a system increases by 125 J K−1 and the entropy of the surroundings decreases by 125
expeople1 [14]

Answer : The process is not spontaneous.

Explanation :

As, we know that:

Change in entropy = Change in entropy of system + Change in entropy of surrounding

As we are given in question, the entropy of surroundings decrease by the same amount as the entropy of the system increases.

For the given reaction to be spontaneous, the total change in entropy should be positive.

Given :

Entropy change of system = +125J/K

Entropy change of surroundings = -125J/K

Total change in entropy = Entropy change of system + Entropy change of surroundings

Total change in entropy = 125 J/K + (-125 J/K)

Total change in entropy = 0

The process is at equilibrium because the entropy change is equal to zero. So, the process is not spontaneous.

4 0
2 years ago
Before raw data can be used as scientific evidence, it must be analyzed and summarized. One way of summarizing data is to find t
Nikitich [7]
The mean is simply the arithmetic average of all your raw data. This can be solved methodically by summing up all of the raw data points that you have. Take note how many raw data points you used, because this will be used to divide the sum. You will obtain the mean.
6 0
2 years ago
In the formula X2O5, the symbol X could represent an element in Group
topjm [15]

Answer: (3) 15

Explanation: We criss-cross down the oxidation numbers to get the subscripts for the correct formulas. That means the X has an oxidation number of 5. The element with the + oxidation number is always written first so it is +5. Of the groups names, only group 15 has +5 as an oxidation number.

6 0
2 years ago
Consider the following reactions and their respective equilibrium constants: NO(g)+12Br2(g)⇌NOBr(g)Kp=5.3 2NO(g)⇌N2(g)+O2(g)Kp=2
maxonik [38]

Answer:

Equilibrium constant of the given reaction is 1.3\times 10^{-29}

Explanation:

NO+\frac{1}{2}Br_{2}\rightleftharpoons NOBr....(K_{p})_{1}=5.3

2NO\rightleftharpoons N_{2}+O_{2}....(K_{p})_{2}=2.1\times 10^{30}

The given reaction can be written as summation of the following reaction-

2NO+Br_{2}\rightleftharpoons 2NOBr

N_{2}+O_{2}\rightleftharpoons 2NO

......................................................................................

N_{2}+O_{2}+Br_{2}\rightleftharpoons 2NOBr

Equilibrium constant of this reaction is given as-

\frac{[NOBr]^{2}}{[N_{2}][O_{2}][Br_{2}]}

=(\frac{[NOBr]}{[NO][Br_{2}]^{\frac{1}{2}}})^{2}(\frac{[NO]^{2}}{[N_{2}][O_{2}]})

=\frac{(K_{p})_{1}^{2}}{(K_{p})_{2}}

=\frac{(5.3)^{2}}{2.1\times 10^{30}}=1.3\times 10^{-29}

7 0
2 years ago
Read 2 more answers
Other questions:
  • if 5 moles of P4 reacted with 22 moles Cl2 according to the above reaction, determine:How many moles PCl3 are produced
    14·1 answer
  • A biology student wants to conduct a study of how the amount of food affects weight gain for mice. He sets up four cages with a
    12·1 answer
  • a compound is found to have 46.67% nitrogen, 6.70% hydrogen, 19.98% carbon and 26.65% oxygen, what is the empirical formula?
    15·1 answer
  • If a dozen clementine oranges have a mass of 744g, what will be the mass of 15 Clementines?
    5·2 answers
  • Gasoline has a density of 0.749 g/mL. There are 454 grams in a pound and 3.7854 litres in a gallon. How many pounds does 19.2 ga
    15·1 answer
  • Robyn has been working on developing a new task to test the reaction time of athletes. As she begins to test athletes using her
    8·1 answer
  • The flask contains 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.160 M NaOH . It requires 11
    13·2 answers
  • Why did hurricane Katrina slow down at data point 7 ?
    5·1 answer
  • Consider these generic half-reactions. Half-reaction E° (V) X+(aq)+e−⟶X(s) 1.52 Y2+(aq)+2e−⟶Y(s) −1.17 Z3+(aq)+3e−⟶Z(s) 0.84 Ide
    8·1 answer
  • Calculate the number of total atoms in 195 grams of Ni(OH)2. Use 6.022x10^23mol-1 for Avogadro’a number
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!