All categories

2 years ago

What happens when Ammonia reacts with zinc sulphate solution

1 answer:

3 0

It will form a tetraamminezinc sulphate and a blue solution will be formed...the reaction should be carried out in a fume chamber because a poisonous substance will be released to the atmosphere

You might be interested in

Write a hypothesis for Section 2 of the lab, which is about the effect of the angle of insolation on the amount of heat a materi

m_a_m_a [10]

Answer:

If the angle of insolation is higher, then the temperature of the soil will be higher because it will receive more direct light.

Explanation:

5 0

2 years ago

Why are salt and sugar both able to dissolve in water, even though the solutes have different types of chemical bonding?

Rama09 [41]

Answer:

ions are surrounded by hydrogen ends with positive partial charge. In this way the salt is dissolved in water. Sugar is a molecular compound formed by covalent bonds. In a polar covalent bond, electrons are shared unevenly

Explanation:

5 0

2 years ago

An unknown compound with a molar mass of 155.06 g/mol consists of 46.47% c, 7.80% h, and 45.72% cl. find the molecular formula f

Contact [7]

Answer:- Molecular formula of the compound is $C_6H_1_2Cl_2$ .

Solution:- From given information:

C = 46.47%

H = 7.80%

Cl = 45.72%

First of all we find out the empirical formula from given percentages. We divide the given percentages by their respective atomic masses to calculate the moles:

$C=\frac{46.47}{12.01}$ = 3.87

$H=\frac{7.80}{1.01}$ = 7.72

$Cl=\frac{45.72}{35.45}$ = 1.29

Now, we divide the moles of each by the least one of them. Least one is Cl as it's moles are least as compared to the moles of C and H. So, let's divide the moles of each by 1.29.

$C=\frac{3.87}{1.29}$ = 3

$H=\frac{7.72}{1.29}$ = 6

$Cl=\frac{1.29}{1.29}$ = 1

So, the empirical formula of the compound is $C_3H_6Cl$ .

Empirical formula mass = 3(12.01) + 6(1.01) + 1(35.45)

= 36.03 + 6.06 + 35.45

= 77.54

To calculate the number of formula units we divide molar mass by empirical formula mass.

number of empirical formula units = $\frac{155.06}{77.54}$

= 2

So, the molecular formula would be two times of empirical formula that is, $C_6H_1_2Cl_2$ .

4 0

2 years ago

Read 2 more answers

Identify the oxidizing agent and the reducing agent in the following reactions: (i) 8NH3( g) + 6NO2( g) => 7N2( g) + 12H2O( l

shusha [124]

Answer:

(i) Oxidizing Agent: NO2 / Reducing Agent NH3-

(ii) Oxidizing Agent AgNO3 / Reducing Agent Zn

Explanation:

(i) 8NH3( g) + 6NO2( g) => 7N2( g) + 12H2O( l)

In this reaction, both two reactants contain nitrogen with a different oxidation number and produce only one product which contains nitrogen with a unique oxidation state. So, nitrogen is oxidized and reduced in the same reaction.

Nitrogen Undergoes a change in oxidation state from 4+ in NO2 to 0 in N2. It is reduced because it gains electrons (decrease its oxidation state). NO2 is the oxidizing agent (electron acceptor).

Nitrogen Changes from an oxidation state of 3- in NH3 to 0 in N2. It is oxidized because it loses electrons (increase its oxidation state). NH3 is the reducing agent (electron donor)

(ii) Zn(s) +AgNO3(aq) => Zn(NO3)2(aq) + Ag(s)

Ag changes oxidation state from 1+ to 0 in Ag(s).

Ag is reduced because it gains electrons and for this reason and AgNO3 is the oxidizing agent (electron acceptor)

Zn Changes from an oxidation state of 0 in Zn(s) to 2+ in Zn(NO3)2. It is oxidized and for this reason Zn is the reducing agent (electron donor).

Balanced equation:

Zn(s) +2AgNO3(aq) => Zn(NO3)2(aq) + 2Ag(s)

4 0

2 years ago

Which chemical reaction involves the fewest oxygen atoms?

Free_Kalibri [48]

Answer:

4Fe+ 6H2 O+ 3O2 ----> 4Fe(OH)3

5 0

1 year ago