The simplified solubility of glucose at 30°C is 1.25 g/g of water. Considering that the density of water at 30°C is 1 g/mL, the equivalent mass of 400 mL of water is also 400g.
The concentration of the solution in water is,
550 g/400g of water = 1.375 g glucose / g of water
Since the concentration is higher compared to the solubility of glucose at the specified temperature, it can be said that the solution is SATURATED.
F = ma = (kg)(m/s2) = kg ´ m/s2 N
hope this helps :D
The temperature will change from 100K to 173.87 K
calculation
by use of law that is V1/T1=V2/T2
V1=3.75 L
T1=100k
V2=6.53 L
T2=?
make T2 the subject of the formula
T2=(V2 xT1)V1
=6.52 x100/3.75=173.87K
Answer:
Fe is the anode and Sn is the cathode; NO3- ions flow into half-cell compartment (A) and Na ions flow into half-cell compartment (B).
Explanation:
The purpose of a salt bridge in a voltaic cell is not to move electrons from the electrolyte, it's main function is the maintenance of charge balance between the half cells .The electrons flow from the anode to the cathode.
The iron half cell which has a higher reduction potential serves as anode. Iron atoms give up electrons to form positive ions according to the equation;
Fe(s)-----> Fe^2+(aq) + 2e
Hence there will be an excess of positive ions in the anode (compartment A). NO3^- ions from the salt bridge will migrate towards this compartment to ensure charge balance.
Similarly, in compartment B(cathode) Sn^2+ ions will accept two electrons according to the reaction;
Sn^2+(aq) + 2e ------> Sn(s)
This reaction causes a depletion of positive ions in compartment B, hence Na^+ from the salt bridge move towards this compartment to ensure charge balance.
