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Iteru [2.4K]
2 years ago
8

What is the percent composition of hydrogen in a compound if the mass of the initial compound is 276 grams and the mass of colle

cted hydrogen after decomposition is 41.4 grams?
Chemistry
2 answers:
Sliva [168]2 years ago
5 0

Answer : The percent composition of hydrogen in a compound is, 15%

Solution : Given,

The mass of compound = 276 grams

The mass of collected hydrogen after decomposition = 41.4 grams

Formula used :

\%\text{ composition of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of compound}}\times 100

Now put all the given values in this formula, we get the percent composition of hydrogen.

\%\text{ composition of hydrogen}=\frac{41.4g}{276g}\times 100=15\%

Therefore, the percent composition of hydrogen in a compound is, 15%

SVEN [57.7K]2 years ago
5 0
I think it is 20.11%
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Water flows over Niagara Falss at the average rate of 2,400,000 kg/s, and the average height of the falls is about 50 m. Knowing
liberstina [14]

Answer:

1. 176 × 10^12 W ; 78400000000

Explanation:

Given the following :

Fall rate = 2,400,000kg/s

Average height of fall = 50m

Gravitational Potential of falling water = mgh = mass × acceleration due to gravity × height =

How many 15 W LED light bulbs could it power?

Recall : power = workdone / time

Workdone = gravitational potential energy

Mass of water = density * volume

Density of water = 1 * 10^3kg/m^3

Rate of fow = volume / time = 2400000

Hence,

Power = 1000 * 2,400,000 * 9.8 * 50

Power = 1176000000000

Power = 1. 176 × 10^12 W

How many 15 W LED light bulbs could it power?

1176000000000 / 15 = 78400000000

= 78400000000 15 W bulbs

4 0
2 years ago
A 500 mL sample of a 0.100 M formate buffer, pH 3.75, is treated with 5 mL of 1.00 M KOH. What is the pH following this addition
lubasha [3.4K]

<u>Answer:</u> The pH of the solution after addition of KOH is 3.84

<u>Explanation:</u>

We are given:

pH of buffer = 3.75

pK_a of formic acid = 3.75

Using Henderson-Hasselbalch equation for formate buffer:

pH=pK_a+\log(\frac{[HCOO-]}{[HCOOH]})

Putting values in above equation, we get:

3.75=3.75+\log(\frac{[HCOO-]}{[HCOOH]})\\\\\log(\frac{[HCOO-]}{[HCOOH]})=0\\\\\frac{[HCOO-]}{[HCOOH]}=1

[HCOO-]=[HCOOH]

We are given:

Concentration of formate buffer = 0.100 M

[HCOO-]+[HCOOH]=0.1

[HCOO-]=[HCOOH]=0.05M

As, the volume of buffer is the same. So, the concentration is taken as number of moles of formate ions as well as formic acid

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

Molarity of KOH = 1.00 M

Volume of solution = 5 mL

Putting values in above equation, we get:

1.00M=\frac{\text{Moles of KOH}\times 1000}{5mL}\\\\\text{Moles of KOH}=0.005mol

The chemical reaction for formic acid and KOH follows the equation:

                  HCOOH+KOH\rightarrow HCOO^-+H_2O

Initial:       0.05    0.005               0.05

Final:         0.045          -                0.055          

Volume of solution = 500 + 5 = 505 mL = 0.505 L    (Conversion factor:  1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[salt]}{[acid]})

pH=pK_a+\log(\frac{[HCOO^-]}{[HCOOH]})

We are given:

pK_a = negative logarithm of acid dissociation constant of formic acid = 3.75

[HCOO^-]=\frac{0.055}{0.505}

[HCOOH]=\frac{0.045}{0.505}

pH = ?

Putting values in above equation, we get:

pH=3.75+\log(\frac{0.055/0.505}{0.045/0.505})\\\\pH=3.84

Hence, the pH of the solution after addition of KOH is 3.84

3 0
2 years ago
in order to find the molar mass of an unknown compound, a research scientist prepared a solution of 0.930 g of an unknown in 125
PtichkaEL [24]

Answer:

Molar mass→ 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

Explanation:

Let's apply the formula for freezing point depression:

ΔT = Kf . m

ΔT = 74.2°C - 73.4°C → 0.8°C

Difference between the freezing T° of pure solvent and freezing T° of solution

Kf = Cryoscopic constant → 5.5°C/m

So, if we replace in the formula

ΔT = Kf . m → ΔT / Kf = m

0.8°C / 5.5 m/°C = m → 0.0516 mol/kg

These are the moles in 1 kg of solvent so let's find out the moles in our mass of solvent which is 0.125 kg

0.0516 mol/kg . 0.125 kg = 6.45×10⁻³ moles. Now we can determine the molar mass:

Molar mass (mol/kg) → 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol

3 0
2 years ago
For which of the following properties does sodium have a larger value than rubidium? Select all that apply.
Doss [256]

Answer:

Ionization energy

Electronegativity

Explanation:

-due to its smaller ionic radius....the electron in the outter most shell tends to expierence a stronger nuclear attraction...which makes it harder to remove the electron from the sodium atom

-Rubidium has lesser ionization energy because its (i) affected by its larger ionic radius which tends to lessen the nuclear attraction ...hence making it easier to remove the electron...(ii)and also by the screening effect done by the inner shells, which also tends to lessen the nuclear attraction.

Sodium has a higher electronegativity than rubidium;

Electronegativity is the charge density of electrons in an atom...in which its high when the atomic radius is smaller...

So hence due to the sodium atomic radius being smaller...it tends to have a higher charge density than rubidium....which then gives it a higher electronegativity value

4 0
2 years ago
Check my answers please? 1. Which of the following is a correctly written thermochemical equation? NH4Cl NH4+ + Cl 2C8H18 + 25O2
snow_tiger [21]
1. I think you chose the right answer, the equation has the states of the reactants and products. 2. I think you chose the right answer. 3. I think you also chose the right answer. Assuming that the Hrxn is written as kJ per mol CH4 4. Heat of solution is the enthalpy change associated with dissolving a solute in a solvent. I think the first choice is the right one. 5. I think you chose the right answer.
4 0
1 year ago
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