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Iteru [2.4K]
2 years ago
8

What is the percent composition of hydrogen in a compound if the mass of the initial compound is 276 grams and the mass of colle

cted hydrogen after decomposition is 41.4 grams?
Chemistry
2 answers:
Sliva [168]2 years ago
5 0

Answer : The percent composition of hydrogen in a compound is, 15%

Solution : Given,

The mass of compound = 276 grams

The mass of collected hydrogen after decomposition = 41.4 grams

Formula used :

\%\text{ composition of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of compound}}\times 100

Now put all the given values in this formula, we get the percent composition of hydrogen.

\%\text{ composition of hydrogen}=\frac{41.4g}{276g}\times 100=15\%

Therefore, the percent composition of hydrogen in a compound is, 15%

SVEN [57.7K]2 years ago
5 0
I think it is 20.11%
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The recommended daily intake of potassium ( K ) is 4.725 g . The average raisin contains 3.513 mg K . Fill in the denominators o
kondor19780726 [428]

Explanation:

It is known that 1 gram contains 1000 milligrams. And, mathematically we can represent it as follows.

             \frac{1 g}{1000 mg} or \frac{1000 mg}{1 g}

So, when we have to convert grams into milligrams then we simply multiply the digit with 1000. And, if we have to convert a digit from milligrams to grams then we simply divide it by 1000.

4 0
2 years ago
By mistake, a quart of oil was dumped into a swimming pool that measures 25.0 m by 30.0 m. The density of the oil was 0.750 g/cm
kondor19780726 [428]

The oil slick thick = 1.256 x 10⁻⁴ cm

<h3>Further explanation</h3>

Volume is a derivative quantity derived from the length of the principal

The unit of volume can be expressed in liters or milliliters or cubic meters

The conversion is

1 cc = 1 cm3

1 dm = 1 Liter

1 L = 1.06 quart

<em>so for 1 quart = 0.943 L</em>

\tt 0.943~L=0.943\times 10^{-3}m^3

Volume of oil dumped = volume of swimming pool

\tt 0.943\times 10^{-3}~m^3=25\times 30\times h(h=thick)\\\\h=\dfrac{0.943\times 10^{-3}}{750~m^2}=1.257\times 10^{-6}~m=\boxed{\bold{1.256\times 10^{-4}~cm}}

3 0
2 years ago
The molecular mass of methyl ethanoate is 74.1 amu . calculate the molecular mass of propanoic acid, an isomer of methyl ethanoa
kobusy [5.1K]
Isomers are the compounds having same molecular formula but different structural formula. 

Since, molecular formula is isomers are same, they have same mass.

Now, <span>methyl ethanoate is  an isomer of propanoic acid, hence they have same mass.

</span>∴ Molecular mass of propanoic acid = 74.1 amu or 74.1 g/mol<span>
</span>
4 0
2 years ago
Standard Thermodynamic Quantities for Selected Substances at 25 ∘C Reactant or product ΔHf∘(kJ/mol) Al(s) 0.0 MnO2(s) −520.0 Al2
Svet_ta [14]

Answer:

-1815.4 kJ/mol

Explanation:

Starting with standard enthalpies of formation you can calculate the standard enthalpy for the reaction doing this simple calculation:

∑ n *ΔH formation (products) - ∑ n *ΔH formation (reagents)

This is possible because enthalpy is state function meaning it only deppends on the initial and final state of the system (That's why is also possible to "mix" reactions with Hess Law to determine the enthalpy of a new reaction). Also the enthalpy of formation is the heat required to form the compound from pure elements, then products are just atoms of reagents organized in a different form.

In this case:

ΔH rxn = [(2 * -1675.7) - (3 * -520.0)] kJ/mol = -1815.4 kJ/mol

4 0
2 years ago
29. A certain nut crunch cereal contains 11.0 grams of sugar (sucrose, C12H22O11) per serving size of 60.0 grams. How many servi
adoni [48]

Answer:

The answer is: 51.8 g (86% of serving size)

Explanation:

In order to solve the problem, we have to first determine the number of moles there are in 11.0 g of sucrose. Sucrose has a molecular weight of 342 g (we calculate this from the molar mass of the elements : 12 x 12 g/mol C + 22 x 1 g/mol H + 11 x 16 g/mol O). So, we divide the mass (11.0 g) into the molecular weight of sucrose:

11.0 g sucrose x 1 mol/342 g sucrose= 0.032 mol

We have 0.032 mol of sucrose in a serving of 60 g. But we need less moles (0.0278 mol):

0.032 mol ------------ 60 g serving

0.0278 mol------------ x= 0.0278 mol x 60 g serving/0.032 mol

                                x= 51.8 g

So,  lesser than 1 serving of 60 g must be eaten to consume 0.0278 mol os sucrose. Exactly, 51.8 g (which stands for a 86% of the serving size).

3 0
2 years ago
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