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DENIUS [597]
2 years ago
11

In an experiment, calcium carbonate reacted with different volumes of hydrochloric acid in water. One of the products formed dur

ing the experiment was carbon dioxide. The time taken for 0.89 mL of carbon dioxide to form was recorded. A partial record of the experiment is shown. Experimental Record Flask Mass of Calcium Carbonate Volume of HCl Volume of Water Time 1 4.0 g 25 mL 0 mL 11.2 seconds 2 4.0 g 20 mL 5 mL 3 4.0 g 15 mL 10 mL 4 4.0 g 10 mL 15 mL

Chemistry
1 answer:
Arte-miy333 [17]2 years ago
5 0

Answer:

12.8seconds, 14.6seconds, 16.4seconds

Explanation:

the answers should b right as long as it is increasing in trend.

the reason why is bc of lower vol of hcl, and higher vol of water present. there is amount of hcl molecules present per volume. lesser chance of collisions, lower rate of successful collisions to poduce CO2

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The pK1, pK2, and pKR of the amino acid lysine are 2.2, 9.1, and 10.5, respectively. The pK1, pK2, and pKR of the amino acid arg
almond37 [142]

Answer:

pH 9,8 is likely to work best for this separation

Explanation:

Ion exchange chromatography is a chemical process where molecules are separated by affinity to an ion exchange resin. To separate different aminoacids you must use the isoelectric point (That is the pH where the aminoacid will be in its neutral form).

For lysine, PI is:

pH = \frac{1}{2} (9,1+10,5) = 9,8

For arginine:

pH = \frac{1}{2} (9,0+12,5) = 10,75

At pH = 9,8 lysine will be in its neutral form and will not be retain in the column but arginine will be in +1 charge being retained by the ion exchange resin.

Thus, <em>pH 9,8 is likely to work best for this separation</em>

<em></em>

I hope it helps!

5 0
2 years ago
A 5.00 L sample of helium expands to 12.0 L at which point the
mina [271]

Answer:

1.73 atm

Explanation:

Given data:

Initial volume of helium = 5.00 L

Final volume of helium = 12.0 L

Final pressure = 0.720 atm

Initial pressure = ?

Solution:

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

P₁ × 5.00 L = 0.720 atm × 12.0 L

P₁ = 8.64 atm. L/5 L

P₁ = 1.73 atm

7 0
1 year ago
Titanium metal requires a photon with a minimum energy of 6.94×10⁻¹⁹J to emit electrons. What is the wavelength of this light? E
Elena-2011 [213]

Answer:2.86x10^-7m

Explanation:E=hc/^

E=6.94x10^-19J

c = 2.9979x10^8m/s

h= 6.626x10^-34Js

^ =( 6.626x10^-34)x( 2.9979x 10^8)/ 6.94x10^-19

= 2.86x10^-7m

5 0
2 years ago
What is the density ρh of hot air inside the balloon? assume that this density is uniform throughout the balloon. express the de
enyata [817]

Answer 1) : The density of the hot air inside the balloon can be found out by using ideal gas equation;


PV = nRT;


As n is number of moles and in gases, number of moles along with mass per mole is equal to the density of the gas.


If the moles in the gas are more the density will be more.


here, density (ρ) = mass (m) / volume (V); substituting in the ideal gas equation we get,

ρ = mP / RT


Answer 2) ρ (hot air) = ρ (cold air) X \frac{T_{h}}{T_{c}}

Here according to the formula because T(hot air) >T(cold air),


So, the density of hot air greater than the density of cold air.


The relationship between the ρ (h) = ρ(c) X \frac{T_{h}}{T_{c}}

6 0
2 years ago
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Solids retain their shape and size, if kept constant temperature and pressure. At a constant temperature and pressure, liquids r
Gnoma [55]
At a constant temperature and pressure, liquids retain their volume
5 0
2 years ago
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