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zalisa [80]
2 years ago
6

Titanium metal requires a photon with a minimum energy of 6.94×10⁻¹⁹J to emit electrons. What is the wavelength of this light? E

xpress your answer using three significant figures.
Chemistry
1 answer:
Elena-2011 [213]2 years ago
5 0

Answer:2.86x10^-7m

Explanation:E=hc/^

E=6.94x10^-19J

c = 2.9979x10^8m/s

h= 6.626x10^-34Js

^ =( 6.626x10^-34)x( 2.9979x 10^8)/ 6.94x10^-19

= 2.86x10^-7m

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Directions: Select the choice that best fits each statement. The following questions(s) refer to the following elements. (A) Car
Illusion [34]

Answer:

sulfur

Explanation:

During mining, sulfur from pyrite contributes to acid-mine drainage.

3 0
1 year ago
The volume of a gas is decreased from 100 liters at 173.0°C to 50 liters at a constant pressure. After the decrease in volume, w
Minchanka [31]

Answer:

223.08 K

Explanation:

First we <u>convert 173.0 °C to K</u>:

  • 173.0 °C + 273.16 = 446.16 K

With the absolute temperature we can use <em>Charles' law</em> to solve this problem:

  • T₁V₂=T₂V₁

Where in this case:

  • T₁ = 446.16 K
  • V₂ = 50 L
  • T₂ = ?
  • V₁ = 100 L

We <u>input the data</u>:

  • 446.16 K * 50 L = T₂ * 100 L

And <u>solve for T₂</u>:

  • T₂ = 223.08 K
5 0
1 year ago
For scuba dives below 150 ft, helium is often used to replace nitrogen in the scuba tank. If 15.2 g of He(g) and 30.6 g of O2(g)
abruzzese [7]

Answer:

see explanation below

Explanation:

To do this exercise, we need to use the following expression:

P = nRT/V

This is the equation for an ideal gas. so, we have the temperature of 22 °C, R is the gas constant which is 0.082 L atm / mol K, V is the volume in this case, 5 L, and n is the moles, which we do not have, but we can calculate it.

For the case of the oxygen (AW = 16 g/mol):

n = 30.6 / 32 = 0.956 moles

For the case of helium (AW = 4 g/mol)_

n = 15.2 / 4 = 3.8 moles

Now that we have the moles, let's calculate the pressures:

P1 = 0.956 * 0.082 * 295 / 5

P1 = 4.63 atm

P2 = 3.8 * 0.082 * 295 / 5

P2 = 18.38 atm

Finally the total pressure:

Pt = 4.63 + 18.38

Pt = 23.01 atm

7 0
2 years ago
A 0.3870-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.7191Â g of co
olchik [2.2K]
The chemical formula for the compound can be written as,

    CxHyOz 

where x is the number of C atoms, y is the number of H atoms, and z is the number of O atoms. The combustion reaction for this compound is,
   
    CxHyOz + O2 --> CO2 + H2O 

number of moles of C:
     (0.7191 g)(1 mol CO2/44 g of CO2) = 0.0163 mol CO2
 This signifies that 0.0163 mole of C and the mass of carbon in the compound,
        (0.0163 mols C)(12 g C/ 1 mol C) = 0.196 g C

number of moles H:
      (0.1472 g H2O)(1 mol H2O/18 g H2O) = 0.00818 mol H2O

This signifies that there are 0.01635 atoms of H in the compound.
      mass of H in the compound = (0.01635 mols H)(1 g of H) = 0.01635 g H

Mass of oxygen in the compound,
   0.3870 - (0.196 g C + 0.01635 g H) = 0.1746 g

Moles O in the compound = (0.1746 g O)(1 mol O/16 g O) = 0.0109 mols O

The formula of the compound is,
      C0.0163H0.01635O0.0109

Dividing the numbers by the least number,
    C3/2H3/2O

The empirical formula of the compound is therefore,
    <em>  C₃H₃O₂</em>
5 0
2 years ago
**PLATO QUESTION, PLEASE ANSWER CORRECTLY**
Ivenika [448]
The corect answers will be:
1) A
2) B
3) D

Hope this helped :)
7 0
1 year ago
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