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zalisa [80]
2 years ago
6

Titanium metal requires a photon with a minimum energy of 6.94×10⁻¹⁹J to emit electrons. What is the wavelength of this light? E

xpress your answer using three significant figures.
Chemistry
1 answer:
Elena-2011 [213]2 years ago
5 0

Answer:2.86x10^-7m

Explanation:E=hc/^

E=6.94x10^-19J

c = 2.9979x10^8m/s

h= 6.626x10^-34Js

^ =( 6.626x10^-34)x( 2.9979x 10^8)/ 6.94x10^-19

= 2.86x10^-7m

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it takes 513 kj to remove a mole of electrons from the atoms at the surface of a piece of metal. how much energy does it take to
schepotkina [342]

Answer:

The right solution is "8.5\times 10^{-19} \ joule".

Explanation:

As we know,

1 mole electron = 6.023\times 10^{23} \ no. \ of \ electrons

Total energy = 513 \ KJ

                     = 513\times 1000 \ joule

For single electron,

The amount of energy will be:

= \frac{513\times 1000}{(6.023\times 10^{23})}

= 8.5\times 10^{-19} \ joule

8 0
2 years ago
Suppose that a 100 mL sample of ideal gas is held in a piston-cylinder apparatus. Its volume could be increased to 200 mL by
Ivahew [28]

Answer:

e. reducing the pressure from 608 torr to 0.40 atm at constant temperature.

Explanation:

According to Boyle's law when a gas is at the same temperature and there is a mass in a closed container so the pressure and the volume changes in the opposite direction

So here the equation is

P_1V_1=P_2V_2

Now we choose the options

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P_1 = 608\ torr = 0.8\ atm \\\\P_2= 0.4\ atm

Now applying these values to the above equation

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P1V1=P2V2

P_1V_1=P_2V_2

0.8\times0.1 = 0.4\times0.2

0.8 = 0.8

Hence, it is proved

6 0
2 years ago
Find the mass in grams of 1.40x10^23 molecules of n2
mina [271]
<span>Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We calculate as follows:

</span>1.40x10^23 molecules of N2 ( 1 mol / 6.022 x 10^23 molecules ) ( 28.02 g / mol ) = 6.51 g N2
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Answer:

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If I am correct I would believe that it would be a muscle cell.
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