All categories

2 years ago

How is the energy of the universe conserved during the combustion of gasoline in a car engine?

Chemistry

2 answers:

ExtremeBDS [4]2 years ago

8 0

The energy produced during combustion of gasoline in a car engine is converted as kinetic energy.

Explanation

The conservation of energy clearly states that "energy can neither be created nor be destroyed , it can only be transferred from one form to another form".

The combustion of gasoline in a car engine tends to generate heat energy, this heat energy will be transferred as kinetic energy which will lead to motion of cars.

This the energy of the universe will be conserved as the energy created by the combustion is used as kinetic energy for movement of cars.

Marianna [84]2 years ago

6 0

In a car driven by a gasoline combustion engine, heat energy is quickly converted into kinetic energy which results in the motion of the car.

According to the law of the conservation of energy, energy cannot be destroyed or created. It is can only be transformed from one form to another.

You might be interested in

Enter the correct answer for each unit conversion.

Luden [163]

Answer:

50 mm

4 ft

36 ft

250 cm

1 L

Explanation:

Centimeter to millimeter:

1 cm is equal to 10 mm.

5cm× 10 mm/1 cm

50 mm

Inches to feet conversion:

1 foot is equal to 12 inches.

48 inch × 1 feet /12 inch

4 feet

Yard to Feet conversion:

1 yard is equal to 3 feet.

12 yd × 3 ft / 1 yd

36 ft

Meter to centimeter:

One meter is equal to 100 cm.

2.5 m × 100 cm / 1m

250 cm

Milliliter to Liter:

One L is equal to 1000 mL.

1000 mL = 1 L

4 0

1 year ago

Read 2 more answers

The Lewis dot model of a molecule is shown. A molecule is shown with atoms arranged in the order HCCH. There are three horizonta

denis-greek [22]

Answer:

B)The octet of carbon atom remains incomplete in the molecule.

Explanation:

8 0

2 years ago

How many grams of copper (II) nitrate would be produced from 0.80 g of copper metal reacting with excess nitric acid?

zaharov [31]

Answer:

$m_{Cu(NO_3)_2}=2.36 gCu(NO_3)_2$

Explanation:

Hello!

In this case, since the chemical reaction between copper and nitric acid is:

$2HNO_3+Cu\rightarrow Cu(NO_3)_2+H_2$

By starting with 0.80 g of copper metal (molar mass = 63.54 g/mol) and considering the 1:1 mole ratio between copper and copper (II) nitrate (molar mass = 187.56 g/mol) we can compute that mass via stoichiometry as shown below:

$m_{Cu(NO_3)_2}=0.80gCu*\frac{1molCu}{63.54gCu} *\frac{1molCu(NO_3)_2}{1molCu} *\frac{187.56gCu(NO_3)_2}{1molCu(NO_3)_2} \\\\m_{Cu(NO_3)_2}=2.36 gCu(NO_3)_2$

However, the real reaction between copper and nitric acid releases nitrogen oxide, yet it does not modify the calculations since the 1:1 mole ratio is still there:

$4HNO_3+Cu\rightarrow Cu(NO_3)_2+2H_2O+2NO_2$

Best regards!

7 0

2 years ago

5. You have 100 kg of gas of the following composition: CH4 - 30% H2 - 10% N2 - 60% What is the average molecular weight of this

Lorico [155]

Answer:

21.8 g/mol

Explanation:

Molecular weight of CH4 = 16g/mol

H2 = 2g/mol

N2 = 28g/mol

(16*30 + 2*10 + 28*60)/100

=2180/100

=21.8g/mol

6 0

1 year ago

An organic acid is composed of carbon (68.84%), hydrogen (4.96%), and oxygen (26.20%). Its molar mass is 122.12 g/mol. Determine

nekit [7.7K]

Answer:

The molecular formula of the compound is $C_{7}H_{6}O_{2}$ .

Explanation:

Let consider that given percentages are mass percentages, so that mass of each element are determined by multiplying molar massof the organic acid by respective proportion. That is:

Carbon

$m_{C} = \frac{68.84}{100}\times \left(122.12\,\frac{g}{mol} \right)$

$m_{C} = 84.067\,g$

Hydrogen

$m_{H} = \frac{4.96}{100}\times \left(122.12\,\frac{g}{mol} \right)$

$m_{H} = 6.057\,g$

Oxygen

$m_{O} = \frac{26.20}{100}\times \left(122.12\,\frac{g}{mol} \right)$

$m_{O} = 31.995\,g$

Now, the number of moles ( $n$ ), measured in moles, of each element are calculated by the following expression:

$n = \frac{m}{M}$

Where:

$m$ - Mass of the element, measured in grams.

$M$ - Molar mass of the element, measured in grams per mol.

Carbon ( $m_{C} = 84.067\,g$ , $M_{C} = 12.011\,\frac{g}{mol}$ )

$n = \frac{84.067\,g}{12.011\,\frac{g}{mol} }$

$n = 7$

Hydrogen ( $m_{H} = 6.057\,g$ , $M_{H} = 1.008\,\frac{g}{mol}$ )

$n = \frac{6.057\,g}{1.008\,\frac{g}{mol} }$

$n = 6$

Oxygen ( $m_{O} = 31.995\,g$ , $M_{O} = 15.999\,\frac{g}{mol}$ )

$n = \frac{31.995\,g}{15.999\,\frac{g}{mol} }$

$n = 2$

For each mole of organic acid, there are 7 moles of carbon, 6 moles of hydrogen and 2 moles of oxygen. Hence, the molecular formula of the compound is:

$C_{7}H_{6}O_{2}$

8 0

1 year ago