answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kozerog [31]
1 year ago
8

Enter the correct answer for each unit conversion.

Chemistry
2 answers:
Luden [163]1 year ago
4 0

Answer:

50 mm

4 ft

36 ft

250 cm

1 L

Explanation:

Centimeter to  millimeter:

1 cm is equal to 10 mm.

5cm× 10 mm/1 cm

50 mm

Inches to feet conversion:

1 foot is equal to 12 inches.

48 inch ×  1 feet /12 inch

4 feet

Yard to Feet conversion:

1 yard is equal to 3 feet.

12 yd × 3 ft / 1 yd

36 ft

Meter to centimeter:

One meter is equal to 100 cm.

2.5 m × 100 cm / 1m

250 cm

Milliliter to Liter:

One L is equal to 1000 mL.

1000 mL = 1 L

Vera_Pavlovna [14]1 year ago
4 0

Answer:

50, 4, 36, 250, 1

Explanation:

You might be interested in
Consider the equilibrium reaction: 3CIO-(aq) ↔ CIO3-(aq) + 2CI-(aq) The equilibrium constant Kc = 3.2 x 103. The following conce
blagie [28]

Answer:

Forward direction

Explanation:

The reaction quotient of an equilibrium reaction measures relative amounts of the products and the reactants present during the course of the reaction at  particular point in the time.

Q < Kc , reaction will proceed in forward direction.

Q > Kc , reaction will proceed in backward direction.

Q = Kc , reaction at equilibrium.

It is the ratio of the concentration of the products and the reactants each raised to their stoichiometric coefficients. The concentration of the liquid and the gaseous species does not change and thus is not written in the expression.

Thus, for the reaction:

3CIO^{-}_{(aq)}\rightleftharpoons CIO_3^{-}_{(aq)}+2Cl^{-}

The expression is:

Q=\frac {[CIO_3^{-}][Cl^{-}]^2}{[CIO^{-}]^3}

Given,

[Cl⁻] = 0.50 mol/L; [ClO₃⁻] = 0.32 mol/L; [ClO⁻] = 0.24 mol/L

So,

Q=\frac{0.32\times (0.50)^2}{(0.24)^3}

Q = 5.7870

Since, Q < Kc (3.2\times 10^3)

The reaction will go in forward direction.

6 0
2 years ago
Calculate the mass in grams of each of the following amounts: 1.002 mol of chromium 4.08 x 10-8 mol of neon
Pepsi [2]

Answer:

Mass_{chromium}=52.1\ g

Mass_{neon}=8.23\times 10^{-7}\ g

Explanation:

<u>Calculation of the mass of chromium as:- </u>

Moles = 1.002 moles

Molar mass of chromium = 51.9961 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

1.002\ mol= \frac{Mass}{51.9961\ g/mol}

Mass_{chromium}=1.002\times 51.9961\ g = 52.1\ g

<u>Calculation of the mass of neon as:- </u>

Moles = 4.08\times 10^{-8} moles

Molar mass of neon = 20.1797 g/mol

Thus,

1.002\ mol= \frac{Mass}{20.1797\ g/mol}

Mass_{neon}=4.08\times 10^{-8}\times 20.1797\ g = 8.23\times 10^{-7}\ g

6 0
2 years ago
In a reaction, 25 grams of reactant
Vsevolod [243]

Answer:

D. 15g

Explanation:

The law of conservation of mass states that, in a chemical reaction, mass can neither be created nor destroyed. This means that the amount of matter in the elements of the reactants must be equal to the amount in the resulting products.

In this question, 25 grams of a reactant AB, was broken down in a reaction to produce 10 grams of products A and X grams of product B. According to the law of conservation of mass, the mass of the reactant must be equal to the total mass of the products. This means that 25 grams must also be the total mass of both products in this reaction. Hence, if product A is 10 grams, product B will be 25 grams - 10 grams = 15 grams.

Therefore, product B must be 15 grams in order to form a total of 25 grams when added to the mass of product A. This will equate the mass of the reactant AB and fulfill the law of conservation of mass.

8 0
2 years ago
An unknown compound is composed of 65.44% C, 29.07% O, and 5.49% H. A sample weighing 5.34 g, when dissolved in 60.00 g H2O, low
sergey [27]

Answer:

The molecular formula of the compound is C14H11O6

Explanation:

To lower the freezing point we have to apply this formula

ΔT = Kf . molality

ΔT = 0,6°C

So ΔT / Kf = molality ( moles of solute in 1kg of solvent)

0,6° / 1,86 m/°C = 0,322 moles

This moles are in 1kg of water, but I dissolved the solute in 60 g so the rule of three will be

1000 g water _____ 0,322 moles

60 g water _______ (60 . 0,322)/ 1000 = 0,01932 moles

This moles are the mass of the weigh I dissolved, 5,34 g

So let's find out the molar mass

0,01932 moles are ____ 5.34 g

1 mol is _____________ (5,34 . 1 )/ 0,01932 = 276.39 g/m

Option C is the answer

C14H11O6 = 12.14 + 11.1 + 16.6 = ≅ 276

6 0
1 year ago
Read 2 more answers
2 M n O 2 + 4 K O H + O 2 + C l 2 → 2 K M n O 4 + 2 K C l + 2 H 2 O , there are 100.0 g of each reactant available. Which reacta
Sliva [168]

Answer:

The limiting reactant is KOH.

Explanation:

To find the limiting reactant we need to calculate the number of moles of each one:

\eta = \frac{m}{M}

<u>Where</u>:

η: is the number of moles

m: is the mass

M: is the molar mass

\eta_{MnO_{2}} = \frac{100.0 g}{86.9368 g/mol} = 1.15 moles  

\eta_{KOH} = \frac{100.0 g}{56.1056 g/mol} = 1.78 moles  

\eta_{O_{2}} = \frac{100.0 g}{31.998 g/mol} = 3.13 moles  

\eta_{Cl_{2}} = \frac{100.0 g}{70.9 g/mol} = 1.41 moles  

Now, we can find the limiting reactant using the stoichiometric relation between the reactants in the reaction:

\eta_{MnO_{2}} = \frac{\eta_{MnO_{2}}}{\eta_{KOH}}*\eta_{KOH} = \frac{2}{4}*1.78 moles = 0.89 moles

We have that between MnO₂ and KOH, the limiting reactant is KOH.

\eta_{O_{2}} = \frac{\eta_{O_{2}}}{\eta_{Cl_{2}}}*\eta_{Cl_{2}} = \frac{1}{1}*1.41 moles = 1.41 moles

Similarly, we have that between O₂ and Cl₂, the limiting reactant is Cl₂.

Now, the limiting reactant between KOH and Cl₂ is:

\eta_{KOH} = \frac{\eta_{KOH}}{\eta_{Cl_{2}}}*\eta_{Cl_{2}} = \frac{4}{1}*1.41 moles = 5.64 moles

Therefore, the limiting reactant is KOH.

I hope it helps you!

6 0
1 year ago
Read 2 more answers
Other questions:
  • Which of the following pairs lists a substance that can neutralize HNO3 and the salt that would be produced from the reaction?
    8·1 answer
  • What is the empirical formula of a compound containing 5.03 grams carbon, 0.42 grams hydrogen, and 44.5 grams chlorine?
    7·1 answer
  • One of the substances that give wet goats and dirty gym socks their characteristic odors is hexanoic acid, CH3CH2CH2CH2CH2CO2H,
    13·1 answer
  • A sample consisting of 1.0 mol of perfect gas molecules with CV = 20.8 J K−1 is initially at 4.25 atm and 300 K. It undergoes re
    9·1 answer
  • When HCl(g) reacts with NH3(g) to form NH4Cl(s) , 176 kJ of energy are evolved for each mole of HCl(g) that reacts. Write a bala
    11·1 answer
  • Consider the following molecules and the description of the bonding present in each: CH3CH2CH2CH3CH3CH2CH2CH3 (C−CC−C and C−HC−H
    15·1 answer
  • Which represents the correct equilibrium constant expression for the reaction below?
    6·2 answers
  • HgS + O2 → HgO + SO2
    9·1 answer
  • How much heat in kJ is produced by the oxidation of 18.6 g of Mn?
    9·1 answer
  • - A 300g sample of CaCO3 was heated until 10 L of CO2 was collected
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!