When heat energy is supplied to a material it can raise the temperature of mass of the material.
Specific heat is the amount of energy required by 1 g of material to raise the temperature by 1 °C.
equation is
H = mcΔt
H - heat energy
m - mass of material
c - specific heat of the material
Δt - change in temperature
substituting the values in the equation
120 J = 10 g x c x 5 °C
c = 2.4 Jg⁻¹°C⁻¹
Answer:
Explanation:
The main task here is that there are some missing gaps in the above question that needs to be filled with the appropriate answers. So, we are just going to do rewrite the answer below as we indicate the missing gaps by underlining them and making them in bold format.
SO; In the quantum-mechanical model of the hydrogen atom.
As the n level increases. the energy <u>increases</u> and thus levels are <u>closer to </u>each other. Therefore, the transition <u>3p→2s</u> would have a greater energy difference than the transition from <u>4p→3p.</u>
The rate constant, k, for the decomposition reaction : k = 0.0124 / days
<h3>Further explanation</h3>
Given
The half-life of 56 days
Required
The rate constant, k
Solution
For first-order, rate law : ln[A]=−kt+ln[A]o
The half-life : the time required to reduce to half of its initial value.
The half life :
t1/2 = (ln 2) / k
k = (ln 2) / t1/2
k = 0.693 / 56 days
k = 0.0124 / days
Answer:
See explanation
Explanation:
A flammable solvent refers to a solvent that catches fire easily. The precautions to be taken when working with flammable solvents are;
1) heat the solvent at a low to medium hot plate setting.
2) if you need to boil the solvent, use a condenser rather than a flask or beaker without a cover.
3) make sure that the hotplate is larger than the vessel containing the mixture that is being heated.
4) do not use strong oxidizing agents
The answer: is yes, It is a buffer solution.
first, we need to get moles of sodium hydroxide and propanoic acid:
moles NaOH = molarity * volume
= 0.5M * 0.1 L = 0.05 moles
moles propanoic acid = molarity * volume
= 0.75 M * 0.1 L = 0.075 moles
[NaOH] at equilibrium = 0.05 m
[propanoic acid ] at equilibrium = 0.075 - 0.05 = 0.025 m
when Pka for propanoic acid (given) = 4.89
so by substitution:
∴PH = Pka + ㏒[NaOH]/[propanoic acid ]
∴ PH = 4.89 + ㏒ 0.05 / 0.025
= 5.19
