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bija089 [108]
1 year ago
7

What is molarity of 3 mole of hydrochloric acid in 3L of water

Chemistry
1 answer:
Mila [183]1 year ago
6 0

Answer:

1

Explanation:

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How many moles are in 1.50 g of ethylamine, ch3ch2nh2?
zavuch27 [327]
Mass =  mass/molar  mass  of   ch3ch2nh2
the   molar  mass  of CH3CH2NH2 =  12  +(1x3)+12+(1 x2)+14+(1x2) =45  g/mol

moles  is therefore  =  1.50g /45g/mol =   0.033 moles
6 0
2 years ago
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Determine the PH at the point in the titration of 40.0ml of 0.200M HC4H7o2 with 0.100 M Sr(OH)2 after 100ml of the strong base h
Dmitriy789 [7]

Answer:

Check the explanation

Explanation:

Mols HC4H7O2 = (volume in L)*(molarity) = (40.0 mL)*(0.200 M)

= (40.0 mL)*(1 L)/(1000 mL)*(0.200 M)

= 8.00*10-3 mol.

Mols Sr(OH)2 corresponding to 10.0 mL of 0.100 M solution =

(volume in L)*(molarity)

= (10.0 mL)*(0.100 M)

= (10.0 mL)*(1 L)/(1000 mL)*(0.100 M)

= 1.00*10-3 mol.

Consider the ionization of Sr(OH)2 as below.

Sr(OH)2 (aq) ----------> Sr2+ (aq) + 2 OH- (aq)

As per the stoichiometric equation,

1 mol Sr(OH)2 = 2 mols OH-.

Therefore,

0.0010 mol Sr(OH)2 = [0.0010 mol Sr(OH)2]*(2 mols OH-)/[1 mole Sr(OH)2]

= 0.0020 mol

= 2.00*10-3 mol

Set up the ICE charts as below.

HC4H7O2 (aq) + OH- (aq) ------------> H2O (l) + C4H7O2- (aq)

Before (mol)        8.00*10-3         2.00*10-3                           -                -

Change (mol)      -2.00*10-3       -2.00*10-3                           -        +2.00*10-3

After (mol)           6.00*10-3                0                                  -          2.00*10-3

The change in a pure substance, e.g., H2O is not considered in an acid-base reaction.

Volume of the solution = (40.0 + 10.0) mL = 50.0 mL = (50.0 mL)*(1 L)/(1000 mL) = 0.05 L.

The initial concentrations are obtained by dividing the numbers of moles by the volume, 0.05 L.

Set up the ICE charts as below.

HC4H7O2 (aq) + OH- (aq) ------------> H2O (l) + C4H7O2- (aq)

Initial (M)             0.160               0.0400                             -                -

Change (M)        -0.0400            -0.0400                            -           +0.0400

Equilibrium (M) 0.120                     0                                  -            0.0400

The acid-ionization constant is written as

Ka = [H3O+][C4H7O2-]/[HC4H7O2] = 1.5*10-5

Plug in the known values and get

Ka = [H3O+]*(0.0400)/(0.120) = 1.5*10-5

======> [H3O+] = (1.5*10-5)*(0.120)/(0.0400) (ignore units)

======> [H3O+] = 4.5*10-5

The proton concentration of the solution is 4.5*10-5 M.

pH = -log (4.5*10-5 M)

= 4.346

≈ 4.35 (ans).

8 0
1 year ago
Write the expression for the equilibrium constant Kp for the following reaction.Enclose pressures in parentheses and do NOT writ
maxonik [38]

<u>Answer:</u> The expression for K_p is written below.

<u>Explanation:</u>

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of the products and the reactants each raised to the power their stoichiometric ratios. It is expressed as K_p

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_p is written as:

K_p=\frac{P_{C}^c\times P_{D}^d}{P_{A}^a\times P_{B}^b}

The partial pressure for solids and liquids are taken as 1.

For the given chemical equation:

NH_4HS(s)\rightleftharpoons NH_3(g)+H_2S(g)

The expression for K_p for the following equation is:

K_p=\frac{(P NH_3)\times (P H_2S)}{(P NH_4HS)}

The partial pressure of NH_4HS will be 1 because it is solid.

So, the expression for K_p now becomes:

K_p=\frac{(P NH_3)\times (P H_2S)}{1}

Hence, the expression for K_p is written above.

5 0
2 years ago
Which of the following are elements, which are molecules but not compounds, which are compounds but not molecules, and which are
andreev551 [17]

Explanation:

Molecules of compounds are are compounds composed two or more than two different elements.

Molecules of an elements are made up two or more than two numbers of same type of atoms

(a) SO_2

It is compound composed of sulfur and oxygen element.

(b) S_8

It is a molecules of a single element made up of 8 sulfur atoms.

(c) Cs

It is a symbol of an element named cesium.

(d) N_2O_5

It is compound composed of nitrogen and oxygen element.

(e) O

It is a symbol of an element named oxygen.

(f) O_2

It is a molecule of a single element made up of 2 oxygen atoms.

(g) O_3

It is a molecule of a single element made up of 3 oxygen atoms.

(h)CH_4

It is compound composed of carbon and hydrogen element.

(i) KBr

It is compound composed of potassium and bromine element.

(j) S

It is a symbol of an element named sulfur.

(k) P_4

It is a molecule of a single element made up of 4 phosphorus atoms.

(l) LiF

It is compound composed of lithium and fluorine element.

4 0
1 year ago
Read 2 more answers
A bottle has a capacity of 1.2 liters. If the density of ether is 0.74 g/mL, what mass of ether can the bottle hold?
AfilCa [17]

Answer:

Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. It is a property that can be used to describe a substance. We calculate as follows:

Volume = 60.0 g ( 1 mL / 0.70 g ) = 85.71 mL

Therefore, the correct answer is option B.

Explanation:

8 0
1 year ago
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