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2 years ago

Draw the product that is expected when hexanoyl chloride is treated with Et2CuLi

Chemistry

1 answer:

PolarNik [594]2 years ago

4 0

Answer:

Product formed is octan-3-one.

Explanation:

$Et_2CuLi$ is a Gilman reagent. General formula of Gilman reagent is $R_2CuLi$ .

Where R is alkyl group or aryl group.

Gilman reagents react with the organo halides to replace halides with alkyl group or aryl group and this reaction is known as Corey–House synthesis.

When hexanoyl chloride is treated with $Et_2CuLi$ , the chloride group of the hexanoyl chloride is substituted with the ethyl group of the $Et_2CuLi$ to form octan-3-one with the removal of EtCu and LiCl.

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Picric acid has been used in the leather industry and in etching copper. However, its laboratory use has been restricted because

olchik [2.2K]

Answer:

0.3023 M

Explanation:

Let Picric acid = $H_{picric}$

So, $H_{picric}$ + $H_2}O$ ⇄ $H_3}O^+$ + $Picric^-$

The ICE table can be given as:

$H_{picric}$ + $H_2}O$ ⇄ $H_3}O^+$ + $Picric^-$

Initial: 0.52 0 0

Change: - x + x + x

Equilibrium: 0.52 - x + x + x

Given that;

acid dissociation constant ( $K_a$ ) = 0.42

$K_a = \frac{[H_3O^+][Picric^-]}{H_{picric}}$

$0.42 = \frac{[x][x]}{0.52-x}}$

$0.42 = \frac{[x]^2}{0.52-x}}$

0.42(0.52-x) = x²

0.2184 - 0.42x = x²

x² + 0.42x - 0.2184 = 0 -------------------- (quadratic equation)

Using the quadratic formula;

$\frac{-b+/-\sqrt{b^2-4ac} }{2a}$ ; ( where +/- represent ± )

= $\frac{-0.42+/-\sqrt{(0.42)^2-4(1)(-0.2184)} }{2*1}$

= $\frac{-0.42+/-\sqrt {0.1764+0.8736} }{2}$

= $\frac{-0.42+\sqrt {1.0496} }{2}$ OR $\frac{-0.42-\sqrt {1.0496} }{2}$

= $\frac{-0.42+1.0245}{2}$ OR $\frac{-0.42-1.0245}{2}$

= $\frac{0.6045}{2}$ OR $-\frac{1.4445}{2}$

= 0.30225 OR - 0.72225

So, we go by the +ve integer that says:

x = 0.30225

x = [ $H_3}O^+$ ] = [ $Picric^-$ ] = 0.3023 M

∴ the value of [H3O+] for an 0.52 M solution of picric acid = 0.3023 M (to 4 decimal places).

6 0

2 years ago

emelie is working on a science project. her task is to answer the question does rogooti a hair cream sold on tv affect the speed

joja [24]

Answer:

This question is incomplete and unclear; the complete question including the missing part is:

Emelie is working on a science project. Her task is to answer the question:

"Does Rogooti (a hair cream sold on TV) affect the speed of hair growth

(in length)". Her family is willing to volunteer for the experiment. Identify the control group (CG) and the independent and dependent variables.

ANSWER:

Independent variable: Rogooti hair cream

Dependent variable: Speed of hair growth/length

Control group: Family members that do not use the Rogooti hair cream

Explanation:

In an experiment, the independent variable is the variable that the experimenter changes or manipulates in order to bring about a measurable response. In this case, the ROGOOTI HAIR CREAM is the independent variable.

Dependent variable refers to the variable that is measured or the variable that responds to the change made to the independent variable. In this case, the dependent variable is SPEED AT WHICH HAIR GROWS (IN LENGTH).

Control group in an experiment is the group that does not receive the experimental treatment. In this case, the experimental treatment is the Rogooti hair cream, hence, the control group will be the VOLUNTEER FAMILY MEMBERS THAT DOES NOT RECEIVE THE ROGOOTI HAIR CREAM ON THEIR HAIR.

6 0

2 years ago

What volume of a 0.00945-M solution of potassium hydroxide would be required to titrate 50.00 mL of a sample of acid rain with a

andrezito [222]

Answer:

1.30mL

Explanation:

The equation for the reaction is given below:

H2SO4 + 2KOH —> K2SO4 + 2H2O

From the equation above we obtained the following:

Mole of acid (nA) = 1

Mole of base (nB) = 2

The following data were obtained from the question:

Mb = 0.00945M

Vb =?

Va = 50mL

Ma = 1.23 × 10^−4M

Using MaVa / MbVb = nA/nB, we can calculate the volume of KOH as illustrated below:

MaVa / MbVb = nA/nB

(1.23 × 10^−4 x 50)/0.00945xVb = 1/2

Cross multiply to express in linear form

1.23 × 10^−4 x 50 x 2 = 0.00945xVb

Divide both side by 0.00945

Vb = (1.23 × 10^−4 x 50 x 2) /0.00945

Vb = 1.30mL

3 0

2 years ago

Does the reaction of a main-group metal oxide in water produce an acidic solution or a basic solution? Write a balanced equation

Fynjy0 [20]

<u>Answer:</u> The main group metal produce a basic solution in water and the reaction is $MO+H_2O\rightarrow M(OH)_2$

<u>Explanation:</u>

Main group elements are the elements that are present in s-block and p-block.

The metals that are the main group elements are located in Group IA, Group II A and Group III A.

Oxides are formed when a metal or a non-metal reacts with oxygen molecule. There are two types of oxides which are formed: Acidic oxides and basic oxides.

Acidic oxides are formed by the non-metals.
Basic oxides are formed by the metals.

When a metal oxide is reacted with water, it leads to the formation of a base.

The general formula of the oxide formed by Group II-A metals is 'MO'

The chemical equation for the reaction of metal oxide of Group II-A and water follows:

$MO+H_2O\rightarrow M(OH)_2$

Hence, the main group metal produce a basic solution in water and the reaction is $MO+H_2O\rightarrow M(OH)_2$

4 0

2 years ago

Sodium fluoroacetate (NaO₂C₂H₂F) is a common poison used in New Zealand to control invasive species, such as rats. It can be pre

NISA [10]

Answer:

-219

Explanation:

1.5(339) - 1.5(485) = -219

7 0

2 years ago