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levacccp [35]
2 years ago
10

Given the following data, calculate the densities of a carbon-14 nucleus and a carbon-14 atom. Particle Mass Electron kg Proton

kg Neutron kg The diameter of the nucleus is about cm and electrons move about the nucleus at an average distance of about cm away from it. (a) Calculate the density of a carbon-14 nucleus. Density
Chemistry
1 answer:
Harman [31]2 years ago
5 0
When it goes bioom bing bong bang pew pew pew yeauae right?
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7 0
2 years ago
Oxides of nitrogen are pollutant gases which are emitted from car exhausts.
V125BC [204]
Let's look at the molar weight of the answers: 
NO is 30 g/mol 
NO2 is 46 
N2O is 44 
N2O4 is 124 

<span>We have the grams of the product, so we need the moles in order to calculate the molar weight. We us PV=nRT for this, assuming standard temperature and pressure. </span>
You were given the liters (.120L) 
Std pressure is 1 atmosphere 
You&#x27;re looking for n, the number of moles 
<span>Temp is 293.15 kelvin, thats standard </span>
And r is the gas constant in liters-atm per mol kelvin 

(.120 liters)(1atm)=n(293.15K)(.08206) 
Solving for n is .0049883835 mol 

<span>.23g divided by .0049883 mol is about 46g&#x2F;mol. You&#x27;re answer is B I think, NO2

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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4 0
2 years ago
Read 2 more answers
What is the hydronium ion concentration of a solution whose pH is 7.30
Assoli18 [71]
[ H₃O⁺] = 10 ^ - pH

[ H₃O⁺ ] = 10 ^ - 7.30

[ H₃O⁺ ] = 5.011 x 10⁻⁸ M

hope this helps!
6 0
2 years ago
A well-insulated, closed device claims to be able to compress 100 mol of propylene, acting as a SoaveRedlich-Kwong gas and with
Setler79 [48]

Explanation:

The given data is as follows.

    Moles of propylene = 100 moles,    T_{i} = 300 K

    T_{f} = 800 K,    V_{i} = 2 m^{3}

    V_{f} = 0.02 m^{3},   C_{p} of propylene = 100 J/mol

Now, we assume the following assumptions:

Since, it is a compression process therefore, work will be done on the system. And, work done will be equal to the heat energy liberating without any friction.

            W = mC_{p} \Delta T

     100 moles \times 100 J/mol K (800 - 300) K

                 = 5 \times 10^{6} J

                 = 5 MJ

Thus, we can conclude that a minimum of 5 MJ work is required without any friction.

3 0
2 years ago
If charges flow very slowly through a metal, why does it not require several hours for a light to come on when you throw a switc
Harlamova29_29 [7]
T<span>he charges themselves may not move fast, but the force upon them does. The electric field set up by the battery or generator propagates through the wires at the speed of light.

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6 0
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