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levacccp [35]
2 years ago
10

Given the following data, calculate the densities of a carbon-14 nucleus and a carbon-14 atom. Particle Mass Electron kg Proton

kg Neutron kg The diameter of the nucleus is about cm and electrons move about the nucleus at an average distance of about cm away from it. (a) Calculate the density of a carbon-14 nucleus. Density
Chemistry
1 answer:
Harman [31]2 years ago
5 0
When it goes bioom bing bong bang pew pew pew yeauae right?
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Silver is often extracted from ores such as k[ag(cn)2] and then recovered by the reaction 2k ⎡ ⎣ag(cn)2 ⎤ ⎦(aq) + zn(s) ⟶ 2ag(s)
lions [1.4K]
Take note of the whole number beside each substance in the reaction because these will be used in the stoichiometric calculations below:

Molar mass of <span>k[ag(cn)2]:199 g/mol
Molar mass of Zn(Cn)2: 117.44 g/mol
Avogadro's number: 6.022</span>×10²³ molecules/mol

a.)

35.27 g*(1 mol/199 g)*(1 mol Zn(Cn)₂/ 2 mol K[Ag(CN)₂])*(6.022×10²³ molecules/mol) = <em>5.34×10²² molecules of Zn(Cn)₂</em>

b.)

35.27 g*(1 mol/199 g)*(1 mol Zn(Cn)₂/ 2 mol K[Ag(CN)₂])*(117.44 g/mol) = <em>10.41 g of Zn(Cn)₂</em>
5 0
2 years ago
For a particular reaction, ΔH∘=67.7 kJ/molΔH∘=67.7 kJ/mol and Δ????∘=126.9 J/(mol⋅K).ΔS∘=126.9 J/(mol⋅K). Assuming these values
Pavlova-9 [17]

Answer:

T=533.49\, K

For temperatures higher than 533.49 K we will see a spontaneous reaction, and for temperatures lower than that the reaction will not be spontaneous.

Explanation:

When are chemical reactions spontaneous? To find out we need to look at the reaction's change in Gibbs Free energy:

\Delta G=\Delta H-T\Delta S

When this is greater than zero, the reaction isn't spontaneous, when it is less than zero, we have a spontaneous reaction. The reaction must then change from spontaneous to non spontaneous when \Delta G=0. If we insert that into our equation we get:

0=\Delta H-T\Delta S\\\\T=\frac{\Delta H}{\Delta S}

That is the temperature at which the reaction's spontaneity will change, plugging in our values we find:

T=533.49\, K

At that temperature we have  \Delta G=0.

Now, at a temperature greater than this one, the entropy term in our equation for the Gibbs' free energy of reaction will take over, and make  \Delta G, thus the reaction will be spontaneous.

On the other hand, if we lower the temperature, we will have a smaller entropy term, and we will have:  \Delta G>0. That is, the reaction will not be spontaneous. Therefore for temperatures higher than 533.49 K we will see a spontaneous reaction, and for temperatures lower than that the reaction will not be spontaneous.

8 0
2 years ago
Charlie is frying an egg in a pan located over a gas burner. He develops a model to determine the energy produced by the flame i
frosja888 [35]

Answer: B.)

Explanation:  Heat flows from pan to sounroundings

8 0
2 years ago
An ideal gas occupies a volume V at an absolute temperature T. If the volume is halved and the pressure kept constant, what will
Kruka [31]

Answer:

It will be halve of T

Explanation:

V1 = V

T1 = T

V2 = ½V

T2 = x

V1/T1 = V2/T2

V/T = ½V/x

Vx = ½VT

2Vx = VT

2x = T

x = ½T

6 0
2 years ago
When HCl(g) reacts with NH3(g) to form NH4Cl(s) , 176 kJ of energy are evolved for each mole of HCl(g) that reacts. Write a bala
Orlov [11]

Answer:

q = -176kJ

Explanation:

HCl and NH3 reacts as following to NH4Cl

HCl(g) + NH3(g)=========>NH4Cl(s)   : ΔH = -176 KJ

Clearly,

ENERGY IS EVOLVED MEANING IT IS A EXOTHERMIC REACTION .

therefore, the value of heat evolved as q = -176kJ

8 0
1 year ago
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