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2 years ago

In which Colorado Rockies scenario was there more erosion? Why was there more erosion in the scenario?

2 answers:

7 0

There was more erosion in the Colorado Rockies scenario where there was steady rain compared to the scenario in the same area where there was only a drizzle. There is more erosion because the steady rain increased the volume of the river more than the drizzle did. Because there was more water added to the river, the river flowed faster. The faster a river flows, the more sediments it transports or erodes.

DENIUS [597]2 years ago

4 0

Answer:

Explanation:

The Erosion in the Colorado Rookies Scenario that record a ready rain were more than the other scenario in the same area with just a drizzle. The Erosion is much in the Colorado Rockies Scenario that record a steady rain because the volume of the rivers has goes up compare to that of the Scenario with just a drizzle. As a result of the increased in the amount of the rivers bank that is flowing, the river flows more faster which helps in the transportation of the sediments or Erodes.

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How many grams of C5H12 must be burned to heat 1.39 kg of water from 21.2 °C to 97.0 °C? Assume that all the heat released durin

faust18 [17]

Answer:

m = 8.9856 g

Explanation:

In order to do this, we need to write the expressions that are to be used. First, to calculate heat:

Q = m*C*ΔT (1)

Where C would be heat capacity of the substance.

The heat can also be relationed with the moles and enthalpy of a compound using the following expression:

Q = n*ΔH (2)

Finally for the mass of any compound, we use the following expression:

m = n*MM (3)

So, in order to calculate the grams of pentane (C5H12), we need to calculate the moles of the compound, and to do that, we need the heat exerted.

So, as we are using water, let's calculate the heat that is been exerted with the water. The C of the water is 4.186 J/g °C so:

Q = (1.39 * 1000) * 4.186 * (21.2 - 97)

Q = -441,045.33 J

This is the heat neccesary to burn pentane and heat water. Now, with this value, let's calculate the moles used of pentane with expression (2). The ΔH of the pentane is -3,535 045.kJ/mol or -3.535x10⁶ J/mol. Solving for n we have:

n = -441,045.3 / -3.535x10⁶

n = 0.1248 moles

Finally, we can calculate the grams needed with expression (3). The molar mass of pentane is 72 g/mol

m = 0.1248 * 72

m = 8.9856 g

This is the mass needed to heat 1.39 kg of water

6 0

2 years ago

How do I Unscramble this?<br><br> reusirtneadn rahi<br><br> _ _ _ _ _ _ _ _ _ _ _ _ hair

vladimir2022 [97]

The answer is unrestrained hair.

Have a nice day!

3 0

2 years ago

Read 2 more answers

How many moles of tungsten (W,183.85 g/mol) are in 415 grams of tungsten?

ozzi

2.25739773716275. I used a calculator during class today to get this answer, and I am pretty sure it is right, hope it helps.

8 0

2 years ago

Read 2 more answers

In the reaction of nitrogen gas with oxygen gas to produce nitrogen oxide, what is the effect of adding more oxygen gas to the i

Alborosie

<h3>Answer:</h3>

The Equilibrium would shift to produce more NO

<h3>Explanation:</h3>

The reaction is;

N₂(g) + O₂(g) ⇆ 2NO(g)

When a reaction is at equilibrium then the forward reaction rate will be equivalent to the reverse reaction rate. Additionally, the concentration of the reactants and products are the same.
From Le Chatelier's principle, additional reactants favor the formation of more products while additional products favor the formation of more reactants.
For example, when more oxygen is added then more Nitrogen (II) oxide will be formed.
Oxygen is a reactant and when increased it favors forward reaction which leads to the formation of more NO which is the product.

3 0

2 years ago

The concentration of C29H60 in summer rainwater is 34 ppb. Find the molarity of this compound in nanomoles per liter (nM).

Naya [18.7K]

Answer: The concentration of C29H60 in nM per liter is 83,33 nM/liter

Explanation: Let's start from the ppb definition: ppb means parts per billion. In terms of concentracion measuring this means micrograms of solute per liter of solution.

The algebraic expression would be:

<em>ppb [=] micrograms of compound/liter of solution</em>

We can assume that the solvent is water. The solute is dissolved in water and both create the C29H60 solution.

For the exercise we have 34 ppb of C29H60, that means 34 micrograms of C29H60 in one liter of solution. So, since now, we have to convert the units from the initial data to the required answer.

The respective procedure is in a attached file.

5 0

1 year ago