Answer would be B. I provided work on an image attached. Message me if u have any other questions on how to do it
Click the "draw structure" button to launch the drawing utility. Propane (CH3CH2CH3) has both 1° and 2° hydrogens. Draw the carb
on radical formed by homolysis of a 1° C―H bond in propane. draw structure ... Draw the carbon radical formed by homolysis of a 2° C―H bond in propane.
1 answer:
Answer:
a) find attached image 1
b) find attached image 2
Explanation :
The more stable radical is formed by a reaction with smaller bond dissociation energy.
since the bond dissociation for cleavage of the bond to form primary free radical is higher, more energy must be added to form it. This makes primary free radical higher in energy and therefore less stable than secondary free radical.
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