answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mash [69]
2 years ago
9

Imagine if during the cathode ray experiment, the size of the particles of the ray was the same as the size of the atom forming

the cathode. Which other model or scientific observation would have also been supported?
This would support Dalton's postulates that proposed the atoms are indivisible because no small particles are involved.
This would support Bohr's prediction about electrons moving in orbits having specific energy.
This would support Bohr's prediction about electrons being randomly scattered around the nucleus in the atom.
This would support Dalton's postulates that proposed that atoms combine in fixed whole number ratios to form compounds.
Chemistry
2 answers:
Yakvenalex [24]2 years ago
7 0

Answer:

This would support Dalton's postulates that proposed the atoms are indivisible because no small particles are involved.

Explanation:

Experiment using the gas discharge tube by J.J Thomson led to the discovery of cathode rays which are now known as electrons.

Primarily, Thomson's experiment led to the discovery of cathode rays, electrons, as subatomic particles.

If the size of the atoms observed at the cathode is the same as that of the rays,we can conclude that the particles of the rays are the simplest form of matter we can have. This would suggest that the atom is indeed the smallest indivisible particle of a matter according to Dalton.

torisob [31]2 years ago
4 0

Answer:

This would support Dalton's postulates that proposed the atoms are indivisible because no small particles are involved.

Explanation:

Dalton proposed that all matter is made up of atoms. Atoms are indivisible. But Thompson’s cathode ray experiment proved that the cathode rays are made up of negatively charged particles which were deflected by both electric and magnetic field. This caused Thompson to propose the Plum and Pudding model of the atom.

You might be interested in
What type of chemical reaction is this? Cl2(g) + 2KBr(aq) - 2KCl(aq) + Br2(l)
Sindrei [870]
C. Single-replacement

Chlorine replaces Bromine in KBr.
7 0
2 years ago
Sulfur is composed of three isotopes: 32S, 33S, and 34S. The atomic masses of these isotopes are given below. 32S: 31.97207 amu
elena-14-01-66 [18.8K]

Answer:

Abundance of 32S is 94.41%

Explanation:

The average atomic mass is defined as the sum of the atomic masses of each isotope times its abundance:

Average atomic mass = ∑ Atomic mass istope*Abundance

For the sulfur:

32.07amu = 31.97207X + 32.97146Y + 33.96786*0.0422 <em>(1)</em>

<em>Where X is abundance of 32S and Y abundance of 33S</em>

Also we can write:

1 = X + Y + 0.0422 <em>(2)</em>

0.9578 - X = Y

Because the sum of the abundances = 1

Replacing (2) in (1):

32.07amu = 31.97207X + 32.97146(0.9578 - X) + 33.96786*0.0422

32.07 = 31.97207X + 31.58006 - 32.97146X + 1.43344

-0.9435 = -0.99939X

0.9441  =X

In percentage, abundance of 32S is 94.41%

3 0
1 year ago
In the reaction N2 + 3H2 ⇌ 2NH3, an experiment finds equilibrium concentrations of [N2] = 0.1 M, [H2] = 0.05 M, and [NH3] = 0.00
jasenka [17]
  The   equilibrium  constant  Kc   for  this  reaction    is  calculated  as  follows

from  the  equation   N2  + 3H2 =2 NH3

   qc =   (NH3)2/{(N2)(H2)^3}


Qc   is  therefore  = ( 0.001)2  /{(0.1) (0.05)^3}  = 0.08
3 0
1 year ago
Read 2 more answers
Heating 235 g of water from 22.6°C to 94.4°C in a microwave oven requires 7.06 × 104 J of energy. If the microwave frequency is
Darya [45]

Answer: 3.69 × 10^27

Explanation:

Amount of energy required = 7.06 × 10^4 J

Frequency of microwave (f) = 2.88 × 10^10 s−1

Planck's constant (h) = 6.63 × 10^-34 Jᐧs/quantum

Recall ;

Energy of photon = hf

Therefore, energy of photon :

(6.63 × 10^-34)j.s× (2.88 × 10^10)s^-1

= 19.0944 × 10^(-34 + 10) = 19.0944×10^-24 J

Hence, number of quanta required :

(7.06 × 10^4)J / (19.0944 × 10^-24)J

= 0.369 × 10^(4 + 24) = 0.369×10^28

= 3.69 × 10^27

6 0
2 years ago
What is the stoichiometric ratio between BaCl2 and NaCl
bixtya [17]
<span>BaCl2+Na2SO4---->BaSO4+2NaCl There is 1.0g of BaCl2 and 1.0g of Na2SO4, which is the limiting reagent? "First convert grams into moles" 1.0g BaCl2 * (1 mol BaCl2 / 208.2g BaCl2) = 4.8 x 10^-3 mol BaCl2 1.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 7.0 x 10^-3 mol Na2SO4 (7.0 x 10^-3 mol Na2SO4 / 4.8 x 10^-3 mol BaCl2 ) = 1.5 mol Na2SO4 / mol BaCl2 "From this ratio compare it to the equation, BaCl2+Na2SO4---->BaSO4+2NaCl" The equation shows that for every mol of BaCl2 requires 1 mol of Na2SO4. But we found that there is 1.5 mol of Na2SO4 per mol of BaCl2. Therefore, BaCl2 is the limiting reagent.</span>
7 0
2 years ago
Other questions:
  • A gas sample occupies 3.50 liters of volume at 20.°c. what volume will this gas occupy at 100.°c (reported to three significant
    14·2 answers
  • The observations and results of Thomson’s cathode ray experiment led to what change to the atomic model?
    7·2 answers
  • Given the reaction: HSO4– + HPO42– ↔ SO42– + H2PO4-Which pair represents an acid and its conjugate base?
    6·1 answer
  • The model of the atom where the central core contains protons and neutrons surrounded by a cloud of electrons is best described
    8·2 answers
  • Select the statement(s) that explain(s) the relationship between the arrangement of elements by size and first ionization energy
    11·2 answers
  • Three measurements of 34.5m, 38.4m, and 35.3m are taken. If the accepted value of the measurement is 36.7m, what is the percent
    14·1 answer
  • Why did you blank with the 0.0020 M Fe(NO3)3 solution as opposed to just DI water? What does it do to your spectrum? What chemic
    14·1 answer
  • 3. You measure a cube and determine that its sides are 0.65m. You place the cube on a mass scale and determine that this cube ha
    5·1 answer
  • (14.1.50) 0.03 mol of helium are enclosed in a cylinder with a piston which maintains a constant pressure in the helium. Initial
    8·1 answer
  • I am giving brainiest! All I need are the last two questions at the bottom the rest of this info is to help solve them. I hope I
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!