<span>0.127 moles
The formula for nitroglycerin is C3H5N3O9 so let's first calculate the molar mass of it.
Carbon = 12.0107
Nitrogen = 14.0067
Hydrogen = 1.00794
Oxygen = 15.999
C3H5N3O9 = 3 * 12.0107 + 5 * 1.00794 + 3 * 14.0067 + 9 * 15.999 = 227.0829
Now calculate the number of moles of nitroglycerin you have by dividing the mass by the molar mass
2.50 ml * 1.592 g/ml / 227.0829 g/mol = 0.017527 mol
The balanced formula for when nitroglycerin explodes is
4 C3H5N3O9 => 12 CO2 + 10 H2O + O2 + 6 N2
Since all of the products are gasses at the time of the explosion, there is a total of 29 moles of gas produced for every 4 moles of nitroglycerin
Now multiply the number of moles of nitroglycerin by 29/4
0.017527 mol * 29/4 = 0.12707075 moles
Round to 3 significant figures, giving 0.127 moles</span>
The reaction between boron sulfide and carbon is given as:
2B2S3 + 3C → 4B + 3CS2
As per the law of conservation of mass, for any chemical reaction the total mass of reactants must be equal to the total mass of the products.
Given data:
Mass of C = 2.1 * 10^ 4 g
Mass of B = 3.11*10^4 g
Mass of CS2 = 1.47*10^5
Mass of B2S3 = ?
Now based on the law of conservation of mass:
Mass of B2S3 + mass C = mass of B + mass of CS2
Mass of B2S3 + 2.1 * 10^ 4 = 3.11*10^4 + 1.47*10^5
Mass of B2S3 = 15.7 * 10^4 g
Answer:
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a computer that shows pictures of atoms on screen
candy with letters on one side
Explanation:
<h3>Answer:</h3>
3.7 Moles of Nitrogen
<h3>
Explanation:</h3>
On observing the chemical formula C₈H₁₁NO₂ (might be formula of Dopamine) it is found that one mole of this compound contains;
8 Moles of Carbon
11 Moles of hydrogen
1 Mole of Nitrogen and
2 Moles of Oxygen respectively.
<u>Calculate Number of Moles of Nitrogen:</u>
As,
1 Mole of C₈H₁₁NO₂ contains = 1 Mole of Nitrogen
So,
3.7 Moles of C₈H₁₁NO₂ will contain = X Moles of Nitrogen
Solving for X,
X = (3.7 Moles × 1 Mole) ÷ 1 Mole
X = 3.7 Moles of Nitrogen
of octane had been converted to carbon dioxide CO₂.
<h3>Explanation</h3>
Octane has a molar mass of

1.000 gallon of this fuel would have a mass of 2.650 kilograms or
, which corresponds to
of octane.
Octane undergoes complete combustion to produce carbon dioxide and water by the following equation:

An incomplete combustion of octane that gives rise to carbon monoxide and water but no carbon dioxide would consume not as much oxygen:

The mass of the product mixture is
heavier than that of the octane supplied. Thus
of oxygen were consumed in the combustion. There are
of oxygen molecules in
of oxygen.
Let the number of moles of octane that had undergone complete combustion as seen in the first equation be
(
). The number of moles of octane that had undergone incomplete combustion through the second equation would thus equal
.
25 moles of oxygen gas is consumed for every two moles of octane that had undergone complete combustion and 17 moles if the combustion is incomplete.


Therefore
out of the 23.2 moles of octane had undergone complete combustion to produce carbon dioxide.
