<h2>The answers are
and
</h2>
Explanation:
Given -
a) The molecular formula of ethylene glycol -
∴ The empirical formula of ethylene glycol will be -
Given -
b) The molecular formula of per-oxo-disulfuric acid (a compound used in bleaching agents) -
∴ The empirical formula of per-oxo-disulfuric acid will be -
Hence, the answers are and .
Answer:
activity coefficient 
activity coefficient 
The change in pH in part A = 0.092
The change in pH in part B = 0.102
Explanation:
From the given information:
pH of HCl solution = 1.092
Activity of the pH solution [a] = 
[a] = 0.0809 M
Recall that [a] = 
× C
where;
= activity coefficient
C = concentration
Making the activity coefficient the subject of the formula, we have:
![\gamma = \dfrac{[a]}{C}](https://tex.z-dn.net/?f=%5Cgamma%20%3D%20%5Cdfrac%7B%5Ba%5D%7D%7BC%7D)
B.
The pH of a solution of HCl and KCl = 2.102
[a] = 
[a] = 0.00791 M
activity coefficient 
C. The change in pH in part A = 1.091 - 1.0 = 0.092
The change in pH in part B = 2.102 -2.00 = 0.102
Answer:
13,2 %.
Explanation:
Overall yield = 0.55 * 0.24
= 0.132
= 13,2 %.
Answer:
The number of moles of potassium hydroxide, KOH required to make 4 moles of K₂SO₄ is 8 moles of KOH
Explanation:
2KOH + H₂SO₄ → K₂SO₄ + 2H₂O
From the above reaction, we have 2 moles of KOH combining with 1 mole of H₂SO₄ to produce 1 mole of K₂SO₄ and 2 moles of H₂O.
Therefore the number of moles of potassium hydroxide that will be needed to make 4 moles of K₂SO₄ is;
8KOH + 4H₂SO₄ → 4K₂SO₄ + 8H₂O
8 moles of KOH is required to make 4 moles of K₂SO₄.
This method of quantitative determination of percent purity is titrimetric reactions. These reactions most commonly involve neutralization reactions between an acid and a base. Then, we look at the neutralization reaction:
H₂C₂O₄ + 2 NaOH ⇒ Na₂C₂O₄ + 2 H₂O
So, we do the stoichiometric calculations. The important data we should know is the molar mass of oxalic acid which is equal to 90 g/mol.
(0.2283 mol/L NaOH * 0.3798 L * 1 mol H₂C₂O₄/ 2mol NaOH * 90 g/mol H₂C₂O₄) ÷ 0.7984 g *100%
= 488%
This is impossible. The purity can't be more than 100%. Looking at our calculations and the balance reaction, all steps were done correctly. So, I think there is some typographical error in the given. The mass of the sample should be 7.984 g. Then, the answer would be 48.87% purity.
