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Nat2105 [25]
1 year ago
12

Substances with high lattice energies tend to be less soluble than substances with low lattice energies. On that basis predict t

he relative aqueous solubility at 20 °C, from highest to lowest, of the following ionic compounds: Ce2(SO4)3, K2SO4, KBr, NaCl.
Chemistry
1 answer:
goldenfox [79]1 year ago
8 0

Answer:

KBr > NaCl  > K_{2}SO_{4} > Ce_{2}(SO_{4})_{3}  

Explanation:

Generally, the higher the lattice energy of the substance, the lower the solubility of the substance. The lattice energy of KBr is the lowest, follow by that NaCl and that of K_{2}SO_{4} while that of  K_{2}SO_{4} is the highest. Based on the relationship between the lattice energy and solubility, the solubility of the substances ranging from the highest to lowest is KBr > NaCl  > K_{2}SO_{4} > Ce_{2}(SO_{4})_{3}.

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