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shepuryov [24]
2 years ago
8

What was the original volume of a gas if heating it from 22k to 85k produced a volume of 3.8 liters?

Chemistry
1 answer:
mel-nik [20]2 years ago
3 0

Answer: the original volume was 0.98L

Explanation:

V1 =?

T1 = 22k

V2 = 3.8L

T2 = 85k

V1 /T1 = V2 /T2

VI/22 = 3.8/85

V1 = 22 x (3.8/85)

V1 = 0.98L

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For this exercise, you can simulate the described conditions by changing the values in the run experiment tool of the simulation
Furkat [3]
1) ideal gas law: p·V = n·R·T.
p - pressure of gas.
V -volume of gas.
n - amount of substance.
R - universal gas constant.
T - temperature of gas.
n₁ = 0,04 mol, V₁ = 0,06 l.
n₂ = 0,07 mol, V₂ = 0,06 · 0,07 ÷ 0,04 = 0,105 l.
2) V₁ = 0,06 l, T₁ = 240,00 K.
T₂ = 340,00 K, V₂ = 340 · 0,06 ÷ 240 = 0,05 l.
3 0
2 years ago
Read 2 more answers
A boy with pneumonia has lungs with a volume of 1.9 L that fill with 0.080 mol of air when he inhales. When he exhales, his lung
mariarad [96]

<u>Answer:</u> The number of moles of gas remaining in the lungs is 0.063 moles

<u>Explanation:</u>

The relationship of number of moles and volume at constant temperature and pressure was given by Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.

The equation used to calculate number of moles is given by:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1\text{ and }n_1 are the initial volume and number of moles

V_2\text{ and }n_2 are the final volume and number of moles

We are given:

V-1=1.9L\\n_1=0.080mol\\V_2=1.5L\\n_2=?

Putting values in above equation, we get:

\frac{1.9}{0.080}=\frac{1.5}{n_2}\\\\n_2=\frac{1.5\times 0.080}{1.9}=0.063

Hence, the number of moles of gas remaining in the lungs is 0.063 moles

8 0
2 years ago
Quartz,SiO2,contains 46.7% silicon. What mass of silicon is present in 381 g of quartz?
swat32

Answer:

119 g.

Explanation:

4 0
2 years ago
For which of the following properties does sodium have a larger value than rubidium? Select all that apply.
Doss [256]

Answer:

Ionization energy

Electronegativity

Explanation:

-due to its smaller ionic radius....the electron in the outter most shell tends to expierence a stronger nuclear attraction...which makes it harder to remove the electron from the sodium atom

-Rubidium has lesser ionization energy because its (i) affected by its larger ionic radius which tends to lessen the nuclear attraction ...hence making it easier to remove the electron...(ii)and also by the screening effect done by the inner shells, which also tends to lessen the nuclear attraction.

Sodium has a higher electronegativity than rubidium;

Electronegativity is the charge density of electrons in an atom...in which its high when the atomic radius is smaller...

So hence due to the sodium atomic radius being smaller...it tends to have a higher charge density than rubidium....which then gives it a higher electronegativity value

4 0
2 years ago
The refractive index, n of a polymer was determined as a function of temperature. The results are given in the table. Determine
mylen [45]

Answer:

Explanation:

The given data shows linear trend between refractive index and temperature .

From 20 degree to 80 degree , every increase of 10 degree decreases refractive index by .0015 . This trend breaks at 90 degree beyond which , refractive index falls at greater rate or sharply.

So transition temperature is 90 degree .

4 0
2 years ago
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