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aksik [14]
1 year ago
7

The observations and results of Thomson’s cathode ray experiment led to what change to the atomic model?

Chemistry
2 answers:
olchik [2.2K]1 year ago
4 0

"the addition of negatively charged electrons" is the answer.

Vesnalui [34]1 year ago
3 0
<span>In short, Thompson's cathode ray experiment led to the identification of electrons in an atom. The experiment showed that all atoms have subatomic particles with a negative charge. This allowed Thompson to develop the rough model of the atom that we are familiar with today.</span>
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A metal oxide with the formula mo contains 15.44% oxygen. in the box below, type the symbol for the element represented by m.
lana66690 [7]

<u>Answer:</u> The element represented by M is Strontium.

<u>Explanation:</u>

Let us consider the molar mass of metal be 'x'.

The molar mass of MO will be = Molar mass of oxygen + Molar mass of metal = (16 + x)g/mol

It is given in the question that 15.44% of oxygen is present in metal oxide. So, the equation becomes:

\frac{15.44}{100}\times (x+16)=16g/mol\\\\(x+16)=\frac{16g/mol\times 100}{15.44}\\\\x=(103.626-16)g/mol\\\\x=87.62g/mol

The metal atom having molar mass as 87.62/mol is Strontium.

Hence, the element represented by M is Strontium.

8 0
1 year ago
Read 2 more answers
Sixty-five percent of the mass of bone is a compound called hydroxyapatite. sixty-five percent of the mass of bone is a compound
mafiozo [28]
True. Its simple how i remeberd was the bone has 650,000 cells and the bone has 65% hydroxyapatite
5 0
1 year ago
In the PhET simulation, make sure that the checkbox Stable/Unstable in the bottom right is checked. Using the PhET simulation as
lord [1]

Answer:

kindly check the EXPLANATION SECTION

Explanation:

In order to be able to answer this question one has to consider the neutron proton ratio. Considering this ratio will allow us to determine the stability of a nuclei. The most important rule that helps us in determination of stability is that when the Neutron- Proton ratio  of any nuclei ranges from  to 1 to 1.5, then we say the nuclei is STABLE.

Also, we need to understand that when the  Neutron- Proton ratio is LESS THAN 1 or GREATER THYAN 1.5, then we say the nuclei is UNSTABLE.

So, let us check which is stable and which is unstable:

a. 4 protons and 5 neutrons =  Neutron- proton ratio = N/P = 5/4= stable.

b. 7 protons and 7 neutrons  =  Neutron- proton ratio = N/P = 7/7= 1 = stable.

c. 2 protons and 3 neutrons  =  Neutron- proton ratio = N/P = 3/5 =0.6 =unstable.

d. 3 protons and 0 neutrons  =  Neutron- proton ratio = N/P = 0/3= 0= unstable.

e. 6 protons and 5 neutrons  =  Neutron- proton ratio = N/P = 5/6= 0.83 = unstable.

f. 9 protons and 9 neutrons  =  Neutron- proton ratio = N/P = 9/9 = 1 = stable.

g. 8 protons and 7 neutrons  =  Neutron- proton ratio = N/P =  7/8 =0.875 = unstable.

h. 1 proton and 0 neutrons =  Neutron- proton ratio = N/P = 0/1 =0 = unstable

6 0
2 years ago
Draw the structure of a compound with molecular formula c5h12 that exhibits only one kind of proton (all 12 protons are chemical
Sophie [7]
The middle carbon is 4-degree since it is attached to 4 carbons. All other carbons are 1-degree since they are attached to only 1 carbon. 

Hydrogens attached with 1-degree carbon are all same. Hydrogen are often refereed to as protons. No carbon is attached to 4-degree carbon. So all hydrogens in this structure are same.

This structure is called  NeoPentane

4 0
2 years ago
Diana raises a 1000. N piano a distance of 5.00 m using a set of pulleys. She pulls
Alina [70]

Answer:

a) 250 N

b) 50 N

c) 5000 J

d) 4

e) 3.33

Explanation:

Given that weight of piano (F_r) = 1000 N, distance moved by pulley (d_r) = 5 m and the rope used (d_e) =20 m

a) The effort applied (F_e) if it was an ideal machine is:

F_e=\frac{F_rd_r}{d_e} = \frac{1000*5}{20}=250N

b) If the actual effort  = 300 N

The force to overcome friction = actual effort - F_e = 300 - 250 = 50 N

c) Work output = F_rd_r=1000*5=5000J

d) ideal mechanical  advantage (IMA) = \frac{d_e}{d_r} =\frac{20}{5} = 4

e) Input force = 300 N, Therefore:

actual mechanical advantage = F_r / input force = 1000 / 300 = 3.33

5 0
2 years ago
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