Answer:
In 1000 ml there is 0.10 moles of Fe 2+
Therefore, in 10 ml there is (0.1/1000)*10= 0.001 mol of Fe2+
mole ratio for rxn Fe2+ : MnO4- is
1 : 2
therefore if 0.001 moles of Fe2+ react then 0.001*2 =0.002 moles of MnO4- react with Fe2+
hence, molarity of MnO4- = (mol*vol)/1000
= 0.002*10.75/1000= 2.15*10-5M
Explanation:
Hope this helps
Answer:
C
Explanation:
Looking at the periodic table, we can see that sodium is in group 1, so a sodium ion would be Na⁺, with a charge of +1. Oxygen is in group 16, so an oxygen ion would be O²⁻, with a charge of -2.
A compound formed only by a single sodium ion and a single oxygen ion would thus have a charge of -1, and in order to have a stable ionic compound its charge must be zero.
Answer:
premium: 91 octane rating
Explanation:
Octane number refers to the percentage or volume fraction of isooctane in a fuel.
The octane number gives a picture of how safe a fuel is for an engine. The higher the octane rating the lesser the tendency of the fuel to cause knocking of the engine.
The type of gasoline with the highest percentage of octane among the options is premium.
Sorenson
Explanation:
The values used in the scale of pH and pOH are derived from a system designed by Sorenson. Søren Peter Lauritz Sørensen, a Danish chemist introduced the system of pH and pOH for describing the alkalinity and acidity of substances.
- The pH and pOH scale is logarithmic scale that ranks the acidity and bascity of compounds.
- pH is the negative logarithm of the concentration of hydrogen/hydroxonium ions in solution i.e
pH = -log₁₀{H⁺]
- pOH is the negative log of the concentration of the hydroxyl ions in a solution i.e
pOH = -log₁₀{OH⁻]
Learn more:
calculating pH: brainly.com/question/12985875
pH scale: brainly.com/question/11063271
#learnwithBrainly
Answer:
1.72 L
Explanation:
Initial Temperature of the gas T =90°+273= 363 K
Initial Volume of the gas V1= 1.41 L
Final temperature of the gas T2= 170°c +273= 443 K
Final volume of the gas V2= ????
Using Charles law;
V1/T1 = V2/T2
V1T2= V2T1
V2= V1T2/T1
V2= 1.41×443/363
V2= 1.72 L
