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Cerrena [4.2K]
1 year ago
14

Sulfur is composed of three isotopes: 32S, 33S, and 34S. The atomic masses of these isotopes are given below. 32S: 31.97207 amu

33S: 32.97146 amu 34S: 33.96786 amu The abundance of 34S is 4.22%. Given the average atomic mass of sulfur (32.07 amu), determine the abundance of 32S to two decimal places.
Chemistry
1 answer:
elena-14-01-66 [18.8K]1 year ago
3 0

Answer:

Abundance of 32S is 94.41%

Explanation:

The average atomic mass is defined as the sum of the atomic masses of each isotope times its abundance:

Average atomic mass = ∑ Atomic mass istope*Abundance

For the sulfur:

32.07amu = 31.97207X + 32.97146Y + 33.96786*0.0422 <em>(1)</em>

<em>Where X is abundance of 32S and Y abundance of 33S</em>

Also we can write:

1 = X + Y + 0.0422 <em>(2)</em>

0.9578 - X = Y

Because the sum of the abundances = 1

Replacing (2) in (1):

32.07amu = 31.97207X + 32.97146(0.9578 - X) + 33.96786*0.0422

32.07 = 31.97207X + 31.58006 - 32.97146X + 1.43344

-0.9435 = -0.99939X

0.9441  =X

In percentage, abundance of 32S is 94.41%

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Answer:

mass percent of carbon       = 57.78 %

mass percent of hydrogen   = 6.40 %

mass percent of nitrogen    = 8.96 %

mass percent of oxygen    = 20.49 %

mass percent of sulfur     =  10.24 %

Explanation:

Given data

Molecular formula = C₁₄H₂₀N₂O₄S

molecular mass (total mass) = 312.39 g/mol

Percentage of carbon = ?

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Percentage of nitrogen = ?

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Solution

1st we find out number of moles of each element from the molecular formula

  Number of moles of carbon  = 14 mol

  Number of moles of hydrogen   = 20 mol

  Number of moles of nitrogen   = 2 mol

  Number of moles of oxygen  = 4 mol

  Number of moles of sulfur   = 1 mol

Now we find out the mass of each element

as we know that

     <em>mass = number of moles × molecular mass</em>

 mass of carbon  = 14 mol × 12 g/mol

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 mass of hydrogen   = 20 mol × 1 g/mol

 mass of hydrogen   = 20 g

 mass of nitrogen   = 2 mol × 14 g/mol

 mass of nitrogen   = 28 g

 mass of oxygen  = 4 mol × 16 g/mol

 mass of oxygen  = 64 g

 mass of sulfur   = 1 mol × 32 g/mol

 mass of sulfur   =  32 g

now we find out the mass percent of each element

<em>         mass percent = ( mass ÷ total mass ) × 100</em>

 mass percent of carbon  = ( 168 g ÷ 312.39 g/mol ) × 100

 mass percent of carbon  = 57.78 %

 mass percent of hydrogen   = ( 20 g ÷ 312.39 g/mol ) × 100

 mass percent of hydrogen   = 6.40 %

 mass percent of nitrogen   = ( 28 g ÷ 312.39 g/mol ) × 100

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 mass of oxygen  =( 64 g ÷ 312.39 g/mol ) × 100

 mass percent of oxygen  = 20.49 %

 mass percent of sulfur   = ( 32 g ÷ 312.39 g/mol ) × 100

 mass percent of sulfur   =  10.24 %

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