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topjm [15]
2 years ago
12

In the reaction N2 + 3H2 ⇌ 2NH3, an experiment finds equilibrium concentrations of [N2] = 0.1 M, [H2] = 0.05 M, and [NH3] = 0.00

1 M. What is the equilibrium constant Kc for this reaction?
a. 0.08
b. 0.20
c. 5.0
d. 12.5
Chemistry
2 answers:
Margarita [4]2 years ago
4 0

Answer: K_c = 0.08

Explanation: The given balanced equation is:

N2+3H_2\rightleftharpoons 2NH_3

equilibrium expression is written as:

K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}

Equilibrium concentrations are given for products and reactants. Let's plug in the values.

K_c=\frac{(0.001)^2}{(0.1)(0.05)^3}

K_c = 0.08

So, the correct choice is A) 0.08.

jasenka [17]2 years ago
3 0
  The   equilibrium  constant  Kc   for  this  reaction    is  calculated  as  follows

from  the  equation   N2  + 3H2 =2 NH3

   qc =   (NH3)2/{(N2)(H2)^3}


Qc   is  therefore  = ( 0.001)2  /{(0.1) (0.05)^3}  = 0.08
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